http://www.einstein-online.info/spotlights/doppler
Albert Einstein Institute: "The frequency of a wave-like signal - such as sound or light - depends on the movement of the sender and of the receiver. This is known as the Doppler effect. (...) In the above paragraphs, we have only considered moving sources. In fact, a closer look at cases where it is the receiver that is in motion will show that this kind of motion leads to a very similar kind of Doppler effect. Here is an animation of the receiver moving towards the source: (...) By observing the two indicator lights, you can see for yourself that, once more, there is a blue-shift - the pulse frequency measured at the receiver is somewhat higher than the frequency with which the pulses are sent out. This time, the distances between subsequent pulses are not affected, but still there is a frequency shift: As the receiver moves towards each pulse, the time until pulse and receiver meet up is shortened."
In this explanation of the Doppler shift the distance between subsequent pulses represents the wavelength so the fact that "the distances between subsequent pulses are not affected" simply means that the moving observer measures the wavelength of light, lambda, to be unaffected. The frequency, however, shifts from f, as measured by the source, to f'=f(1+v/c), as measured by the moving observer:
http://rockpile.phys.virginia.edu/mod04/mod34.pdf
Paul Fendley: "Now let's see what this does to the frequency of the light. We know that even without special relativity, observers moving at different velocities measure different frequencies. (This is the reason the pitch of an ambulance changes as it passes you it doesn't change if you're on the ambulance). This is called the Doppler shift, and for small relative velocity v it is easy to show that the frequency shifts from f to f(1+v/c) (it goes up heading toward you, down away from you). There are relativistic corrections, but these are negligible here."
So the moving observer measures the frequency to be f'=f(1+v/c) and the wavelength to be unaffected, (lambda)'=(lambda). Therefore, he measures the speed of the light wave to be:
c' = f'(lambda)' = f'(c/f) = c + v
Is that possible? Absolutely impossible because Divine Albert has said observers always measure the speed of light to be c. Of course, it takes long and painful exercises to become believer in Divine Albert's wisdom:
http://www.liferesearchuniversal.com/1984-22
George Orwell: "He set to work to exercise himself in crimestop. He presented himself with propositions - "the Party says the earth is flat", "the party says that ice is heavier than water" - and trained himself in not seeing or not understanding the arguments that contradicted them. It was not easy. It needed great powers of reasoning and improvisation. The arithmetical problems raised, for instance, by such a statement as "two and two make five" were beyond his intellectual grasp. It needed also a sort of athleticism of mind, an ability at one moment to make the most delicate use of logic and at the next to be unconscious of the crudest logical errors. Stupidity was as necessary as intelligence, and as difficult to attain."
Pentcho Valev
pva...@yahoo.com