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TypeError: 'choice_text' is an invalid keyword argument for this functionThat above, is where the problem is where the problem is so I am going to guess you need to check your model if you wrote everything correctly.If I can see what your model looks like, I can probe in.
On Thu, Jun 15, 2017 at 10:34 AM, danbmathew <danbm...@gmail.com> wrote:
Well I'm new to django and my code is just as in the documentation.But got an error while trying to run the codeline q.choice_set.create(choice_text='Not much', votes=0).This part of the code is almost at the end of the segment named Playing With API.I will also post the error.Traceback (most recent call last):File "<console>", line 1, in <module>File "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\fields\related_descriptors.py", line 653, in createreturn super(RelatedManager, self.db_manager(db)).create(**kwargs)File "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\manager.py", line 85, in manager_methodreturn getattr(self.get_queryset(), name)(*args, **kwargs)File "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\query.py", line 392, in createobj = self.model(**kwargs)File "C:\Users\DELL\AppData\Local\Programs\Python\Python36-32\lib\site-packages\django\db\models\base.py", line 571, in __init__raise TypeError("'%s' is an invalid keyword argument for this function" % list(kwargs)[0])TypeError: 'choice_text' is an invalid keyword argument for this functionPlease help me.
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