Definitely. Thanks!
On Nov 13, 11:38 am, Sam Silverberg <
sam.silverb...@gmail.com> wrote:
> The memory required is not related to the volume size but rather the unique
> data that will be copied to the volume. The unique data lookup table, that
> is filled with the unique data finger prints, is allocated into memory when
> the SDFS volume is mounted. The table's size, and thus the memory required,
> is related to the allocation-size configuration attribute and not the volume
> size.
>
> As an example, if you set the allocation size to 1TB or
> allocation-size="107374182400" then the unique data lookup table memory will
> be around 270 megabytes based on the following calculation:
>
> memory size = ([allocation-size]/[chunk-size in bytes])*32
>
> or
>
> memory size = (107374182400/131072)*32
>
> 32 is the size of the unique data record stored in memory.
> 121072 is 128k in bytes
>