root node sum()

[Marc McIntyre]

Hi, 

I am trying to create a sunburst diagram using D3.js V4. On a root node there is a sum() method for calculating the value of a node + all of it's descendants. I only have a already computed value of the node's sum. Is there a way to use that value without adding up all of the descendants? 

Cheers,

Marc. 

[Mike Bostock]

Take a look at how node.sum is implemented:

https://github.com/d3/d3-hierarchy/blob/master/src/hierarchy/sum.js

So, if you wanted to use your precomputed sum, you could say:

root.eachAfter(function(node) {
node.value = node.data.value;
});

A similar but more wasteful approach would be to pass a value accessor to node.sum that returns zero for any internal (non-leaf) node and discard your precomputed sums.

Mike

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