How to check whether one of outV match with a given vertex ?

[Eric Cyliu]

For a vertex 'e', there are three in edges. I would like to check whether one of vertex 'b' is in the list. 

I am quite new for gremlin. Thanks for your help.

//

g.V().has('name','e').inE().outV()

==>v[2]

==>v[4]

==>v[6]

//

b

==>v[2]

// this did not work

g.V().has('name','e').inE().outV() == b

==>false

[Daniel Kuppitz]

Since you know vertex e and vertex b, you probably want to find the edge between them (if one exists):

g.V().has("name", "e").inE().filter(outV().is(b))

If all you need is a boolean value, then just append a .hasNext().

Cheers,

Daniel

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[Eric Cyliu]

Yes, this is exactly what I wanted.

I also figured another way myself. This solution is much compact. Mine looks like this.

g.V().has('name','e').inE().outV().hasId(b.id())

Thank you Daniel very much.

On Thursday, August 25, 2016 at 11:47:43 AM UTC+3, Daniel Kuppitz wrote:

Since you know vertex e and vertex b, you probably want to find the edge between them (if one exists):

g.V().has("name", "e").inE().filter(outV().is(b))

If all you need is a boolean value, then just append a .hasNext().

Cheers,

Daniel

On Thu, Aug 25, 2016 at 9:15 AM, Eric Cyliu <farsca...@live.com> wrote:

For a vertex 'e', there are three in edges. I would like to check whether one of vertex 'b' is in the list. 

I am quite new for gremlin. Thanks for your help.

//

g.V().has('name','e').inE().outV()

==>v[2]

==>v[4]

==>v[6]

//

b

==>v[2]

// this did not work

g.V().has('name','e').inE().outV() == b

==>false

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