How to "flatten" nested keys in a dictionary, when key structure varies?

[Mike Titus]

Given this YAML:

somevar:
  alpha:
    beta:
      gamma:
        foo1: bar1
        foo2: bar2
  red:
    green:
      blue:
        baz1: quz1
        baz2: quz2

I want to construct strings of the full key paths:

somevar/alpha/beta/gamma
somevar/red/green/blue

Thanks.

[Matt Martz]

There is no built in way to do this, however with a new custom filter, maybe you can get it:

def dict_path(my_dict, path=None):

    if path is None:

        path = []

    for k, v in my_dict.iteritems():

        newpath = path + [k]

        if isinstance(v, dict):

            for u in dict_path(v, newpath):

                yield u

        else:

            yield newpath, v

class FilterModule(object):

    def filters(self):

        return {

            'dict_path': dict_path

        }

And then a playbook that makes use of this:

---

- hosts: all

  vars:

    somevar:

      alpha:

        beta:

          gamma:

            foo1: bar1

            foo2: bar2

      red:

        green:

          blue:

            baz1: quz1

            baz2: quz2

  tasks:

    - debug:

        msg: "{{ item.0|join('/') }} => {{ item.1 }}"

      with_items:

        - "{{ somevar|dict_path|list }}"

Results in the output of (restricted to 1 item from the loop for brevity):

ok: [localhost] => (item=([u'alpha', u'beta', u'gamma', u'foo1'], u'bar1')) => {

    "item": [

        [

            "alpha",

            "beta",

            "gamma",

            "foo1"

        ],

        "bar1"

    ],

    "msg": "alpha/beta/gamma/foo1 => bar1"

}

with that, you could derive a playbook that makes those paths, puts the values into files, etc...

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Matt Martz
@sivel
sivel.net

[Mike Titus]

That worked perfectly -- thanks so much!

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