Capture the path from the list returned via find module

[Saranya N]

Hi all ,

I'm trying to find two XML files in all the locations only if it contains a severname and then pass the list of these files to the replace module to replace that severname by another string.

I'm able to get the file list via shell module but not via the find module.

I tried various options that I found online

---

- hosts: all



tasks:

- name: Find all Paascli Files

find:

paths: /opt/common

patterns: “test.xml|ordit.xml”

recurse: yes

contains: "servername "

register: matched_files



- debug:

msg: "{{ matched_files.files }}"



# - debug:

# msg: "{{ matched_files.files[0].path }}"





- name: Replace the word

replace:

path: "{{ item.path }}"

regexp: "servername"

replace: "new_servername"

backup: yes

# with_items: "{{ matched_files.files }}"

with_items: "{{ matched_files.results | sum(attribute='files', start=[]) | map(attribute='path')|list }}"

I get " dict object has no attribute results for the above with_item option.


Can someone suggest how to capture the path attribute from the returned file list via find module.

[Karl Auer]

Not sure if it will make a difference, but you have a space after "servername" in your contains: line.

​Regards, K.​

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Karl Auer

Email  : ka...@2pisoftware.com
Website: http://2pisoftware.com

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[Saranya N]

That space is a typo in my post