Displaying Binary matrix in AMPL

[khan]

Dear All, 

I am trying to print this binary matrix in AMPL using the following code. But when I display it gives me this:

Executing on neos-7.neos-server.org
c = 11

A :=
1 2    1
1 6    1
1 9    1
1 11   1
2 3    1
2 6    1
2 7    1
2 9    1
2 10   1
2 11   1
3 4    1
3 7    1
3 8    1
3 9    1
3 10   1
3 11   1
4 5    1
4 8    1
4 10   1
4 11   1
;

No variables declared.

AMPL MOD FILE:

param n:=4;

param c:=(n^2/2)+(n/2)+1;

param A {1..n,1..c} binary, default 0;

for {i in 1..n} 

{let A[i,i+1] := 1;}

for {i in 1..n-1} 

{let A[i,n+i+1] := 1;

      let A[i+1,n+i+1] := 1;}

for {i in 1..n-2}

{let A[i,n+i+4]:=1;

let A[i+1,n+i+4]:=1;

let A[i+2,n+i+4]:=1;}

for {i in 1..n-3}

{let A[i,n+i+6]:=1;

let A[i+1,n+i+6]:=1;

let A[i+2,n+i+6]:=1;

let A[i+3,n+i+6]:=1;}

AMPL DATA FILE:

data;

display c;

display A;

[khan]

okay I got the solution for this: 

I used like that and it works;

option display_1col 0, display_transpose -10;

display A;

[khan]

But its not displaying the first col of zeros. Whats arong? Output is here below:

A [*,*]
:   2   3   4   5   6   7   8   9  10  11    :=
1   1   .   .   .   1   .   .   1   .   1
2   .   1   .   .   1   1   .   1   1   1
3   .   .   1   .   .   1   1   1   1   1
4   .   .   .   1   .   .   1   .   1   1
;

[Robert Fourer]

When you define param A to be "default 0" then AMPL doesn't normally assign the 0 values until A is used by a "solve". As a result, if you "display A" before solving, you will see only the nonzero values that have been assigned so far. You can force all the zeros to be displayed, even before solving, by giving a more explicit display statement:

display {i in 1..n, j in 1..c} A[i,j];

Bob Fourer
am...@googlegroups.com

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