emailing the content of the current page

Vlad

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Jun 20, 2019, 1:07:34 AM6/20/19

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I'd like to send an email with html content - the current page:

mail.send('y...@example.com', 'Message subject', '<html>html body</html>')

How do I make the html body available in python code? (i.e. how do I pass it from the view to the python code?)

to get it in js easy - document.documentElement.outerHTML - but it's a long thing, just args and vars presumably won't work.

what would be the best way to pass it over / to make it available in the code in order to send by email?

p.s. I don't want to render page the again, as it has been already rendered; otherwise response.render would be an option...

Val K

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Jun 20, 2019, 6:23:55 AM6/20/19

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I think you can try to yield rendered view from controller just by 'return rendered_response'. If controller returns string (not dict) it will be sent as is

Val K

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Jun 20, 2019, 7:12:13 AM6/20/19

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Also you can hack wsgihandler.py to catch rendered response

Vlad

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Jun 20, 2019, 1:26:33 PM6/20/19

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I couldn't figure out how this woks, so just rendered it again. Not a big deal - just a matter of convenience. The email requests come occasionally, so this extra render doesn't cause trouble.

Thank you, Val!

Val K

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Jun 20, 2019, 1:39:45 PM6/20/19

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I mean the following logic:

def foo():
    ...
    ret = dict(...)
    if email_required:
        html = response.render(ret)
        ... # send html by email
        return html
    return ret

Eliezer (Vlad) Tseytkin

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Jun 20, 2019, 1:48:58 PM6/20/19

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oops

got it!

changing it right now!

simple and brilliant, as always :)

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Val K

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Jun 20, 2019, 2:07:29 PM6/20/19

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#pretty decorator
def with_email_to(addr):
    def inner(f):
        def emailer():
            ret = f()
            html = response.render(ret)
            ... # send html to addr by email
            return html
        return emailer
    return inner

@with_email_to('jo...@google.com')
def foo():
    ...




On Thursday, June 20, 2019 at 8:39:45 PM UTC+3, Val K wrote:I mean the following logic:def foo():
    ...
    ret = dict(...)
    if email_required:
        html = response.render(ret)
        ... # send html by email
        return html
    return ret    



On Thursday, June 20, 2019 at 8:26:33 PM UTC+3, Vlad wrote:I couldn't figure out how this woks, so just rendered it again. Not a big deal - just a matter of convenience. The email requests come occasionally, so this extra render doesn't cause trouble. 
Thank you, Val!

On Thursday, June 20, 2019 at 6:23:55 AM UTC-4, Val K wrote:I think you can try to yield rendered view from controller just by 'return rendered_response'. If controller returns string (not dict) it will be sent as is

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Eliezer (Vlad) Tseytkin

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Jun 20, 2019, 2:25:23 PM6/20/19

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this is simply awesome!

thank you !

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