regexp : windows filename recognition

[Ni Va]

Hi,

Here is a kind of filename in fat chars that I would like to recognize:

  $FOOBBBAR_Foooofbar_f_oobar_(2019-07-29) - Copie.zed.lnk                                                  232.0 KiB     2019

Thank you

[aro...@vex.net]

> Here is a kind of filename in fat chars that I would like to recognize:
>

> * $FOOBBBAR_Foooofbar_f_oobar_(2019-07-29) - Copie.zed.lnk*
> 232.0 KiB 2019

There's a practically infinite universe of expressions that could be made
to match it. What's distinctive about it?

It might help if you could provide an example of something that you don't
want to match, and point out what discriminates the match vs non-match.

[Ni Va]

Anything chars contained in windows'filename before a lot of spaces and begining on third char after start of line.

Anything chars of filename= \w\s-_. many times

^..filename                                    some others chars.*$

Thank you

[Andy Wokula]

Am 09.10.2019 um 14:16 schrieb Ni Va:
> Anything chars contained in windows'filename before a lot of spaces
> and begining on third char after start of line.
>
> Anything chars of filename= \w\s-_. many times
>
> ^..filename some others chars.*$

/^..\zs.\+$

List of false positives:
XXX

--
Andy

[Ni Va]

Don't understand why it returns 2 first chars on this example :

+ 20191009_191004_Vim.8.1.2125/                                                                                              4.0 KiB [D] 2019-10-

echo substitute(getline(line('.')),'^..\zs\(.\+\)\(\s\+\d\+\.\d\+\)\@=.*$','\1', "") returns + 20191009_191004_Vim.8.1.2125/

Thank you for help.

NiVa

[Andy Wokula]

Am 10.10.2019 um 10:44 schrieb Ni Va:
> Don't understand why it returns 2 first chars on this example :
>
> + 20191009_191004_Vim.8.1.2125/ 4.0 KiB [D] 2019-10-
> echo substitute(getline(line('.')),'^..\zs\(.\+\)\(\s\+\d\+\.\d\+\)\@=.*$','\1', "") returns + 20191009_191004_Vim.8.1.2125/

The match starts after `\zs', what comes before is not substituted.

I wonder why the greedy \(.\+\) does not include any spaces.
Looks like \(\s\+\d\+\.\d\+\)\@= is checked before any backtracking takes place.
"no backtracking" => actually this depends on re=0 or re=2.

:echo substitute(getline('.'), '^..\(.\{-}\)\s\+\d\+\.\d\+.\{,20}$', '\1', '')

--
Andy

[Ni Va]

It works well with .*$ in order to substitute and get first backward reference.

^..\(.\{-}\)\s\+\d\+\.\d\+.\{,20} needed to add .*$

Thank you.