getting the full path of arguments in command completion=file

[Martin Alaçam]

Hello, 
 
command! -nargs=* -complete=file Loader call Test(<f-args>)

How would I get the <f-args> to be full paths to the arguments (file names)?
I am guessing it has to be done in the command, and not in the function being called (Test)? 

Thanks in advance, 

Martin 

[Martin Alaçam]

Found it: 
command! -nargs=* -complete=file Loader for f in [<f-args>] | call Test(fnamemodify(f, ":p")) | endfor

[Gary Johnson]

On 2020-03-22, Martin Alaçam wrote:

> command! -nargs=* -complete=file Loader call Test(<f-args>)
>
> How would I get the <f-args> to be full paths to the arguments (file names)?
> I am guessing it has to be done in the command, and not in the function being
> called (Test)? 

Here's one way to do it. Replace "echo path" by your actual
processing of each file.

function! Test(...)
for file in a:000
let path = fnamemodify(file, ":p")
echo path
endfor
endfunction

Regards,
Gary

[Martin Alaçam]

Ah, it works from within the function too, that is smart. And the nicer solution. Thanks! 

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