vim9script: dump file content to list of list question !

[Ni Va]

Hi,

I got this kind of classical logfile :

2021/01/14 07:42:22.588 Information Foo dbg 

2021/01/14 07:42:22.588 Information Bar dbg 

2021/01/14 07:42:22.588  Information    Foobar dbg 

2021/01/14 07:42:22.588  Information    Barbar dbg 

..

.

and would like to add all lines' informations split by space into dict or array in vim9script.

['2021/01/14', '07:42:22.588', 'Information  Foo dbg   ']

trying map(getline(1, '$'), ' v:val->split() ') it returns list<list<string>> but impossible to declare var foo: list<list<string>>

How can I fix it ?

Best Wishes 2021

NiVa

[c.wil...@btinternet.com]

Hi

not quite clear on what you want to achieve. If it's lines like the square bracketed example (rather than internal Vim arrays), then you cd use 4 :%s constructs:

:%s/^/['/
:%s/$/']/
:%s/ /','/
:%s/ /','/

which cd of course be canned in a single command. Note not to use a global instead of the two single replacements.

regards - Chris

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[Jürgen Krämer]

Hi,

Ni Va schrieb am 15.01.2021 um 14:38:
>
> I got this kind of classical logfile :
>

> 2021/01/14 07:42:22.588 InformationFoo dbg 
> 2021/01/14 07:42:22.588 InformationBar dbg 

> 2021/01/14 07:42:22.588 Information    Foobar dbg 
> 2021/01/14 07:42:22.588 Information    Barbar dbg 
> ..
> .
>
> and would like to add all lines' informations split by space into dict or array in vim9script.
> ['2021/01/14', '07:42:22.588', 'Information  Foo dbg   ']
>
> trying map(getline(1, '$'), ' v:val->split() ') it returns list<list<string>> but impossible to declare var foo: list<list<string>>
>
> How can I fix it ?

you need to use mapnew() instead of map(), because the item type changes.

getline() returns a list of strings. The supplied expression would replace
every item of type string by an item of type list<string>. In Vim9 script
this is not allowed. Instead you need to use mapnew() which creates a new
list which is then filled with the results of the mapping expression.

Regards,
Jürgen

[Ni Va]

Hi Jürgen and thank you.

•  this seems to work well !

             var bigData_records = mapnew(getline(1, '$'), '' v:val->split() ' )

• Considering this kind of records:

2021/01/14 07:42:22.588 InformationFoo dbg 
2021/01/14 07:42:22.588 InformationBar dbg   

I wonder if I can build big dict in one line

• first key level is day
• second key level would be hour stamped  
• value is list of rest of infos

It should look like that inline:

mapnew(getline(1, '$'),     ' g:bigData[v:val->split()[0][v:val->split()[1]] = v:val->split()[2 : -1]  ')

Actually I have a more developped vimscript that ensure existence of keys ...

var lines: list<string> = getline(1, '$')     

var l: list<string> = []                      

var day: string = ''                          

var hour: string = ''                         

var infos: string = ''                        

var hourDict:  dict<any> = {}                 

var infosList: list<any> = []                 

                                              

for line in lines[0 : g:dataRows]             

                                              

  l     = line->split()                       

  day   = l[0]                                

  hour  = l[1]                                

  infos = l[2 : ]->join()                     

  #echomsg day .. ' ' .. hour .. ' ' .. infos 

                                              

  # Hours' dict                               

  if !has_key(hourDict, hour)                 

    hourDict[hour] = [infos]                  

  else                                        

    hourDict[hour]->add(infos)                

  endif                                       

                                              

  # Days' dict                                

  if !has_key(g:dataD, day)                   

    g:dataD[day] = hourDict                   

  endif                                       

                                              

endfor