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umutcan aral

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Jul 14, 2016, 12:18:10 PM7/14/16
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2016-07-14 18.55.17.jpg

fernandes

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Jul 14, 2016, 12:39:16 PM7/14/16
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14 Temmuz 2016 Perşembe 19:18:10 UTC+3 tarihinde umutcan aral yazdı:
2016-07-14 18.55.17.jpg

Cem Ozgur Sentin

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Jul 14, 2016, 1:52:16 PM7/14/16
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2^x=3^y=6'dan x=log2(6) ve y=log3(6) olur. Buna göre,

6/x+6/y
=6/[log2(6)]+6/[log3(6)]
=6log6(2)+6log3(6)
=6*[log6(2)+log6(3)]
=6*log6(2*3)
=6log6(6)
=6*1
=6 çıkar.

Asma Batuhan

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Jul 14, 2016, 4:27:06 PM7/14/16
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14 Temmuz 2016 Perşembe 19:18:10 UTC+3 tarihinde umutcan aral yazdı:
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