[Question] filter start with [all[current]]

[Mohammad Rahmani]

I have a view template like below

\define FilterTiddler() test-tiddler

<$set name="revealFilters" tiddler=<<FilterTiddler>> field=text emptyValue="[!is[system]]">
<$list filter="[all[current]subfilter<revealFilters>match<currentTiddler>]">
<<currentTiddler>> is selected!!
</$list>
</$set>

This template is used to show a message on a selected tiddler (those filtered through reavealFilters.

Filter shall be able to

1. select only one tiddler e.g myTiddler

2. select tiddlers by tag e.g. [tag[myTag]]

3. select tiddlers by combination of criteria e.g. [tag[foo]] [tag[bar]] [prefix[New]]

My question is: in the above code

1. the subfilter is a selection constructor. Why do we need all[current] in the filter?

2. What do you propose for the last part of the filter run? It seems the match<currentTiddler>  is slow?

3. What simpler solution do you propose?

Best wishes

Mohammad

[Mohammad Rahmani]

It seems this also works:

\define FilterTiddler() test-tiddler

<$set name="revealFilters" tiddler=<<FilterTiddler>> field=text emptyValue="[!is[system]]">

<$list filter="[subfilter<revealFilters>match<currentTiddler>]">

<<currentTiddler>> is selected!!
</$list>
</$set>

Is there any simpler solution?

Best wishes

Mohammad

[Saq Imtiaz]

Have you tried something like this (without using a set widget)

[all[current]subfilter{tiddler-with-filter}]

where the filter in tiddler-with-filter is something like:

[tag[myTag]]

[Mohammad Rahmani]

Hi Saq,

On Wed, Feb 24, 2021 at 11:28 AM Saq Imtiaz <saq.i...@gmail.com> wrote:

Have you tried something like this (without using a set widget)

[all[current]subfilter{tiddler-with-filter}]

While subfilter is a selection constructor why we need all[current]?

 

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[Saq Imtiaz]

You don't need it, but it limits the input to the subfilter to a single tiddler which is much faster than evaluating it for all tiddlers. Furthermore this obviates the need for the match<current> part.

[Mohammad Rahmani]

On Wed, Feb 24, 2021 at 1:10 PM Saq Imtiaz <saq.i...@gmail.com> wrote:

You don't need it, but it limits the input to the subfilter to a single tiddler which is much faster than evaluating it for all tiddlers. Furthermore this obviates the need for the match<current> part.

Thank you! Let's give a try this new solution!

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[Mohammad Rahmani]

Hi again Saq!

On Wed, Feb 24, 2021 at 11:28 AM Saq Imtiaz <saq.i...@gmail.com> wrote:

Have you tried something like this (without using a set widget)

[all[current]subfilter{tiddler-with-filter}]

where the filter in tiddler-with-filter is something like:

[tag[myTag]]

Tested above solution works but if I use a tiddler name for example HelloThere when I tested on https://tiddlywiki.com/

I see the output on all tiddlers, Does it mean [all[current]] bypassed here? I think this is because subfilter ignores the input!

 

--

[Saq Imtiaz]

[all[current]subfilter{tiddler-with-filter}]

works when filter in tiddler-with-filter is something like:

[tag[myTag]]

which tests conditions on its input (i.e. selection modifiers).

However if the filter applied by your subfilter is of the form:

HelloThere (i.e. selection constructor)

It is equivalent to writing [all[current]title[HelloThere]] which will always evaluate to HelloThere and since the filter always has a result your view template will be applied to all tiddlers.

Alternatively if you want to use selection constructors, you could do this though it will be slower:

[all[current]] :intersection[subfilter{tiddler-with-filter}]

or

[subfilter{tiddler-with-filter}contains:title<currentTiddler>]

[Mohammad Rahmani]

Thank you Saq!

Now, I got the point with your detailed explanations!

Much appreciated!

Best wishes

Mohammad

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