Float precision

[Paul Royik]

Is it possible to set for float precision of 50, but to cut trailing zeros for finite decimals?

a=Float('0.5',prec=50)

print a/7

Output: 0.071428571428571428571428571428571428571428571428571

a=Float('0.5',prec=50)

print a

Output: 0.50000000000000000000000000000000000000000000000000 (but I want a)

For latex correct output is 0.5

But how to print 0.5 instead of 0.5 with many trailing zeros?

In what cases is Float('some number', prec='') is useful?

[Vinzent Steinberg]

On Sunday, July 12, 2015 at 6:18:26 PM UTC+2, Paul Royik wrote:

Is it possible to set for float precision of 50, but to cut trailing zeros for finite decimals?

a=Float('0.5',prec=50)

print a/7

Output: 0.071428571428571428571428571428571428571428571428571

a=Float('0.5',prec=50)

print a

Output: 0.50000000000000000000000000000000000000000000000000 (but I want a)

For latex correct output is 0.5

But how to print 0.5 instead of 0.5 with many trailing zeros?

In floating point representation, there is no difference between finite and non-finite decimals, so they are printed the same.
If you want to remove trailing zeros, convert it to a string and strip the zeros:

    a_without_zeros = str(a).rstrip('0')

Vinzent

[Paul Royik]

str(a).rstrip('0') trick won't won't work with complex numbers, like 0.3000000000000+0.50000000000i

[Aaron Meurer]

The printer has an option to do this. Use sstr() and set the full_prec flag.

Aaron Meurer

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[Paul Royik]

Thank you.