How to find the number of broken pages in a particular page?

[Sudhansu Sekhar panda]

Hi All,

How to find the number of broken pages in a particular page?

Can anyone help me for the same through code?

Thanks,

Sudhansu

[ARK Satyanarayana Raju]

Hi,
This is sample code for u r question.

 
import java.util.List;

import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.firefox.FirefoxDriver;
import org.testng.annotations.AfterTest;
import org.testng.annotations.BeforeTest;
import org.testng.annotations.Test;

public class FindLinksandCheckforBrokenLinks {
    WebDriver driver;
    @BeforeTest
    public void open()
    {
        driver=new FirefoxDriver();
        driver.manage().window().maximize();
        driver.navigate().to("http://www.google.co.in/");// Use navigate instead of driver.get()
    }
    @AfterTest
    public void teardown()
    {
        driver.quit();
    }
    @Test
    public void brokenlinks() throws InterruptedException
    {
          WebElement footer= driver.findElement(By.xpath("//div[@id='footer']"));  // Get Footer element which contains all footer links
          List<WebElement> elements=footer.findElements(By.tagName("a"));
          int size=elements.size();
          System.out.println("Total links are: "+size);
          for(int j = 0;j<size;j++){    //create loop based upon number of links to traverse all links
             footer= driver.findElement(By.xpath("//div[@id='footer']"));   // We are re-creating "footer" webelement as DOM changes after navigate.back()
             footer.findElements(By.tagName("a")).get(j).getText();
             footer.findElements(By.tagName("a")).get(j).click();
             Thread.sleep(3000);
             System.out.println(driver.getTitle());
              if(driver.getTitle().contains("404")) {
               System.out.println("404 Found");
              }
              driver.navigate().back();
           Thread.sleep(3000);
          }

    }     
    }
   

Thanks,
Raju

[Mark Collin]

This won't work, you will suffer from StaleElementReferenceExceptions after navigating to the first link and then clicking back.

I would suggest not using selenium to check (by all means use Selenium to find them, just not to check them) links but instead use a Java library that can do it instead.  Have a read of:

http://ardesco.lazerycode.com/index.php/2012/07/how-to-download-files-with-selenium-and-why-you-shouldnt/

Specifically the section called "Checking that links are valid"

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[Sudhansu Sekhar panda]

Hi Mark,

You are absolutely right. The same error message is getting displayed. Is there any way to prevent this?

[Mark Collin]

Yes, read the blog entry I linked It tells you how to do what you want to do.

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