A 50 Ω resistor at a known temperature is a predictable noise source.
If your radio telescope (LNA, receiver chain, backend) also has a 50 Ω input impedance, then a 50 Ω resistor connected to that input is a perfectly matched thermal noise source. No reflections, no standing waves — just clean, well-defined noise power.
Any resistor above absolute zero generates Johnson–Nyquist noise. The available noise power is
P = k T B
where:
Crucially:
When you switch your receiver input from the antenna to a 50 Ω load:
This is the basis of:
A simple 50 Ω terminator at room temperature:
The same resistor, deliberately heated:
A calibrated noise diode is essentially:
If the resistor were not 50 Ω:
With a matched 50 Ω load:
Think of the 50 Ω resistor as an artificial sky with a precisely known brightness temperature.
Switching between:
lets you translate raw power levels into Kelvin, which is what radio astronomy actually cares about.
I don't understand how 50 ohm resistor matches 50 ohm impedance- surely the two are not the same thing?
You’re absolutely right to be suspicious here — the wording sounds hand-wavy until the distinction is nailed down properly. Let’s slow it right down and separate the concepts.
Resistance (R)
A real, dissipative property. Converts RF power into heat. A 50 Ω resistor is (ideally) frequency-independent.
Impedance (Z)
The ratio of RF voltage to current at a port:
Z = V / I
So yes — they are not the same thing in general.
When we say:
“a 50 Ω resistor matches a 50 Ω system”
what we really mean is:
The input impedance of the receiver is designed to be 50 Ω resistive, and the resistor presents 50 Ω resistive impedance at the frequencies of interest.
If both sides present:
Z = 50 + j0Ω
then from the RF signal’s point of view:
At that point, the distinction stops mattering electrically.
At RF we don’t think “this is a resistor” or “this is an amplifier”. We think:
What impedance does this port present at this frequency?
If both ports look identical to the wave, they are matched — regardless of what’s inside.
Good instinct again.
The receiver input:
But at the input connector:
That’s all matching ever means.
The sloppy phrase:
“50 Ω resistor matches 50 Ω impedance”
really means:
“Two ports present equal complex impedance, so no reflection occurs”
It has nothing to do with:
Thermal noise theory assumes:
When your receiver input is matched:
Imagine shouting down a perfectly tuned hallway:
The hallway doesn’t have to be “made of your throat” — it just has to present the same impedance.
Hi Alex,
In that you are absolutely right – I have noticed that when I ask questions of ChatGPT sometimes it quotes my own website www.astronomy.me.uk – now that is a really dubious source of information – I know what rubbish is on there – but it turns out that 100+ GB of apparently sensible information with top level URL seems to persuade the AI engine that this is good quality information!
NB For anyone reading my website please let me know where information is wrong and needs to be changed or put comment to that effect on the webpage in question.
Andy
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That is helpful to know – please keep such comments coming along!
From: 'b alex pettit jr' via Society of Amateur Radio Astronomers <sara...@googlegroups.com>
Sent: 05 February 2026 10:58
To: andrew.thornett via Society of Amateur Radio Astronomers <sara...@googlegroups.com>
Subject: Re: [SARA] Re: How can a 50 ohm resistor be used to produce reference signal on a radio telescope with 50 ohm impedance? Surely, resistance and impedance are not the same thing.
Hi Andrew,
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https://old.w1yca.org › tech › ant › reflectIII.pdf
There are many of changes and clarifications that probably make this worth a look...
Really like this:
= an example of an Automated Information retrieval system .. it has a huge data base, but no Brains :) TNX
....bill....