drracket -- getting the buffer's current filename?

ibar...@radford.edu

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Sep 1, 2020, 10:35:55 AM9/1/20

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When running from inside drracket, `(find-system-path 'run-file)` understandable returns the DrRacket executable. Is there a way for me to further find the name of the source-file, in that situation?

--Ian

Robby Findler

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Sep 1, 2020, 12:42:50 PM9/1/20

to ibar...@radford.edu, Racket Users

Not sure if this is what you want, but here's a thing:

#lang racket
(define-syntax (my-source stx)
#`'#,(syntax-source stx))

my-source

On Tue, Sep 1, 2020 at 9:36 AM ibar...@radford.edu <ibar...@radford.edu> wrote:

When running from inside drracket, `(find-system-path 'run-file)` understandable returns the DrRacket executable. Is there a way for me to further find the name of the source-file, in that situation?
--Ian

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Laurent

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Sep 1, 2020, 1:40:08 PM9/1/20

to ibar...@radford.edu, Racket Users

What do you want this for, more precisely?

On Tue, Sep 1, 2020 at 3:35 PM ibar...@radford.edu <ibar...@radford.edu> wrote:

When running from inside drracket, `(find-system-path 'run-file)` understandable returns the DrRacket executable. Is there a way for me to further find the name of the source-file, in that situation?
--Ian

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