Applicable sets and hashes?

[Maciek Godek]

Hi,

is it possible to take Racket's hash tables and sets, and make them applicable (like in Clojure)?

So that, for example

(#hash((a . 1) (b . 2)) 'a)

would be equivalent to

(hash-ref #hash((a . 1) (b . 2)) 'a)

and 

((set 1 2 3) 1)

would be equivalent to

(set-member? (set 1 2 3) 1)

[Ricardo Herdt]

Hi Maciek,

yes, it is. Take a look at rackjure:

https://docs.racket-lang.org/rackjure/index.html#(part._dict-app)

Regards,

Ricardo

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[Maciek Godek]

Great, thanks!

W dniu niedziela, 8 września 2019 11:57:47 UTC+2 użytkownik ricardo.g.herdt napisał:

Hi Maciek,

yes, it is. Take a look at rackjure:

https://docs.racket-lang.org/rackjure/index.html#(part._dict-app)

Regards,

Ricardo


Am 08.09.2019 11:51 schrieb Maciek Godek:
> Hi,
> is it possible to take Racket's hash tables and sets, and make them
> applicable (like in Clojure)?
>
> So that, for example
>
> (#hash((a . 1) (b . 2)) 'a)
>
> would be equivalent to
>
> (hash-ref #hash((a . 1) (b . 2)) 'a)
>
> and
>
> ((set 1 2 3) 1)
>
> would be equivalent to
>
> (set-member? (set 1 2 3) 1)
>
>  --
>  You received this message because you are subscribed to the Google
> Groups "Racket Users" group.
>  To unsubscribe from this group and stop receiving emails from it,

> send an email to racket...@googlegroups.com.