Working out which directory the current code was loaded from?

[Peter W A Wood]

I have a short racket program/script that reads a file from the directory in which it is stored. The directory structure is something like this:

a/
b/
c/
my-racket.rkt
my-data-file.txt

I want to be able to run the program from the command line no matter what is the current working directory. E.G.:

a> racket b/c/my-racket.rkt
a/b> racket c/my-racket.rkt
a/b/c> racket my-racket.rkt

In order to do so, I need to provide the correct path to my-data-file.txt depending on from where the script was launched. I haven’t learnt about Racket modules yet so I resorted to searching Stack Overflow. I found a code snippet that I used which worked:

(define script-dir (path-only (resolved-module-path-name
(variable-reference->resolved-module-path
(#%variable-reference)))))

Is this the best way to ascertain the directory of the “current module”?

Thanks in advance

Peter

[Philip McGrath]

For this particular purpose, you want `define-runtime-path`: https://docs.racket-lang.org/reference/Filesystem.html#%28part._runtime-path%29

-Philip

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[Peter W A Wood]

Many thanks Philip

The resulting code is much neater and, to me, more readable:

(define-runtime-path foo.txt "foo.txt")

(define-runtime-path bar.txt "bar.txt")

(define-runtime-path outfile.txt "outfile.txt")

(define-runtime-path Data/portfolio.csv "../../Data/portfolio.csv")

(define-runtime-path Data/portfolio.csv.gz "../../Data/portfolio.csv.gz”)

Peter