pyc file issue

Todd Widup

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May 26, 2017, 11:12:30 PM5/26/17

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so I have a few tools I gave over to a friend..gave them the PYC files.

part of what one of the tools does is get the directory path it was executed from to pass along.

anyways, my friend that was running it, kept getting some errors about a path not existing...strange thing was, it was showing the path where I have the tools on my local machine, not where he has them.

so...do PYC files store info like that? I always thought it was strictly a compiled version of the py file, with nothing else

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Todd Widup
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Justin Israel

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May 27, 2017, 1:02:44 AM5/27/17

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On Sat, May 27, 2017, 3:12 PM Todd Widup <todd....@gmail.com> wrote:

so I have a few tools I gave over to a friend..gave them the PYC files.

part of what one of the tools does is get the directory path it was executed from to pass along.

anyways, my friend that was running it, kept getting some errors about a path not existing...strange thing was, it was showing the path where I have the tools on my local machine, not where he has them.

so...do PYC files store info like that? I always thought it was strictly a compiled version of the py file, with nothing else

Do you have an example of what kind of code was returning a cached result from when the pyc was generated?

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Todd Widup
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todd....@gmail.com

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Todd Widup

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May 27, 2017, 12:42:20 PM5/27/17

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def getExecutingfile():
    exFile=namedtuple("filePath","path, file")
    path=None
    name=None
    frame=sys._getframe(1)
    fil=frame.f_code.co_filename
    path,name=os.path.split(fil)

    return exFile(path,name)

thats the code I am running in a util.py file that is called by core.py in core.py is where it seems to get hard coded to the path I have things sourced from

On Fri, May 26, 2017 at 10:02 PM, Justin Israel <justin...@gmail.com> wrote:

On Sat, May 27, 2017, 3:12 PM Todd Widup <todd....@gmail.com> wrote:
so I have a few tools I gave over to a friend..gave them the PYC files.

part of what one of the tools does is get the directory path it was executed from to pass along.

anyways, my friend that was running it, kept getting some errors about a path not existing...strange thing was, it was showing the path where I have the tools on my local machine, not where he has them.

so...do PYC files store info like that? I always thought it was strictly a compiled version of the py file, with nothing else

Do you have an example of what kind of code was returning a cached result from when the pyc was generated?

--
Todd Widup
Creature TD / Technical Artist
todd....@gmail.com

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Justin Israel

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May 27, 2017, 6:17:10 PM5/27/17

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On Sun, May 28, 2017 at 4:42 AM Todd Widup <todd....@gmail.com> wrote:

def getExecutingfile():
    exFile=namedtuple("filePath","path, file")
    path=None
    name=None
    frame=sys._getframe(1)
    fil=frame.f_code.co_filename
    path,name=os.path.split(fil)

    return exFile(path,name)

thats the code I am running in a util.py file that is called by core.py   in core.py is where it seems to get hard coded to the path I have things sourced from

Given that a pyc file has all of its code objects compiled and serialized up front, and that its primary purpose is to optimize subsequent runs of the program as opposed to be used as a distribution format, I suppose it shouldn't be surprising that the filename has already been evaluated and marshalled as part of the code object. It is meant to make sense and be accurate when debugging is performed against the pyc file that lives in the original location relative to the source file. So we could say that while it should work to distribute pyc files to users of the same platform and python version, one could expect certain debugging aspects to not work properly.

Is the intent of this function to get the filename of the module that is the caller of getExecutingfile() (one stack frame back, for debugging purposes)? If so, does this approach work?

sys._getframe(1).f_globals['__file__']

At least this approach isn't referring to the already-compiled code objects, and is looking at the globals for the frame.

Justin

On Fri, May 26, 2017 at 10:02 PM, Justin Israel <justin...@gmail.com> wrote:

On Sat, May 27, 2017, 3:12 PM Todd Widup <todd....@gmail.com> wrote:
so I have a few tools I gave over to a friend..gave them the PYC files.

part of what one of the tools does is get the directory path it was executed from to pass along.

anyways, my friend that was running it, kept getting some errors about a path not existing...strange thing was, it was showing the path where I have the tools on my local machine, not where he has them.

so...do PYC files store info like that? I always thought it was strictly a compiled version of the py file, with nothing else

Do you have an example of what kind of code was returning a cached result from when the pyc was generated?

--
Todd Widup
Creature TD / Technical Artist
todd....@gmail.com

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Todd Widup
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todd....@gmail.com

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Marcus Ottosson

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May 28, 2017, 4:18:54 AM5/28/17

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How about this?

def getExecutingfile():
  return __file__

Justin Israel

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May 28, 2017, 8:13:52 AM5/28/17

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That just returns the file of the current module. The original code wants to inspect the calling frame which could be in another module.

If this utility module is used in some other tool it might look like:

import foo.utils

print foo.utils.getExecutingFile()

# myModule.py

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Todd Widup

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May 28, 2017, 6:22:51 PM5/28/17

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justin's correct

On Sun, May 28, 2017 at 5:13 AM, Justin Israel <justin...@gmail.com> wrote:

On Sun, May 28, 2017, 8:18 PM Marcus Ottosson <konstr...@gmail.com> wrote:
How about this?

def getExecutingfile(): return __file__

That just returns the file of the current module. The original code wants to inspect the calling frame which could be in another module.

If this utility module is used in some other tool it might look like:

import foo.utils
print foo.utils.getExecutingFile()
# myModule.py

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Justin Israel

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May 28, 2017, 6:28:08 PM5/28/17

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On Mon, May 29, 2017, 10:22 AM Todd Widup <todd....@gmail.com> wrote:

justin's correct

Did that suggestion to use the globals end up working?

On Sun, May 28, 2017 at 5:13 AM, Justin Israel <justin...@gmail.com> wrote:

On Sun, May 28, 2017, 8:18 PM Marcus Ottosson <konstr...@gmail.com> wrote:
How about this?

def getExecutingfile(): return __file__

That just returns the file of the current module. The original code wants to inspect the calling frame which could be in another module.

If this utility module is used in some other tool it might look like:

import foo.utils
print foo.utils.getExecutingFile()
# myModule.py

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Todd Widup
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todd....@gmail.com

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Todd Widup

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May 28, 2017, 6:35:47 PM5/28/17

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hadnt tried it yet. been working on another area of this project. once I drop this update to them, ill add some stuff to use __file__ in and see if that works correctly or not.

hmmm, if I did this

in module Path

fil=__file__

then in module Bob

import Path as pth

test=pth.fil

if I path was a py and Bob was a PYC..you think it would compile like I expect?

On Sun, May 28, 2017 at 3:27 PM, Justin Israel <justin...@gmail.com> wrote:

On Mon, May 29, 2017, 10:22 AM Todd Widup <todd....@gmail.com> wrote:
justin's correct

Did that suggestion to use the globals end up working?

On Sun, May 28, 2017 at 5:13 AM, Justin Israel <justin...@gmail.com> wrote:

On Sun, May 28, 2017, 8:18 PM Marcus Ottosson <konstr...@gmail.com> wrote:
How about this?

def getExecutingfile(): return __file__

That just returns the file of the current module. The original code wants to inspect the calling frame which could be in another module.

If this utility module is used in some other tool it might look like:

import foo.utils
print foo.utils.getExecutingFile()
# myModule.py

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Todd Widup
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Justin Israel

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May 28, 2017, 6:51:45 PM5/28/17

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On Mon, May 29, 2017 at 10:35 AM Todd Widup <todd....@gmail.com> wrote:

hadnt tried it yet. been working on another area of this project. once I drop this update to them, ill add some stuff to use __file__ in and see if that works correctly or not.

hmmm, if I did this

in module Path

fil=__file__

then in module Bob

import Path as pth

test=pth.fil

Maybe I don't understand the question, but to me it looks like its the exact same thing as just referring to __file__ directly. All it is doing is creating another reference to the __file__ global variable.

if I path was a py and Bob was a PYC..you think it would compile like I expect?

On Sun, May 28, 2017 at 3:27 PM, Justin Israel <justin...@gmail.com> wrote:

On Mon, May 29, 2017, 10:22 AM Todd Widup <todd....@gmail.com> wrote:
justin's correct

Did that suggestion to use the globals end up working?

On Sun, May 28, 2017 at 5:13 AM, Justin Israel <justin...@gmail.com> wrote:

On Sun, May 28, 2017, 8:18 PM Marcus Ottosson <konstr...@gmail.com> wrote:
How about this?

def getExecutingfile(): return __file__

That just returns the file of the current module. The original code wants to inspect the calling frame which could be in another module.

If this utility module is used in some other tool it might look like:

import foo.utils
print foo.utils.getExecutingFile()
# myModule.py

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Todd Widup
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todd....@gmail.com

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Todd Widup
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