pass a diccionary as function parameters

[Rudi Hammad]

Hi,
 I am trying to do the following
Let´s say that I have a dictionary like this

myDic = {'config_type': u'high', 'config_path': u'C:\somePath'}

I want to create a function that will execute the following the dictionary items as parameters

def foo('config_type'= 'high', 'config_path': 'C:\somePath')

I can´t figure out how to do this.
myDic will keep changing all the time, and I want to extract each time the items as parameters and execute the function
as explained above. The examples that I´ve read with **kwargs I am not sure if they apply here.

thank you

[Marcus Ottosson]

Try this.

myDic = {'config_type': u'high', 'config_path': u'C:\somePath'}

def foo(config_type='high', config_path='C:\somePath'):
    print(config_type, config_path)

foo(**myDic)
# Result: (u'high', u'C:\\somePath')

def foo(**kwargs):
    print(kwargs)

foo(**myDic)
# Result: {'config_type': u'high', 'config_path': u'C:\\somePath'}

​

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[Rudi Hammad]

I want to create a function that will execute the following the dictionary items as parameters

def foo('config_type'= 'high', 'config_path': 'C:\somePath')

EDIT: Sorry I meant def foo(config_type= 'high', config_path= 'C:\somePath')

[Rudi Hammad]

Yes that´s it.Sorry, I misunderstood the use of **kwargs.
Thanks.