Randomly changing stuff to see what happens is not a good approach.
I'd start by very thoroughly checking that you have the right components in the right places, that you don't have any dry joints or solder bridges. Put the resistors you took out back in - they are there for a reason as I mentioned previously.
My money is on you having made a mistake somewhere - problem solving requires a methodical approach, following the signal chain from source, in this case from the 60Hz take off from the power input to the board...
Do you have a 'scope?
Nick
The 10s are driven by 7490s whereas the units are driven by 7492s. Do you have the right chips in the right places?
I'd also try swapping round the 74141s between the 10s and units to see if the problem moves with them - 74141s can fail....
Isolate the problem.
Nick
Ok, did some quick calculations, and the drive current needed to drive the 7417 from the output of the counter with the 360 ohm resistor to VCC, you need 14ma. The current output of the 74LSxx counter is only 8ma, and the 74xx is 16ma. When and if the 7417 see's a good logic low on it's input, it's output will switch low pulling the 510 ohm low, 9ma needed, helping drive the counter output low. The 74LS17 can drive 30ma, so that can help once it can see a good logic low (.8V) on the input. So, if we increase the resistance of the 360 ohm resistor to 625 ohms, that may be a place to start. These are rough calculations, but I would go back to using the 74xx's instead of the 74LSxx's this would have been better.
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Personally, I prefer 4000 series CMOS, for this kind of thing.
Good to see that the OP, and his buddy, figured it out.
360 ohms is way too little resistance for *any* sort of
TTL pullup resistor! That apparently got confused with
the standard *pull down* resistor used to keep an unattended
TTL input *low*. 360 ohms for a TTL pulldown is just right.
2.2k ohms is the standard value to use as a TTL pullup.
That goes for regular old 7400 series TTL, as well as 74LS
series.
The old military practice was to always use 1k ohm as the
standard TTL pullup resistor value. Note that even when using
that 1k pullup resistance, that all we are asking of any TTL
gate which is pulled up by this, is to be able to provide 5
milliamperes
in order for for the output to go low.
Even that value of 1k ohm would work ok with either plain 7400 or
74LS.
2.2k is much more like it, however.
At that value, all we are asking is 2.3 mA, and that works fine.
360 ohms is just simply too close to being a piece of wire!!
(This is all explained in great detail on page 12 of Don Lancaster's
famous TTL Cookbook)
The "seconds-to-minutes" and "minutes-to-hours" pulses are passed thru 1000pf caps, feeding 4.7K loads, that normally sit at 5V. It has to use a 5V supply due to the 74141 drivers, also used. Short pulses are seen at the respective inputs, for minute, and hour, "bumps". Setting is done thru 4093 Schmitt gates, which are made "open drain", by using 1N914 diodes, in their output legs. Since its 4000 CMOS, a logic-0 is anything under 1/3 supply, or ~1.5V or less. A logic-1 is anything over 2/3 supply (>3.5V). The 0.7V diode drop is a non-issue, here. Punching the "hours" or "minute" button, increases the count by one, per depression. No goofy accelerated clock scheme. This would be much more difficult to implement in TTL.