sir please explain how to solve this. In how many ways can 5 subjects be arranged in 6 periods so that each subject appears at least once

[Rudramuni MJ]

[Ganesha AS]

Let the subjects be P,Q,R,S and T. Subject P has a choice of 6 slots in the timetable.  Similarly Q has 5, R has 4, S has 3  and T has 2 choices.  That is 6!=720. But the remaining one slot can be filled in 5 ways by 5 subjects.  That is 5x720=3600 possible Permutations. But they are not distinct as one subject is repeating.  Therefore consider 50% of it. Therefore total Permutations are 1800

On 5 Dec 2014 21:54, "Rudramuni MJ" <mjrmu...@gmail.com> wrote:

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[sadashiva poojary]

Correct Sir because one subject is repeated two times so total number
of permutation are ( 720x5)divided by 2!=1800.

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[Ganesha AS]