weld thickness

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Raghul

non lue,
30 août 2019, 14:53:0830/08/2019
à Materials & Welding
Background: A welder tests on an NPS 6 Sch. 80 (0.432 in. wall) coupon, depositing 0.100 in. of E6010 and the balance of 0.332 in. using E7018.

Question (1): Using E6010, is the welder qualified to deposit 0.864 in. maximum of weld metal?

Reply (1): Yes.

Question (2): Using E7018, is the welder qualified to deposit 0.664 in. maximum of weld metal?

Reply (2): Yes.

Question (3): Is the welder qualified to deposit 0.864 in. of weld metal using E6010 plus 0.664 in. of E7018 weld metal deposit thickness for a total of 1.528 in. in the same groove?

Reply (3): No

Above clauses are get from ASME ix interpretation.

Please explain  Using E6010, how the welder qualified to deposit 0.864 in. maximum of weld metal???????

Aakash

non lue,
21 oct. 2019, 09:36:4021/10/2019
à Materials & Welding
Interpretation number please

defrih...@gmail.com

non lue,
22 oct. 2019, 01:26:0622/10/2019
à Materials & Welding
All Answer : No
Because range qualification welder for production 2t, So E6010 max 0,2 Inch and E7018 max 0,664 Inch
refer to QW 451 ASME IX

Tajuddin Mohammed

non lue,
7 nov. 2019, 22:19:0707/11/2019
à material...@googlegroups.com
Please Refer QW-433 ASME Sec iX
1.If a welder qualified for F4 with backing can weld F3 with backing as per QW-433
Welder is already qualified for F3 without backing 0.200 inch max (2×0.100 inch) and One more 0.664 inch with F3 he can weld total 0.864 inch.

2. For thickness of weld metal qualified refer QW-452.1(b)
For example welder deposited F4 0.332 inch thickness weld metal deposited.
Maximum weld metal deposited will ne 2×0.332= 0.664.




Mohammed Tajuddin

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