Unexpected difference between String.toCharArray() and String.listToArray("") when using isNumeric()

[Juan Aguilar]

I have to loop over a string to evaluate each character in the string and determine whether each character is numeric. In converting the string to an array, I came across some odd behavior:

When I use toCharArray() and then use a for loop over the array, isNumeric() returns false for each value. But if I use a from-to loop and call the array item by index, it evaluates properly:

strAccountNumber = "8B345-7890";

arrAccountNumberTCA = strAccountNumber.toCharArray();
dump(var=arrAccountNumberTCA, label="strAccountNumber.toCharArray()");

echo("<p>");
for (itmTCA in arrAccountNumberTCA){
 echo("isNumeric(#itmTCA#):" & isNumeric(itmTCA) & " (#itmTCA#)<br/>" );
}
echo("</p>");

echo("<p>");
intTCALen = Len(arrAccountNumberTCA);
loop index="i" from="1" to="#intTCALen#" {
 echo("isNumeric(arrAccountNumberTCA[#i#]): " & isNumeric(arrAccountNumberTCA[i]) & " (#arrAccountNumberTCA[i]#)<br/>" );
}
echo("</p>");

Oddly, if I use listToArray("") instead, neither the for loop nor the from-to loops return the expected values from isNumeric():

strAccountNumber = "8B345-7890";

arrAccountNumberLTA = strAccountNumber.listToArray("");
dump(var=arrAccountNumberLTA, label="strAccountNumber.listToArray("""")");

echo("<p>");
for (itmLTA in arrAccountNumberLTA){
 echo("isNumeric(#itmLTA#):" & isNumeric(itmLTA) & " (#itmLTA#)<br/>" );
}
echo("</p>");

echo("<p>");
intLTALen = Len(arrAccountNumberLTA);
loop index="i" from="1" to="#intLTALen#" {
 echo("isNumeric(arrAccountNumberLTA[#i#]): " & isNumeric(arrAccountNumberLTA[i]) & " (#arrAccountNumberLTA[i]#)<br/>" );
}
echo("</p>");

Is this a bug, expected behavior, or am I going about this the wrong way? I guess I could just use Mid without converting the string to an array:

strAccountNumber = "8B345-7890";

echo("<p>");
intStrLen = Len(strAccountNumber);
loop index="i" from="1" to="#intStrLen#" {
 echo("isNumeric(Mid(strAccountNumber, #i#, 1)): " & isNumeric(Mid(strAccountNumber, i, 1)) & " (#Mid(strAccountNumber, i, 1)#)<br/>" );
}
echo("</p>");

Is there a "best" way to do this?

Environment is:

Version	Lucee 4.5.3.018 final

OS	Mac OS X (10.11.6) 64bit
Remote IP	127.0.0.1
Servlet Container	Apache Tomcat/8.0.15
Java	1.8.0_66 (Oracle Corporation) 64bit
Architecture	64bit

Thanks,

Juan

[Jean Moniatte]

Hello,

what about using a regular expression to make sure that each character is numeric?

reFind("^([0-9])$",strAccountNumber)

Thanks,

Jean

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[Denard Springle]

toCharArray() is a java string method, so it converts all of the numbers to strings.

listToArray( strAccountNumber, '' )

works in ACF & Lucee

strAccountNumber.listToArray('')

does not work in Lucee, but does in ACF

I'd say that's a bug and I'd suggest filing a bug report for that.

In the meantime, to get you going, however, I'd just swap around to using the function listToArray() instead of the member function

[Denard Springle]

And by 'does not work in Lucee' I meant that it produces 'no' for isNumeric() when using the listToArray() member function, to clear up any confusion :)

[Michael Offner]

toCharArray is a method of the class String that is returning a char array, not a string array

http://docs.oracle.com/javase/6/docs/api/java/lang/String.html#toCharArray()

so question is should a char primitive type or a java.lang.Character that contains a number be interpreted as numeric.

when i run this in acf and lucee:

c=createObject('java','java.lang.Character').init('1');

writedump(isNumeric(c));

writedump(isNumeric(c&""));

 both engines give me the same result:

false

true

so both interpret a character not as numeric even it contains a number, but they can convert it to a number.

in my case this is a bug in both engines we should address.

but coming back to your problem at hand. the easiest way to do it is this:

strAccountNumber = "8B345-7890";

length=strAccountNumber.len();

for(i=1;i<=length;i++) {

digit=strAccountNumber[i];

echo("isNumeric(#digit#):" & isNumeric(digit) & "<br/>" );

}

// or

loop from=1 to=strAccountNumber.len() index="i" {

digit=strAccountNumber[i];

echo("isNumeric(#digit#):" & isNumeric(digit) & "<br/>" );

}

you can address a string like an array

Micha

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[Michael Offner]

FYI

https://luceeserver.atlassian.net/browse/LDEV-955

On Thu, Aug 4, 2016 at 3:54 PM, Denard Springle <denard....@gmail.com> wrote:

And by 'does not work in Lucee' I meant that it produces 'no' for isNumeric() when using the listToArray() member function, to clear up any confusion :)

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[Juan Aguilar]

Thanks so much, Micha. 

Now that you mention it, I think I remember seeing the "string like an array" in one of your video presentations (but I can't remember for sure.) I was looking all over but was searching for a blog post or thread not a video.

Thanks again,

Juan

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[Michael Offner]

@Juan np

in meantime i also fixed the issue with characters, character are now handled the same way as strings.

@Denard i also fixed that listToArray return a character array in that case.

new version is building atm

Micha

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[Denard Springle]

Thanks Micha! Great work. And thanks for the clarification. :)

-- Denny