What is a proper way to delete a position?

[Alexey Tikhonov]

Hello!

I'm trying to make a script which would replace a selected node in the outline with the node's "shell copy". The new node should have the same header and body as the original one with all children cloned. After creating the new node the original position should be deleted - and that does not work. Could you, please, give me a hint where an error is?

The script looks like this:

# Replaces a node with its shell copy -

# a node with the copied header/body and cloned children

shell_copy = p.insertBefore()

shell_copy.h = p.h

shell_copy.b = p.b

# Preserve the order of the children:

child_no = 0

for child in p.children():

    c.dragCloneToNthChildOf(child, shell_copy, child_no)

    child_no = child_no + 1

# Keep it tidy

shell_copy.contract()

#Delete the old node

p.doDelete() # Does not delete the position. Wrong method?

# Select the newly created position

c.redraw(shell_copy)

Alexey

[Edward K. Ream]

On Mon, Dec 7, 2020 at 1:11 AM Alexey Tikhonov <tickli...@gmail.com> wrote:

Hello!

I'm trying to make a script which would replace a selected node in the outline with the node's "shell copy". The new node should have the same header and body as the original one with all children cloned. After creating the new node the original position should be deleted - and that does not work. Could you, please, give me a hint where an error is?

My guess is that the culprit is:

shell_copy = p.insertBefore()

Oops. This invalidates position p!

Instead, the safe way is to create the new node after p. Now position p remains valid.

Edward

[Alexey Tikhonov]

Thanks!

пн, 7 дек. 2020 г., 18:36 Edward K. Ream <edre...@gmail.com>:

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[Edward K. Ream]

On Mon, Dec 7, 2020 at 10:03 AM Alexey Tikhonov <tickli...@gmail.com> wrote:

Thanks!

You're welcome. Happy scripting.

Edward