Would you please tell me how this happen and how we interpret this?
Dear Terrence,
Thank you very much for your response.
I reconstructed the table adding scaling correction factors and shift parameters. Then, I calculated (standard chi-square/scaling correction factor) + shift parameter in the right edge column. These numbers are about the same as the scaled.chi-square values.

Then, I conducted anova between these two
models.

The scaled chi-squared difference test, using the difference value of standard chi-square between the two models, showed that the factorial invariance model was significantly worse than the configural invariance model. Is my interpretation right?
We should use standard chi-square values for model comparison instead of using scaled chi-square values.
Is my understanding right?
Further, I calculated scaled cfi, tli, and rmsea in the two models.

These values showed that the factorial invariance model was better than the configural invariance model.
Although these findings contradicted the previous ones of the chi-square difference test, the values such as cfi, tli, and rmsea have similar meaning to effect size and they do not always produce similar suggestions to the statistical test. In addition to the two findings, we should judge which model is better comprehensively with theoretical consideration. Is my understanding right?
Sincerely,
Hideki
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factorial invariance model was significantly worse than the configural invariance model. Is my interpretation right?
We should use standard chi-square values for model comparison instead of using scaled chi-square values.
Is my understanding right?
These values showed that the factorial invariance model was better than the configural invariance model.
Although these findings contradicted the previous ones of the chi-square difference test
we should judge which model is better comprehensively with theoretical consideration. Is my understanding right?
Dear Terrence,
Thank you very much for your response.
According to your suggestion, “Try instead looking at local indices of misfit by running lavResidual(),”
I run lavResiduals().
I have four groups, each of which has a standardized residual matrix for covariance (cov.z).
But, it seems to be difficult for me to deal with all of them.
Is lavResiduals() similar to modificationIndices()?
It seems to me that these functions give us only the misfit information in each group.
I think that both lavResiduals() and modificationIndices() cannot show which equal constraint worsen the fit.
Is my understanding right?
I need the information of misfit between groups.
Would you please tell me where I can get such information?
Sincerely yours,
Hideki