JOOQ doesn't set a parameter when its marked as both IN and OUT

[Trisha gangadhar]

I am using a setter to set an IN Parameter, in my oracle stored procedure, its marked as below

PROCEDURE test
    (
       test_1                        IN OUT       someType,

      test_2                         IN.               someType

)

when I use the setter , setTest1 which is auto generated 

Test test = new Test();

test.setTest1("something")

, it sets the value. But when I execute

test.execute(configuration). the binding log shows the value as ? and I get this error

"wrong number or types of arguments in call" , I see all other params are set successfully.

Is this is a known issue? what is the workaround?

[Lukas Eder]

Hi Trisha,

Thanks for your message. I'm not aware of such a limitation, at least not for those dialects for which we support stored procedures. Can you provide a more complete reproducer, including:

- What RDBMS is this about

- What version of jOOQ are you using

- What specific type is someType

- How did you set up your code generator

- Anything else the helps reproduce the issue

Note we have a template to create MCVE's for bug reports and support requests: https://github.com/jOOQ/jOOQ-mcve. Perhaps that's helpful

Thanks,

Lukas

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