calculate real distances of cube map face

[CurvilinearNeanderthaler (Christoph)]

Hello,

I was pondering on the following problem:

Is it possible to calculate the 'real' distances in a cube face image, given the fact that you know the camera heigth?

According to me, correct me if I'm wrong, if you have a camera height of 1.65 m for instance, then the cube face (square) where you standing on, so to speak, should have, according to Pythagoras theorem, sides that are in reality (or represent in reality) 1.65m?

So the question is, because you already know the length of one common side of both squares, can you from there on, calculate/estimate the distances of the cube face 'in front' of you, by measuring the angles?

The maths of how to do this are eluding me for the moment.

Thanks.

[CurvilinearNeanderthaler (Christoph)]

And actually, I believe Pythagoras Theorem gives the length of a half side in this case, so the length is 3.3 m (10 ft 10 inch)
Op zondag 19 juli 2020 08:03:15 UTC+2 schreef CurvilinearNeanderthaler (Christoph):