what is a &^= b means?

[xie cui]

func f(a, b int) int {

    a &^= b

    return a

}

what is this op (&^=) means?

[xie cui]

 it means OANDNOT!!!

[Jan Mercl]

There is a wonderful source of answers to such questions here:
https://golang.org/ref/spec

[Brian Candler]

More or less equivalent to:

a = a & (^b)

where & is bitwise AND operator, and ^ is bitwise NOT operator.  Upshot: any bit which is 1 in 'b' causes the corresponding bit in 'a' to be set to 0.

[Wojciech S. Czarnecki]

Dnia 2021-04-24, o godz. 05:42:01
xie cui <cuiw...@gmail.com> napisał(a):

> what is this op (&^=) means?

This is common idiom for "bit clear" in Go

Chinese: https://gfw.go101.org/article/operators.html

English:
https://go101.org/article/operators.html
https://golang.org/ref/spec#assign_op
https://yourbasic.org/golang/bitwise-operator-cheat-sheet/

Hope this helps,


--
Wojciech S. Czarnecki
<< ^oo^ >> OHIR-RIPE