How, exactly, is the Principle of Equivalence used by Einstein to develop GR? TIA, AG
> Supposedly, the EP gave Einstein his key insight for GR, but his November 1915 doesn't reference it, not once! AG
> tensors are inherently independent of coordinate systems
> What has this to do with the Equivalence Principle?
> For laws of physics to exist, they must be independent of coordinate system.
> I don't see what the EP has to do with this,
On Mon, Jul 6, 2020 at 2:36 AM Alan Grayson <agrays...@gmail.com> wrote:> For laws of physics to exist, they must be independent of coordinate system.That statement IS the Equivalence Principle,
it's just using different language, and Einstein passionately thought it was true, but there were some instances where it didn't seem to be. For example, if there was no limit on how fast you could move and the speed of causality was infinite then you could move at the speed of light alongside a light beam and if you looked at the light beam you would see that it consisted of a unmoving standing wave of electric and magnetic fields; but that's NOT what Maxwell's equations says it should ever look like. So Maxwell's equation, a very important law of physics, would NOT be independent of the coordinate system.
Einstein was just about the only one who was bothered by this and so he worked on the problem and in 1905 he found the solution, at least for Maxwell's equations, he found a way to make them true regardless of the coordinate system.
How, exactly, is the Principle of Equivalence used by Einstein to develop GR? TIA, AG
> I sense a flaw in GR
On Tuesday, July 7, 2020 at 10:06:44 PM UTC-6, Alan Grayson wrote:
On Tuesday, July 7, 2020 at 8:50:50 PM UTC-6, Alan Grayson wrote:
On Tuesday, July 7, 2020 at 8:05:28 PM UTC-6, Bruce wrote:On Wed, Jul 1, 2020 at 4:18 PM Alan Grayson <agrays...@gmail.com> wrote:
How, exactly, is the Principle of Equivalence used by Einstein to develop GR? TIA, AG
This lecture by Sean Carroll should answer all your questions:
Bruce
I'll watch it tonight, but I think I've figured it out; specifically, the EP implies space-time is curved by the presence of mass/energy (and this is independent of the need to express the laws of physics in a coordinate independent way via tensors). AG
Here's my reasoning regarding the EP; if an observer is in a box subject to uniform acceleration, a beam of light starting on the extreme left side (moving transverse or perpendicular to the acceleration vector), will hit a lower point on the right side, showing that uniform acceleration results in curved paths in space-time. But if this result is identical to gravity, locally, it means that curved paths in space-time are produced by, or are equivalent to gravity.
BUT gravity is only observed in the presence of mass/energy. ERGO, the EP implies mass/energy curves space-time. AG
For Bruce; so far I've gotten about two-thirds through Carroll's video. Will complete it this weekend. I sense a flaw in GR, suggested by the inclusion of G, the gravitational constant. How can a constant inferred from an approximate theory of gravity, Newton's Theory of Gravitation, be included in a presumed perfect theory of gravity, General Relativity? Don't you think something very subtle is awry here? AG
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On 7/11/2020 12:54 AM, Alan Grayson wrote:
On Tuesday, July 7, 2020 at 10:06:44 PM UTC-6, Alan Grayson wrote:
On Tuesday, July 7, 2020 at 8:50:50 PM UTC-6, Alan Grayson wrote:
On Tuesday, July 7, 2020 at 8:05:28 PM UTC-6, Bruce wrote:On Wed, Jul 1, 2020 at 4:18 PM Alan Grayson <agrays...@gmail.com> wrote:
How, exactly, is the Principle of Equivalence used by Einstein to develop GR? TIA, AG
This lecture by Sean Carroll should answer all your questions:
Bruce
I'll watch it tonight, but I think I've figured it out; specifically, the EP implies space-time is curved by the presence of mass/energy (and this is independent of the need to express the laws of physics in a coordinate independent way via tensors). AG
Here's my reasoning regarding the EP; if an observer is in a box subject to uniform acceleration, a beam of light starting on the extreme left side (moving transverse or perpendicular to the acceleration vector), will hit a lower point on the right side, showing that uniform acceleration results in curved paths in space-time. But if this result is identical to gravity, locally, it means that curved paths in space-time are produced by, or are equivalent to gravity.
That makes no sense. You're saying that because curved paths can be produced two different ways then they must always be produced the second way.
BUT gravity is only observed in the presence of mass/energy. ERGO, the EP implies mass/energy curves space-time. AG
And that's not even true. Gravitational waves can propagate thru the vacuum. The Schwarzschild solution is for empty space. De Sitter space is an empty cosmos.
Brent
--
For Bruce; so far I've gotten about two-thirds through Carroll's video. Will complete it this weekend. I sense a flaw in GR, suggested by the inclusion of G, the gravitational constant. How can a constant inferred from an approximate theory of gravity, Newton's Theory of Gravitation, be included in a presumed perfect theory of gravity, General Relativity? Don't you think something very subtle is awry here? AG
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On Saturday, July 11, 2020 at 5:05:02 PM UTC-6, Brent wrote:
On 7/11/2020 12:54 AM, Alan Grayson wrote:
On Tuesday, July 7, 2020 at 10:06:44 PM UTC-6, Alan Grayson wrote:
On Tuesday, July 7, 2020 at 8:50:50 PM UTC-6, Alan Grayson wrote:
On Tuesday, July 7, 2020 at 8:05:28 PM UTC-6, Bruce wrote:On Wed, Jul 1, 2020 at 4:18 PM Alan Grayson <agrays...@gmail.com> wrote:
How, exactly, is the Principle of Equivalence used by Einstein to develop GR? TIA, AG
This lecture by Sean Carroll should answer all your questions:
Bruce
I'll watch it tonight, but I think I've figured it out; specifically, the EP implies space-time is curved by the presence of mass/energy (and this is independent of the need to express the laws of physics in a coordinate independent way via tensors). AG
Here's my reasoning regarding the EP; if an observer is in a box subject to uniform acceleration, a beam of light starting on the extreme left side (moving transverse or perpendicular to the acceleration vector), will hit a lower point on the right side, showing that uniform acceleration results in curved paths in space-time. But if this result is identical to gravity, locally, it means that curved paths in space-time are produced by, or are equivalent to gravity.
That makes no sense. You're saying that because curved paths can be produced two different ways then they must always be produced the second way.
BUT gravity is only observed in the presence of mass/energy. ERGO, the EP implies mass/energy curves space-time. AG
And that's not even true. Gravitational waves can propagate thru the vacuum. The Schwarzschild solution is for empty space. De Sitter space is an empty cosmos.Light can propagate through empty space, but it can't arise from nothing. Same presumably for gravitational waves. AG
On Saturday, July 11, 2020 at 5:05:02 PM UTC-6, Brent wrote:
On 7/11/2020 12:54 AM, Alan Grayson wrote:
On Tuesday, July 7, 2020 at 10:06:44 PM UTC-6, Alan Grayson wrote:
On Tuesday, July 7, 2020 at 8:50:50 PM UTC-6, Alan Grayson wrote:
On Tuesday, July 7, 2020 at 8:05:28 PM UTC-6, Bruce wrote:On Wed, Jul 1, 2020 at 4:18 PM Alan Grayson <agrays...@gmail.com> wrote:
How, exactly, is the Principle of Equivalence used by Einstein to develop GR? TIA, AG
This lecture by Sean Carroll should answer all your questions:
Bruce
I'll watch it tonight, but I think I've figured it out; specifically, the EP implies space-time is curved by the presence of mass/energy (and this is independent of the need to express the laws of physics in a coordinate independent way via tensors). AG
Here's my reasoning regarding the EP; if an observer is in a box subject to uniform acceleration, a beam of light starting on the extreme left side (moving transverse or perpendicular to the acceleration vector), will hit a lower point on the right side, showing that uniform acceleration results in curved paths in space-time. But if this result is identical to gravity, locally, it means that curved paths in space-time are produced by, or are equivalent to gravity.
That makes no sense. You're saying that because curved paths can be produced two different ways then they must always be produced the second way.
BUT gravity is only observed in the presence of mass/energy. ERGO, the EP implies mass/energy curves space-time. AG
And that's not even true. Gravitational waves can propagate thru the vacuum. The Schwarzschild solution is for empty space. De Sitter space is an empty cosmos.
Light can propagate through empty space, but it can't arise from nothing. Same presumably for gravitational waves. AG
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--since, in this case, we're dealing with SR, wherein space-time has no curvature? AG
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Can EM waves exist if there are no charges and currents? If you affirm, has this ever been observed? This result, if it is a result, is likely an artifact of the mathematics which has no basis in physical reality. Anyway, are you claiming that spacetime curvature can exist in the absence of matter/energy? Is this what the EP says? AG
I have not followed this thread much. I get the impression there is a lot of confusion.The equivalence principle states there is no distinguishing difference between a frame far away in flat spacetime and one in a region of spacetime that is curved so long as the frame is small in extent. In other words, it there is a curvature R and the dimensions of the frame are d then d << √R. This will mean that any test masses in this small frame will be on co-parallel geodesics and the local physics is no different than if you are on a frame in very distant flat spacetime. The converse of this then is that being on an accelerated frame is indistiguishable from being held fixed in a gravitational field. The surface of the Earth does that for us. Then comparing gravity with acceleration this way the implication is that inertial mass is equal to gravitational mass. The previous case indicates a way forwards to general relativity with local frames or patches that are meshed together in a coordinate atlas and transition function that define connection coefficients and curvature.
--since, in this case, we're dealing with SR, wherein space-time has no curvature? AG
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There can be because it's consistent with the equations. A black hole doesn't include any matter. General relativity is non-linear, that's why there can be non-flat cosmologies that contain no matter. Of course there may be some different, better theory in which spacetime can't be curved without matter...but it seems unlikely since we have good evidence that gravitational waves exist.
Brent
Yes, good evidence that gravitational waves exist, but as far I know they're always associated with material interactions such as collisions of black holes. In the case of EM waves, I'd be more receptive of your claim that they can exist independent of charges and/or currents, but as far as I know there's no evidence of that. AG
LC
On Monday, July 13, 2020 at 6:30:46 PM UTC-5, Alan Grayson wrote:
On Monday, July 13, 2020 at 5:19:30 PM UTC-6, Lawrence Crowell wrote:On Monday, July 13, 2020 at 4:42:24 PM UTC-5, Alan Grayson wrote:
On Monday, July 13, 2020 at 1:42:49 PM UTC-6, Alan Grayson wrote:
On Monday, July 13, 2020 at 11:57:50 AM UTC-6, Brent wrote:
On 7/12/2020 11:50 PM, Alan Grayson wrote:
There can be because it's consistent with the equations. A black hole doesn't include any matter. General relativity is non-linear, that's why there can be non-flat cosmologies that contain no matter. Of course there may be some different, better theory in which spacetime can't be curved without matter...but it seems unlikely since we have good evidence that gravitational waves exist.
Brent
Yes, good evidence that gravitational waves exist, but as far I know they're always associated with material interactions such as collisions of black holes. In the case of EM waves, I'd be more receptive of your claim that they can exist independent of charges and/or currents, but as far as I know there's no evidence of that. AG
But a collision of black holes does NOT involve matter. Black holes (as far as the theory goes) are purely geometric things, i.e. made of empty space.
Brent
How then does the BH at the center of our galaxy weigh in at 4 million solar masses? AG
It's measured by observing the rotation rates of stars near the galactic core, and not so small by comparison with other BH's at the center of galaxies, called Super Massive BH's. AG
It is unfortunately apparent that you are pretty highly confused by some of this. You need to sit down and read a comprehensive book or text on GR and related subjects. It is not going to be possible to clear this up with dozens of email posts.
LC
About the EP; I merely stated that it demonstrates that acceleration is locally indistinguishable from gravity, and then I stated what "locally" means. This is what Wiki and other sources say. Yet you say I am confused. How so? About masses of BH's, I watch documentaries which feature astrophysicists offering their opinions, and they uniformly claim that BH's have mass. How could it be otherwise if they're remnants of massive collapsed stars? Not one makes Brent's claim, that they're just geometric manifestations. AG
Black hole mass is a pure spacetime physics. There is no material stuff anyone can get their hands on. With the tortoise coordinate the distant observer might say the matter-fields that made of a black hole exist, but if one tried to reach them they always recede away. Black holes do not have mass in a standard sense, though they have an ADM mass defined by the curvature of spacetime.
LC
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On 7/14/2020 3:34 AM, Lawrence Crowell wrote:
On Monday, July 13, 2020 at 6:30:46 PM UTC-5, Alan Grayson wrote:
On Monday, July 13, 2020 at 5:19:30 PM UTC-6, Lawrence Crowell wrote:On Monday, July 13, 2020 at 4:42:24 PM UTC-5, Alan Grayson wrote:
On Monday, July 13, 2020 at 1:42:49 PM UTC-6, Alan Grayson wrote:
On Monday, July 13, 2020 at 11:57:50 AM UTC-6, Brent wrote:
On 7/12/2020 11:50 PM, Alan Grayson wrote:
There can be because it's consistent with the equations. A black hole doesn't include any matter. General relativity is non-linear, that's why there can be non-flat cosmologies that contain no matter. Of course there may be some different, better theory in which spacetime can't be curved without matter...but it seems unlikely since we have good evidence that gravitational waves exist.
Brent
Yes, good evidence that gravitational waves exist, but as far I know they're always associated with material interactions such as collisions of black holes. In the case of EM waves, I'd be more receptive of your claim that they can exist independent of charges and/or currents, but as far as I know there's no evidence of that. AG
But a collision of black holes does NOT involve matter. Black holes (as far as the theory goes) are purely geometric things, i.e. made of empty space.
Brent
How then does the BH at the center of our galaxy weigh in at 4 million solar masses? AG
It's measured by observing the rotation rates of stars near the galactic core, and not so small by comparison with other BH's at the center of galaxies, called Super Massive BH's. AG
It is unfortunately apparent that you are pretty highly confused by some of this. You need to sit down and read a comprehensive book or text on GR and related subjects. It is not going to be possible to clear this up with dozens of email posts.
LC
About the EP; I merely stated that it demonstrates that acceleration is locally indistinguishable from gravity, and then I stated what "locally" means. This is what Wiki and other sources say. Yet you say I am confused. How so? About masses of BH's, I watch documentaries which feature astrophysicists offering their opinions, and they uniformly claim that BH's have mass. How could it be otherwise if they're remnants of massive collapsed stars? Not one makes Brent's claim, that they're just geometric manifestations. AG
I didn't say they lacked mass. I said they lacked matter. Thus countering your assumption that gravity requires matter.
Brent
--
Black hole mass is a pure spacetime physics. There is no material stuff anyone can get their hands on. With the tortoise coordinate the distant observer might say the matter-fields that made of a black hole exist, but if one tried to reach them they always recede away. Black holes do not have mass in a standard sense, though they have an ADM mass defined by the curvature of spacetime.
LC
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On Tuesday, July 14, 2020 at 11:31:42 AM UTC-6, Brent wrote:
On 7/14/2020 3:34 AM, Lawrence Crowell wrote:
On Monday, July 13, 2020 at 6:30:46 PM UTC-5, Alan Grayson wrote:
On Monday, July 13, 2020 at 5:19:30 PM UTC-6, Lawrence Crowell wrote:On Monday, July 13, 2020 at 4:42:24 PM UTC-5, Alan Grayson wrote:
On Monday, July 13, 2020 at 1:42:49 PM UTC-6, Alan Grayson wrote:
On Monday, July 13, 2020 at 11:57:50 AM UTC-6, Brent wrote:
On 7/12/2020 11:50 PM, Alan Grayson wrote:
There can be because it's consistent with the equations. A black hole doesn't include any matter. General relativity is non-linear, that's why there can be non-flat cosmologies that contain no matter. Of course there may be some different, better theory in which spacetime can't be curved without matter...but it seems unlikely since we have good evidence that gravitational waves exist.
Brent
Yes, good evidence that gravitational waves exist, but as far I know they're always associated with material interactions such as collisions of black holes. In the case of EM waves, I'd be more receptive of your claim that they can exist independent of charges and/or currents, but as far as I know there's no evidence of that. AG
But a collision of black holes does NOT involve matter. Black holes (as far as the theory goes) are purely geometric things, i.e. made of empty space.
Brent
How then does the BH at the center of our galaxy weigh in at 4 million solar masses? AG
It's measured by observing the rotation rates of stars near the galactic core, and not so small by comparison with other BH's at the center of galaxies, called Super Massive BH's. AG
It is unfortunately apparent that you are pretty highly confused by some of this. You need to sit down and read a comprehensive book or text on GR and related subjects. It is not going to be possible to clear this up with dozens of email posts.
LC
About the EP; I merely stated that it demonstrates that acceleration is locally indistinguishable from gravity, and then I stated what "locally" means. This is what Wiki and other sources say. Yet you say I am confused. How so? About masses of BH's, I watch documentaries which feature astrophysicists offering their opinions, and they uniformly claim that BH's have mass. How could it be otherwise if they're remnants of massive collapsed stars? Not one makes Brent's claim, that they're just geometric manifestations. AG
I didn't say they lacked mass. I said they lacked matter. Thus countering your assumption that gravity requires matter.
Brent
I could have said that gravity requires mass/energy. What's the distinction between matter and mass? TIA, AG
> Can't fermions be considered "matter"? AG
"Thus, matter can be defined as everything composed of elementary fermions."
https://en.wikipedia.org/wiki/Matter
@philipthrift
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Gravitons do not escape from a BH, any more than can light. However, from the perspective of an outside observer all matter than went into a BH is on the surface above the event horizon, called the stretched horizon.LC
On Thursday, July 16, 2020 at 5:08:57 PM UTC-6, Lawrence Crowell wrote:Gravitons do not escape from a BH, any more than can light. However, from the perspective of an outside observer all matter than went into a BH is on the surface above the event horizon, called the stretched horizon.LCGravitons might not exist (and hence quantum gravity can't exist) But whatever the case, how can BH's interact gravitationally with objects beyond its event horizon? You say this doesn't happen. I don't understand your argument. AG
On Thursday, July 16, 2020 at 7:50:07 PM UTC-6, Alan Grayson wrote:
On Thursday, July 16, 2020 at 5:08:57 PM UTC-6, Lawrence Crowell wrote:Gravitons do not escape from a BH, any more than can light. However, from the perspective of an outside observer all matter than went into a BH is on the surface above the event horizon, called the stretched horizon.LCGravitons might not exist (and hence quantum gravity can't exist) But whatever the case, how can BH's interact gravitationally with objects beyond its event horizon? You say this doesn't happen. I don't understand your argument. AG
I may have identified the thousand pound gorilla in the room; the hypothetical force carrying particle of the quantum gravitating field, the graviton, which for BH's doesn't exert any force! AG
LC
The tortoise coordinates is found from the Schwarzschild metricds^2 = (1 - 2m/r)dt^2 - (1 - 2m/r)^{-1}dr^2 - r^2dΩ^2where for a signal leaving a point near the black hole with ds = 0 (null path) and propagating radially out, dΩ = 0, we have dt = dr/(1 - 2m/r) which then leads toT = t - t0 - 2m ln|r - 2m|.That is the tortoise coordinate. Please look this up to read further. I can't spend beaucoup time going over this for weeks to come.LC
On Saturday, July 18, 2020 at 6:18:28 AM UTC-6, Lawrence Crowell wrote:The tortoise coordinates is found from the Schwarzschild metricds^2 = (1 - 2m/r)dt^2 - (1 - 2m/r)^{-1}dr^2 - r^2dΩ^2where for a signal leaving a point near the black hole with ds = 0 (null path) and propagating radially out, dΩ = 0, we have dt = dr/(1 - 2m/r) which then leads toT = t - t0 - 2m ln|r - 2m|.That is the tortoise coordinate. Please look this up to read further. I can't spend beaucoup time going over this for weeks to come.LCYou don't have to. We're done. But you should IMO address Brent's objection, maybe on another thread. AG
On Saturday, July 18, 2020 at 6:31:23 AM UTC-6, Alan Grayson wrote:
On Saturday, July 18, 2020 at 6:18:28 AM UTC-6, Lawrence Crowell wrote:The tortoise coordinates is found from the Schwarzschild metricds^2 = (1 - 2m/r)dt^2 - (1 - 2m/r)^{-1}dr^2 - r^2dΩ^2where for a signal leaving a point near the black hole with ds = 0 (null path) and propagating radially out, dΩ = 0, we have dt = dr/(1 - 2m/r) which then leads toT = t - t0 - 2m ln|r - 2m|.That is the tortoise coordinate. Please look this up to read further. I can't spend beaucoup time going over this for weeks to come.LCYou don't have to. We're done. But you should IMO address Brent's objection, maybe on another thread. AGWhen it comes to GR, you're a genius; no question about it. I wouldn't want to waste your valuable time. But consider this; the Schwartzschild metric applies to NON-ROTATING masses. Do you really think a massive contracting star which forms a BH will be non-rotating? Obviously, it will be RAPIDLY rotating, like an ice skater who contracts her arms. Brent also had some substantive questions about your model. But I see you prefer your illusions than to address his objections. AG
Coordinates are not the basis of physics. Curvatures are covariant, while connections and coordinates are not. These can be imposed in many ways, similar to a gauge choice.LC
On Thursday, July 23, 2020 at 5:56:32 AM UTC-5 agrays...@gmail.com wrote:
On Saturday, July 18, 2020 at 6:31:23 AM UTC-6, Alan Grayson wrote:
On Saturday, July 18, 2020 at 6:18:28 AM UTC-6, Lawrence Crowell wrote:The tortoise coordinates is found from the Schwarzschild metric
ds^2 = (1 - 2m/r)dt^2 - (1 - 2m/r)^{-1}dr^2 - r^2dΩ^2
where for a signal leaving a point near the black hole with ds = 0 (null path) and propagating radially out, dΩ = 0, we have dt = dr/(1 - 2m/r) which then leads to
T = t - t0 - 2m ln|r - 2m|.
That is the tortoise coordinate. Please look this up to read further. I can't spend beaucoup time going over this for weeks to come.
LC
You don't have to. We're done. But you should IMO address Brent's objection, maybe on another thread. AG
When it comes to GR, you're a genius; no question about it. I wouldn't want to waste your valuable time. But consider this; the Schwartzschild metric applies to NON-ROTATING masses. Do you really think a massive contracting star which forms a BH will be non-rotating? Obviously, it will be RAPIDLY rotating, like an ice skater who contracts her arms. Brent also had some substantive questions about your model. But I see you prefer your illusions than to address his objections. AG
The result is similar, but more complex. The same calculation can be done for the Kerr solution. It is just a lot more complicated mathematically.
LC
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On Thursday, July 23, 2020 at 8:27:52 AM UTC-6, Lawrence Crowell wrote:Coordinates are not the basis of physics. Curvatures are covariant, while connections and coordinates are not. These can be imposed in many ways, similar to a gauge choice.
LC
That right; coordinates are not the basis of physics. That's why Einstein had to cast his GR equation in tensor form, so the laws of physics would be independent of coordinate systems. But you're asserting, or so it seems, that there is a unique coordinate system wherein the external gravitational effect of a BH can be calculated. This is what I object to. AG
On Thursday, July 23, 2020 at 6:49:44 AM UTC-5 agrays...@gmail.com wrote:
On Thursday, July 23, 2020 at 5:41:42 AM UTC-6, Lawrence Crowell wrote:On Thursday, July 23, 2020 at 5:56:32 AM UTC-5 agrays...@gmail.com wrote:
On Saturday, July 18, 2020 at 6:31:23 AM UTC-6, Alan Grayson wrote:
On Saturday, July 18, 2020 at 6:18:28 AM UTC-6, Lawrence Crowell wrote:The tortoise coordinates is found from the Schwarzschild metric
ds^2 = (1 - 2m/r)dt^2 - (1 - 2m/r)^{-1}dr^2 - r^2dΩ^2
where for a signal leaving a point near the black hole with ds = 0 (null path) and propagating radially out, dΩ = 0, we have dt = dr/(1 - 2m/r) which then leads to
T = t - t0 - 2m ln|r - 2m|.
That is the tortoise coordinate. Please look this up to read further. I can't spend beaucoup time going over this for weeks to come.
LC
You don't have to. We're done. But you should IMO address Brent's objection, maybe on another thread. AG
When it comes to GR, you're a genius; no question about it. I wouldn't want to waste your valuable time. But consider this; the Schwartzschild metric applies to NON-ROTATING masses. Do you really think a massive contracting star which forms a BH will be non-rotating? Obviously, it will be RAPIDLY rotating, like an ice skater who contracts her arms. Brent also had some substantive questions about your model. But I see you prefer your illusions than to address his objections. AG
The result is similar, but more complex. The same calculation can be done for the Kerr solution. It is just a lot more complicated mathematically.
LC
If you say so. In any event, the idea that an objectively existing gravitational field outside a BH should depend on the choice of a particular coordinate system, seems a non-starter. AG
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On 7/23/2020 4:41 AM, Lawrence Crowell wrote:
On Thursday, July 23, 2020 at 5:56:32 AM UTC-5 agrays...@gmail.com wrote:
On Saturday, July 18, 2020 at 6:31:23 AM UTC-6, Alan Grayson wrote:
On Saturday, July 18, 2020 at 6:18:28 AM UTC-6, Lawrence Crowell wrote:The tortoise coordinates is found from the Schwarzschild metric
ds^2 = (1 - 2m/r)dt^2 - (1 - 2m/r)^{-1}dr^2 - r^2dΩ^2
where for a signal leaving a point near the black hole with ds = 0 (null path) and propagating radially out, dΩ = 0, we have dt = dr/(1 - 2m/r) which then leads to
T = t - t0 - 2m ln|r - 2m|.
That is the tortoise coordinate. Please look this up to read further. I can't spend beaucoup time going over this for weeks to come.
LC
You don't have to. We're done. But you should IMO address Brent's objection, maybe on another thread. AG
I don't know what objection you're referring to. LC is just showing why it takes a distant observer forever to see an infalling object reach the event horizon of a black hole.
Brent
--
When it comes to GR, you're a genius; no question about it. I wouldn't want to waste your valuable time. But consider this; the Schwartzschild metric applies to NON-ROTATING masses. Do you really think a massive contracting star which forms a BH will be non-rotating? Obviously, it will be RAPIDLY rotating, like an ice skater who contracts her arms. Brent also had some substantive questions about your model. But I see you prefer your illusions than to address his objections. AG
The result is similar, but more complex. The same calculation can be done for the Kerr solution. It is just a lot more complicated mathematically.
LC
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On Thursday, July 23, 2020 at 11:59:59 AM UTC-6, Brent wrote:
On 7/23/2020 4:41 AM, Lawrence Crowell wrote:
On Thursday, July 23, 2020 at 5:56:32 AM UTC-5 agrays...@gmail.com wrote:
On Saturday, July 18, 2020 at 6:31:23 AM UTC-6, Alan Grayson wrote:
On Saturday, July 18, 2020 at 6:18:28 AM UTC-6, Lawrence Crowell wrote:The tortoise coordinates is found from the Schwarzschild metric
ds^2 = (1 - 2m/r)dt^2 - (1 - 2m/r)^{-1}dr^2 - r^2dΩ^2
where for a signal leaving a point near the black hole with ds = 0 (null path) and propagating radially out, dΩ = 0, we have dt = dr/(1 - 2m/r) which then leads to
T = t - t0 - 2m ln|r - 2m|.
That is the tortoise coordinate. Please look this up to read further. I can't spend beaucoup time going over this for weeks to come.
LC
You don't have to. We're done. But you should IMO address Brent's objection, maybe on another thread. AG
I don't know what objection you're referring to. LC is just showing why it takes a distant observer forever to see an infalling object reach the event horizon of a black hole.
BrentYour words:I wonder about the use of cicumlocutions like "from the perspective of an outside observer". In special relativity it it is often said that a moving object will looked shortened along the direction of motion. But as Terrell pointed out that's not at all how they look. It is more accurate to say that measuring a moving a object will show that it is shortened along the direction of motion; the difference being that the measurement corrects for the fact that you want the difference in arrival time of photons that left the ends of the object at the same time (an ill defined concept), instead of the image formed by photons that arrived at the same time. But then I think, why not correct for the Lorentz contraction too in the measurement and arrive at what we might call "the proper length". That's just as "measured" as either of the other two.
By the same reasoning, you're really saying the visual impression of a distant observer is that infalling stuff appears to be on the surface of the event horizon. Which is because it takes forever for photons to reach him. But why should he be so naive. He knows what he's seeing is arbitrarily far in his past; so what he should be said to "measure" or "calculate" is that the stuff has already been annihilated at the "singularity" in his reference frame.-----------------------------------------------------I forget why LC brought up this particular coordinate system. He had some point in response to a comment I made. I'll have to review my comments; maybe that the gravitational field due to a BH, external to the event horizon, has an objective reality. AG
On Thursday, July 23, 2020 at 11:59:59 AM UTC-6, Brent wrote:
On 7/23/2020 4:41 AM, Lawrence Crowell wrote:
On Thursday, July 23, 2020 at 5:56:32 AM UTC-5 agrays...@gmail.com wrote:
On Saturday, July 18, 2020 at 6:31:23 AM UTC-6, Alan Grayson wrote:
On Saturday, July 18, 2020 at 6:18:28 AM UTC-6, Lawrence Crowell wrote:The tortoise coordinates is found from the Schwarzschild metric
ds^2 = (1 - 2m/r)dt^2 - (1 - 2m/r)^{-1}dr^2 - r^2dΩ^2
where for a signal leaving a point near the black hole with ds = 0 (null path) and propagating radially out, dΩ = 0, we have dt = dr/(1 - 2m/r) which then leads to
T = t - t0 - 2m ln|r - 2m|.
That is the tortoise coordinate. Please look this up to read further. I can't spend beaucoup time going over this for weeks to come.
LC
You don't have to. We're done. But you should IMO address Brent's objection, maybe on another thread. AG
I don't know what objection you're referring to. LC is just showing why it takes a distant observer forever to see an infalling object reach the event horizon of a black hole.
Brent
Your words:
I wonder about the use of cicumlocutions like "from the perspective of an outside observer". In special relativity it it is often said that a moving object will looked shortened along the direction of motion. But as Terrell pointed out that's not at all how they look. It is more accurate to say that measuring a moving a object will show that it is shortened along the direction of motion; the difference being that the measurement corrects for the fact that you want the difference in arrival time of photons that left the ends of the object at the same time (an ill defined concept), instead of the image formed by photons that arrived at the same time. But then I think, why not correct for the Lorentz contraction too in the measurement and arrive at what we might call "the proper length". That's just as "measured" as either of the other two.
By the same reasoning, you're really saying the visual impression of a distant observer is that infalling stuff appears to be on the surface of the event horizon. Which is because it takes forever for photons to reach him. But why should he be so naive. He knows what he's seeing is arbitrarily far in his past; so what he should be said to "measure" or "calculate" is that the stuff has already been annihilated at the "singularity" in his reference frame.
-----------------------------------------------------
I forget why LC brought up this particular coordinate system. He had some point in response to a comment I made. I'll have to review my comments; maybe that the gravitational field due to a BH, external to the event horizon, has an objective reality. AG