Hi Philip, Hi Bruce, and possible others,
Let us write f_n for the function from N to N computed by nth expression.Now, the function g defined by g(n) = f_n(n) + 1 is computable, and is defined on all N. So it is a computable function from N to N. It is computable because it each f_n is computable, “+ 1” is computable, and, vy our hypothesis it get all and only all computable functions from N to N.But then, g has have itself an expression in that universal language, of course. There there is a number k such that g = f_k. OK?But then we get that g_k, applied to k has to give f_k(k), as g = f_k, and f_k(k) + 1, by definition of g.
On 31 May 2020, at 07:44, Bruce Kellett <bhkel...@gmail.com> wrote:On Sun, May 31, 2020 at 2:26 AM Bruno Marchal <mar...@ulb.ac.be> wrote:Let us write f_n for the function from N to N computed by nth expression.Now, the function g defined by g(n) = f_n(n) + 1 is computable, and is defined on all N. So it is a computable function from N to N. It is computable because it each f_n is computable, “+ 1” is computable, and, vy our hypothesis it get all and only all computable functions from N to N.But then, g has have itself an expression in that universal language, of course. There there is a number k such that g = f_k. OK?But then we get that g_k, applied to k has to give f_k(k), as g = f_k, and f_k(k) + 1, by definition of g.That is a fairly elementary blunder. g_k
applied to k, g_k(k) = f_n(k)+1,
by definition of g_k.
You do not get to change the function from f_n to f_k in the expression.
It is only the argument that changes: in other words, f_n(n) becomes f_n(k).
So you are talking nonsense.
BruceSo f_k(k) = f_k(k) +1.And f_k(k) has to be number, given that we were enumerating functions from N to N. So we can subtract f_k(k) on both sides, and we get 0 = 1. CQFD.
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On 31 May 2020, at 07:44, Bruce Kellett <bhkel...@gmail.com> wrote:On Sun, May 31, 2020 at 2:26 AM Bruno Marchal <mar...@ulb.ac.be> wrote:Let us write f_n for the function from N to N computed by nth expression.Now, the function g defined by g(n) = f_n(n) + 1 is computable, and is defined on all N. So it is a computable function from N to N. It is computable because it each f_n is computable, “+ 1” is computable, and, vy our hypothesis it get all and only all computable functions from N to N.But then, g has have itself an expression in that universal language, of course. There there is a number k such that g = f_k. OK?But then we get that g_k, applied to k has to give f_k(k), as g = f_k, and f_k(k) + 1, by definition of g.That is a fairly elementary blunder. g_kWhat is g_k?
The only enumeration here is the f_k, then we have define a precise, single, function g such thatg(n) = f_n(n) + 1. (f_n(n) is the diagonal term, you can see this by making the table (the infinite matrice) with the number in the top row, and the f_i in a column):0 1 2 3 ...f_0 f_0(0) f_0(1) f_0(2) f_0(3)f_1 f_1(0) f_1(1) f_1(2) f_1(3)f_2 f_2(0) f_2(1) f_2(2) f_2(3)…Here the underlining means “+1”.applied to k, g_k(k) = f_n(k)+1,There are no g_k.
g is the function defined by diagonalisation. g(x) = f_x(x) + 1, that g(0) = f_0(0) + 1, g(1) = f_1(1) + 1, g(2) = f_2(2) + 1, ...
by definition of g_k.The only enumeration was the enumeration of the functions f_kYou do not get to change the function from f_n to f_k in the expression.We do.It is only the argument that changes: in other words, f_n(n) becomes f_n(k).This makes no sense. What is g(2) ? f_n(2) + 1 ? What is n then?
On 31 May 2020, at 10:08, Bruce Kellett <bhkel...@gmail.com> wrote:
On Sun, May 31, 2020 at 5:21 PM Bruno Marchal <mar...@ulb.ac.be> wrote:
On 31 May 2020, at 07:44, Bruce Kellett <bhkel...@gmail.com> wrote:On Sun, May 31, 2020 at 2:26 AM Bruno Marchal <mar...@ulb.ac.be> wrote:Let us write f_n for the function from N to N computed by nth expression.Now, the function g defined by g(n) = f_n(n) + 1 is computable, and is defined on all N. So it is a computable function from N to N. It is computable because it each f_n is computable, “+ 1” is computable, and, vy our hypothesis it get all and only all computable functions from N to N.But then, g has have itself an expression in that universal language, of course. There there is a number k such that g = f_k. OK?But then we get that g_k, applied to k has to give f_k(k), as g = f_k, and f_k(k) + 1, by definition of g.That is a fairly elementary blunder. g_kWhat is g_k?
That is your notation: "But then we get that g_k, applied to k has to give f_k(k),”
The only enumeration here is the f_k, then we have define a precise, single, function g such thatg(n) = f_n(n) + 1. (f_n(n) is the diagonal term, you can see this by making the table (the infinite matrice) with the number in the top row, and the f_i in a column):0 1 2 3 ...f_0 f_0(0) f_0(1) f_0(2) f_0(3)f_1 f_1(0) f_1(1) f_1(2) f_1(3)f_2 f_2(0) f_2(1) f_2(2) f_2(3)…Here the underlining means “+1”.applied to k, g_k(k) = f_n(k)+1,There are no g_k.You defined g_k!! g_k applied to k is f_k(k), and that is your error.
g is the function defined by diagonalisation. g(x) = f_x(x) + 1, that g(0) = f_0(0) + 1, g(1) = f_1(1) + 1, g(2) = f_2(2) + 1, ...But that is not what you said before.
by definition of g_k.The only enumeration was the enumeration of the functions f_kYou do not get to change the function from f_n to f_k in the expression.We do.It is only the argument that changes: in other words, f_n(n) becomes f_n(k).This makes no sense. What is g(2) ? f_n(2) + 1 ? What is n then?n is the number of the function in the ordered list of all functions from N to N. Adding 1 to f_n(n) gives a different function. Diagonalization does not help you here.
So g(n) = f_n(n)+1 is a different function.
It is NOT f_n() with some different argument. So your attempt to make them the same function is invalid.
BruceSo you are talking nonsense.You miss the diagonal. Read again.Bruno
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On 31 May 2020, at 10:08, Bruce Kellett <bhkel...@gmail.com> wrote:That is your notation: "But then we get that g_k, applied to k has to give f_k(k),”That was a typo error. You need to read “g applied to k”. Sorry. But you should have just ask “what is g_k?”.I mean it is not a blunder, but a typo error (probably among many). The typo error is detectable from just the few words which go after.
On Sun, May 31, 2020 at 2:26 AM Bruno Marchal <mar...@ulb.ac.be> wrote:
Let us write f_n for the function from N to N computed by nth expression.
Now, the function g defined by g(n) = f_n(n) + 1 is computable, and is defined on all N. So it is a computable function from N to N. It is computable because it each f_n is computable, “+ 1” is computable, and, vy our hypothesis it get all and only all computable functions from N to N.
But then, g has have itself an expression in that universal language, of course. There there is a number k such that g = f_k. OK?
But then we get that g_k, applied to k has to give f_k(k), as g = f_k, and f_k(k) + 1, by definition of g.
That is a fairly elementary blunder. g_k applied to k, g_k(k) = f_n(k)+1, by definition of g_k. You do not get to change the function from f_n to f_k in the expression. It is only the argument that changes: in other words, f_n(n) becomes f_n(k). So you are talking nonsense.
Bruce
So f_k(k) = f_k(k) +1.
And f_k(k) has to be number, given that we were enumerating functions from N to N. So we can subtract f_k(k) on both sides, and we get 0 = 1. CQFD.
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On 5/30/2020 10:44 PM, Bruce Kellett wrote:
On Sun, May 31, 2020 at 2:26 AM Bruno Marchal <mar...@ulb.ac.be> wrote:
Let us write f_n for the function from N to N computed by nth expression.
Now, the function g defined by g(n) = f_n(n) + 1 is computable, and is defined on all N. So it is a computable function from N to N. It is computable because it each f_n is computable, “+ 1” is computable, and, vy our hypothesis it get all and only all computable functions from N to N.
But then, g has have itself an expression in that universal language, of course. There there is a number k such that g = f_k. OK?
But then we get that g_k, applied to k has to give f_k(k), as g = f_k, and f_k(k) + 1, by definition of g.
That is a fairly elementary blunder. g_k applied to k, g_k(k) = f_n(k)+1, by definition of g_k. You do not get to change the function from f_n to f_k in the expression. It is only the argument that changes: in other words, f_n(n) becomes f_n(k). So you are talking nonsense.
No, I think that's OK. It's a straight substitution n->k. The trick is that g(n) is not some well defined specific function because n has infinite range. So none of this works in a finite world. But it's not surprising that there is incompleteness in an infinite theory.
Bruce
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On 5/31/2020 3:23 PM, Bruce Kellett wrote:
On Mon, Jun 1, 2020 at 3:12 AM 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 5/30/2020 10:44 PM, Bruce Kellett wrote:
On Sun, May 31, 2020 at 2:26 AM Bruno Marchal <mar...@ulb.ac.be> wrote:
Let us write f_n for the function from N to N computed by nth expression.
Now, the function g defined by g(n) = f_n(n) + 1 is computable, and is defined on all N. So it is a computable function from N to N. It is computable because it each f_n is computable, “+ 1” is computable, and, vy our hypothesis it get all and only all computable functions from N to N.
But then, g has have itself an expression in that universal language, of course. There there is a number k such that g = f_k. OK?
But then we get that g_k, applied to k has to give f_k(k), as g = f_k, and f_k(k) + 1, by definition of g.
That is a fairly elementary blunder. g_k applied to k, g_k(k) = f_n(k)+1, by definition of g_k. You do not get to change the function from f_n to f_k in the expression. It is only the argument that changes: in other words, f_n(n) becomes f_n(k). So you are talking nonsense.
No, I think that's OK. It's a straight substitution n->k. The trick is that g(n) is not some well defined specific function because n has infinite range. So none of this works in a finite world. But it's not surprising that there is incompleteness in an infinite theory.
Yes, I had misunderstood what g(n) was supposed to be -- it is simply a representation of the diagonal elements of the array, plus 1. But Bruno's attempt to use the diagonal argument here fails, because he has to show that f_n(n)+1 is not contained in the infinite list. He has failed to do this.
All computable functions are in the list ex hypothesi.
--
Bruce
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On 5/31/2020 3:49 PM, Bruce Kellett wrote:
On Mon, Jun 1, 2020 at 8:31 AM 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 5/31/2020 3:23 PM, Bruce Kellett wrote:
On Mon, Jun 1, 2020 at 3:12 AM 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 5/30/2020 10:44 PM, Bruce Kellett wrote:
On Sun, May 31, 2020 at 2:26 AM Bruno Marchal <mar...@ulb.ac.be> wrote:
Let us write f_n for the function from N to N computed by nth expression.
Now, the function g defined by g(n) = f_n(n) + 1 is computable, and is defined on all N. So it is a computable function from N to N. It is computable because it each f_n is computable, “+ 1” is computable, and, vy our hypothesis it get all and only all computable functions from N to N.
But then, g has have itself an expression in that universal language, of course. There there is a number k such that g = f_k. OK?
But then we get that g_k, applied to k has to give f_k(k), as g = f_k, and f_k(k) + 1, by definition of g.
That is a fairly elementary blunder. g_k applied to k, g_k(k) = f_n(k)+1, by definition of g_k. You do not get to change the function from f_n to f_k in the expression. It is only the argument that changes: in other words, f_n(n) becomes f_n(k). So you are talking nonsense.
No, I think that's OK. It's a straight substitution n->k. The trick is that g(n) is not some well defined specific function because n has infinite range. So none of this works in a finite world. But it's not surprising that there is incompleteness in an infinite theory.
Yes, I had misunderstood what g(n) was supposed to be -- it is simply a representation of the diagonal elements of the array, plus 1. But Bruno's attempt to use the diagonal argument here fails, because he has to show that f_n(n)+1 is not contained in the infinite list. He has failed to do this.
All computable functions are in the list ex hypothesi.
That is what the diagonal argument is all about: you hypothesize that all bit strings (for example) are in your infinite list. Then you flip the diagonal bit of each string and form a new string from all the diagonal elements. And lo, that new string is not in the initial list. Therefore your hypothesis that all bit strings are in the list is disproven.
Bruno has attempted toride to glory on this argument, and has failed miserably!
That's a general problem with reductio arguments. When you get to end you don't know which premise was wrong. Bruno, isn't changing the hypothetical list though, so he's saying the premise that you can order the total functions is wrong. You can order the functions (say lexigraphically) but you can't know which are total.
ISTM the result, that there's an incompleteness theorem for the set of all functions, is quite intuitive. But Bruno seems to be saying this is all finitist because he doesn't assum and axiom of infinity. Yet the "diagonalization" doesn't work in a finite world.
On Mon, Jun 1, 2020 at 9:05 AM 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 5/31/2020 3:49 PM, Bruce Kellett wrote:
On Mon, Jun 1, 2020 at 8:31 AM 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 5/31/2020 3:23 PM, Bruce Kellett wrote:
On Mon, Jun 1, 2020 at 3:12 AM 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 5/30/2020 10:44 PM, Bruce Kellett wrote:
On Sun, May 31, 2020 at 2:26 AM Bruno Marchal <mar...@ulb.ac.be> wrote:
Let us write f_n for the function from N to N computed by nth expression.
Now, the function g defined by g(n) = f_n(n) + 1 is computable, and is defined on all N. So it is a computable function from N to N. It is computable because it each f_n is computable, “+ 1” is computable, and, vy our hypothesis it get all and only all computable functions from N to N.
But then, g has have itself an expression in that universal language, of course. There there is a number k such that g = f_k. OK?
But then we get that g_k, applied to k has to give f_k(k), as g = f_k, and f_k(k) + 1, by definition of g.
That is a fairly elementary blunder. g_k applied to k, g_k(k) = f_n(k)+1, by definition of g_k. You do not get to change the function from f_n to f_k in the expression. It is only the argument that changes: in other words, f_n(n) becomes f_n(k). So you are talking nonsense.
No, I think that's OK. It's a straight substitution n->k. The trick is that g(n) is not some well defined specific function because n has infinite range. So none of this works in a finite world. But it's not surprising that there is incompleteness in an infinite theory.
Yes, I had misunderstood what g(n) was supposed to be -- it is simply a representation of the diagonal elements of the array, plus 1. But Bruno's attempt to use the diagonal argument here fails, because he has to show that f_n(n)+1 is not contained in the infinite list. He has failed to do this.
All computable functions are in the list ex hypothesi.
That is what the diagonal argument is all about: you hypothesize that all bit strings (for example) are in your infinite list. Then you flip the diagonal bit of each string and form a new string from all the diagonal elements. And lo, that new string is not in the initial list. Therefore your hypothesis that all bit strings are in the list is disproven.
Bruno has attempted toride to glory on this argument, and has failed miserably!
That's a general problem with reductio arguments. When you get to end you don't know which premise was wrong. Bruno, isn't changing the hypothetical list though, so he's saying the premise that you can order the total functions is wrong. You can order the functions (say lexigraphically) but you can't know which are total.
ISTM the result, that there's an incompleteness theorem for the set of all functions, is quite intuitive. But Bruno seems to be saying this is all finitist because he doesn't assum and axiom of infinity. Yet the "diagonalization" doesn't work in a finite world.
Take all bit strings of length N (finite) and apply the diagonal argument. The string resulting from putting all the flipped diagonal bits together is not in the original list, contradicting the assumption that the list is complete.
Of course, the list of all strings of length N contains more than N elements, so the diagonal argument does not apply. The set of all strings of infinite length is certainly infinite, so one might work the diagonal argument there -- if one doesn't worry too much about cardinality issues......
I think Bruno should rephrase his argument -- it might be sensible, but as presented it was clearly invalid.
Bruce
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Bruce
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On 1 Jun 2020, at 00:23, Bruce Kellett <bhkel...@gmail.com> wrote:On Mon, Jun 1, 2020 at 3:12 AM 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:On 5/30/2020 10:44 PM, Bruce Kellett wrote:
On Sun, May 31, 2020 at 2:26 AM Bruno Marchal <mar...@ulb.ac.be> wrote:
Let us write f_n for the function from N to N computed by nth expression.
Now, the function g defined by g(n) = f_n(n) + 1 is computable, and is defined on all N. So it is a computable function from N to N. It is computable because it each f_n is computable, “+ 1” is computable, and, vy our hypothesis it get all and only all computable functions from N to N.
But then, g has have itself an expression in that universal language, of course. There there is a number k such that g = f_k. OK?
But then we get that g_k, applied to k has to give f_k(k), as g = f_k, and f_k(k) + 1, by definition of g.
That is a fairly elementary blunder. g_k applied to k, g_k(k) = f_n(k)+1, by definition of g_k. You do not get to change the function from f_n to f_k in the expression. It is only the argument that changes: in other words, f_n(n) becomes f_n(k). So you are talking nonsense.
No, I think that's OK. It's a straight substitution n->k. The trick is that g(n) is not some well defined specific function because n has infinite range. So none of this works in a finite world. But it's not surprising that there is incompleteness in an infinite theory.Yes, I had misunderstood what g(n) was supposed to be -- it is simply a representation of the diagonal elements of the array, plus 1. But Bruno's attempt to use the diagonal argument here fails, because he has to show that f_n(n)+1 is not contained in the infinite list. He has failed to do this.Where?
I repeat the argument. If f_n is an enumeration of *al*l computable functions from N to N, then we can define the function g by saying that on each n in N, g(n) = f_n(n) + 1. (Or if you prefer g = [n](f_n(n) + 1) if you dislike (like me) to use f(x) to describe a function. But most people fear the lambda notation ([n]), so I will use the secondary usual denotation of function, with the implicit meaning that x or n are the variable/input.But now we have a contradiction if we assume f_n mechanically (recursively, computably) enumerable.In that case g is a computable defined on all n in N, and thus has to be in the enumeration of all computable function f_n. That means that it exists a number k such g is f_k, but then:g(k) = f_k(k) (by g being a function computable from N to N)
It took a while for me to get to this. The formula f_k(k) = f(k)+1 and g such that you get 0 = 1 appears to be the contradiction one gets with the enumeration of all Gödel numbers. This illustrates in Gödel's first theorem that no axiomatic system can determine its consistency.
I am not sure about the claims with respect to the ontology of mathematics.
Gödel made statements about how his theorems indicated there is an objective reality to mathematics. I do not disagree with mathematics as objective, but on the other hand I am not sure this is a clear demonstration of that.
The objective or epistemological nature of mathematics is something we endlessly debate.
On 1 Jun 2020, at 12:37, Bruce Kellett <bhkel...@gmail.com> wrote:On Mon, Jun 1, 2020 at 7:08 PM Bruno Marchal <mar...@ulb.ac.be> wrote:On 1 Jun 2020, at 00:23, Bruce Kellett <bhkel...@gmail.com> wrote:On Mon, Jun 1, 2020 at 3:12 AM 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:On 5/30/2020 10:44 PM, Bruce Kellett wrote:
On Sun, May 31, 2020 at 2:26 AM Bruno Marchal <mar...@ulb.ac.be> wrote:
Let us write f_n for the function from N to N computed by nth expression.
Now, the function g defined by g(n) = f_n(n) + 1 is computable, and is defined on all N. So it is a computable function from N to N. It is computable because it each f_n is computable, “+ 1” is computable, and, vy our hypothesis it get all and only all computable functions from N to N.
But then, g has have itself an expression in that universal language, of course. There there is a number k such that g = f_k. OK?
But then we get that g_k, applied to k has to give f_k(k), as g = f_k, and f_k(k) + 1, by definition of g.
That is a fairly elementary blunder. g_k applied to k, g_k(k) = f_n(k)+1, by definition of g_k. You do not get to change the function from f_n to f_k in the expression. It is only the argument that changes: in other words, f_n(n) becomes f_n(k). So you are talking nonsense.
No, I think that's OK. It's a straight substitution n->k. The trick is that g(n) is not some well defined specific function because n has infinite range. So none of this works in a finite world. But it's not surprising that there is incompleteness in an infinite theory.Yes, I had misunderstood what g(n) was supposed to be -- it is simply a representation of the diagonal elements of the array, plus 1. But Bruno's attempt to use the diagonal argument here fails, because he has to show that f_n(n)+1 is not contained in the infinite list. He has failed to do this.Where?I can't show where you are not doing something!I repeat the argument. If f_n is an enumeration of *al*l computable functions from N to N, then we can define the function g by saying that on each n in N, g(n) = f_n(n) + 1. (Or if you prefer g = [n](f_n(n) + 1) if you dislike (like me) to use f(x) to describe a function. But most people fear the lambda notation ([n]), so I will use the secondary usual denotation of function, with the implicit meaning that x or n are the variable/input.But now we have a contradiction if we assume f_n mechanically (recursively, computably) enumerable.In that case g is a computable defined on all n in N, and thus has to be in the enumeration of all computable function f_n. That means that it exists a number k such g is f_k, but then:g(k) = f_k(k) (by g being a function computable from N to N)But there is no need for this computable number to lie on the diagonal. It could well be f_k(x), for x!=k.
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On 2 Jun 2020, at 02:54, Lawrence Crowell <goldenfield...@gmail.com> wrote:This can be thought of as Turing machine computation. The undecidability is a sort of epistemic horizon. We can make these functions a state and measurement, and the 0 = 1 result when an axiomatic system is set to enumerate all its Gödel numbers, or what happens with a universal Turing machine, can be modeled as a function for a state and measurement. The incompleteness result is equivalent to a form of uncertainty in measurements.
The function is a pairing that is a bracket structure and this as a diagonalization leads to a form of g_n(n) = f(n) + 1 and 0 = 1.
This is a part of my practical interest in this. This may have some impact on the nature of quantum computation as well.
The modal logic aspects come from the Gödel second theorem that for a proposition P then NOT-Prove (gn(P) ↔ P is TRUE. If B(x) is a probability predicate, here B = Bew, then for True(B(x) → x) we can let D(x) be B(x) → x and the diagonal result gives us True C↔ D(gn(C)) and True C ↔ (B(gn(x)) → x). From this we can get Löb’s theorem.
The probability predicate serves as a meaning of “necessarily” and Löb’s theorem as a statement of modal logic can be found.
The Löb’s theorem has been said to be a from of sematic structure. With quantum mechanics and my work with the unprovability of any global solution system for all p-adic sets this may have some curious connection.
In particular with gravitation and the measurement problem where nonlinearity enters in. This suggests the “white noise” structure of quantum mechanics gives way to sort of pink noise or a process that is not purely random in a Markovian sense. This does appear to happen with large quantized systems with molecules on up to biology etc. My work with quantum hair on black holes suggests a sort of dualism with the UV physics of quantum gravitation and the IR physics at low energy as(UV physics of gravitation) = (IR physics of fields and matter),which is a way of writing the Einstein field equation.
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On 6/2/2020 2:49 AM, Bruno Marchal wrote:
>> On 1 Jun 2020, at 22:43, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>>
>>
>>
>> On 6/1/2020 2:08 AM, Bruno Marchal wrote:
>>> Brent suggest that we might recover completeness by restricting N to a finite domain. That is correct, because all finite function are computable, but then, we have incompleteness directly with respect to the computable functions, even limited on finite but arbitrary domain. In fact, that moves makes the computer simply vanishing, and it makes Mechanism not even definable or expressible.
>> That's going to come as a big shock to IBM stockholders.
>
> Why? On the contrary. IBM bets on universal machine
No, they bet only on finite machines, and they will be very surprised to
hear that they have vanished.
Brent
On 6/2/2020 2:49 AM, Bruno Marchal wrote:
>> On 1 Jun 2020, at 22:43, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>>
>>
>>
>> On 6/1/2020 2:08 AM, Bruno Marchal wrote:
>>> Brent suggest that we might recover completeness by restricting N to a finite domain. That is correct, because all finite function are computable, but then, we have incompleteness directly with respect to the computable functions, even limited on finite but arbitrary domain. In fact, that moves makes the computer simply vanishing, and it makes Mechanism not even definable or expressible.
>> That's going to come as a big shock to IBM stockholders.
>
> Why? On the contrary. IBM bets on universal machine
No, they bet only on finite machines, and they will be very surprised to
hear that they have vanished.
Brent
For the most part computers are meant to run various algorithms that solve some restricted set of problems, say business applications. We use them largely as tools.LC
On Tuesday, June 2, 2020 at 12:34:37 PM UTC-5, Brent wrote:
On 6/2/2020 2:49 AM, Bruno Marchal wrote:
>> On 1 Jun 2020, at 22:43, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>>
>>
>>
>> On 6/1/2020 2:08 AM, Bruno Marchal wrote:
>>> Brent suggest that we might recover completeness by restricting N to a finite domain. That is correct, because all finite function are computable, but then, we have incompleteness directly with respect to the computable functions, even limited on finite but arbitrary domain. In fact, that moves makes the computer simply vanishing, and it makes Mechanism not even definable or expressible.
>> That's going to come as a big shock to IBM stockholders.
>
> Why? On the contrary. IBM bets on universal machine
No, they bet only on finite machines, and they will be very surprised to
hear that they have vanished.
Brent
For the most part computers are meant to run various algorithms that solve some restricted set of problems, say business applications. We use them largely as tools.
--
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Brent
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@philipthrift
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On 3 Jun 2020, at 21:47, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 6/3/2020 3:26 AM, Lawrence Crowell wrote:
On Tuesday, June 2, 2020 at 12:34:37 PM UTC-5, Brent wrote:
On 6/2/2020 2:49 AM, Bruno Marchal wrote:
>> On 1 Jun 2020, at 22:43, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>>
>>
>>
>> On 6/1/2020 2:08 AM, Bruno Marchal wrote:
>>> Brent suggest that we might recover completeness by restricting N to a finite domain. That is correct, because all finite function are computable, but then, we have incompleteness directly with respect to the computable functions, even limited on finite but arbitrary domain. In fact, that moves makes the computer simply vanishing, and it makes Mechanism not even definable or expressible.
>> That's going to come as a big shock to IBM stockholders.
>
> Why? On the contrary. IBM bets on universal machine
No, they bet only on finite machines, and they will be very surprised to
hear that they have vanished.
Brent
For the most part computers are meant to run various algorithms that solve some restricted set of problems, say business applications. We use them largely as tools.
Mathematics is largely a tool. My pure mathematics friends over on math-fun seem to have most of their fun on Mathematica.
Of course, this is close to Aristotelian theology. It assumes that there is something which is not mathematical in some reality. A platonism or a pythegaorean think that he physical universe is but a tool, invented by the numbers to figure out what happens, and what is real.
But once you grasp that all computations exists in arithmetic (or more exactly, that they are enabled by the arithmetical true relations), even without Mechanism, the charge are reversed. It is those who claim (in metaphysics, not in physics) that there is a primitive universe who have the task to provide evidence.
I have given the way to test this, and, thanks to QM, we can say that there are not yet any evidence found for a primitive physical universe. On the contrary, nature seems to obey exactly to what is needed for mechanism to be true.
Then, if we assume furthermore Mechanism, there is no more choice in this matter. Physics cannot be the fundamental science, it reduces to arithmetic (or any model of any Turing equivalent machinery) “seen-from inside”.
Bruno
Brent
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On 4 Jun 2020, at 07:19, Philip Thrift <cloud...@gmail.com> wrote:
On Wednesday, June 3, 2020 at 1:03:58 PM UTC-5, Lawrence Crowell wrote:On Wednesday, June 3, 2020 at 8:35:34 AM UTC-5, Philip Thrift wrote:
On Wednesday, June 3, 2020 at 5:26:08 AM UTC-5, Lawrence Crowell wrote:For the most part computers are meant to run various algorithms that solve some restricted set of problems, say business applications. We use them largely as tools.LCAll of the (usable) theories of physics invented to date can be (and are) implemented on supercomputers (like those in the Dept. Of Energy national labs).Some physicists though talk as if there is a Church they must go to -- where their minds are elevated into a Platonic realm where Physics is revealed to them.@philipthriftI guess one might say that is what experiments do.LCAs I say,Physics = Math + Witchcraft.(Computational Physics though is a programming domain.)That is correct. But computational physics, like physics, cannot be the last word, and the physical reality, nor the psychological reality can be “entirely” computable. The universal machine is already not something totally computable, only partially.Any theory rich enough to define what is a computer has a non computable semantics.Bruno
> On 2 Jun 2020, at 19:34, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>
>
>
> On 6/2/2020 2:49 AM, Bruno Marchal wrote:
>>> On 1 Jun 2020, at 22:43, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>>>
>>>
>>>
>>> On 6/1/2020 2:08 AM, Bruno Marchal wrote:
>>>> Brent suggest that we might recover completeness by restricting N to a finite domain. That is correct, because all finite function are computable, but then, we have incompleteness directly with respect to the computable functions, even limited on finite but arbitrary domain. In fact, that moves makes the computer simply vanishing, and it makes Mechanism not even definable or expressible.
>>> That's going to come as a big shock to IBM stockholders.
>>
>> Why? On the contrary. IBM bets on universal machine
>
> No, they bet only on finite machines, and they will be very surprised to hear that they have vanished.
They bet on finite machines … including the universal machine, which I insist is a finite machine. That is even the reason why I called it from times to times universal number.
I recall that once we get the phi_i, which can be defined in elementary arithmetic, we get all the universal numbers, that is all u such that there phi_u(x, y) = phi_x(y), and such u can be used to define all the recursive enumeration of all digital machines.
The implementation of this fine but universal machines are called (physical) computer, and is the domain of expertise of IBM.
Bruno
>
> Brent
>
>> and know well what is a computer: a finite arithmetical being in touch with the infinite, and indeed, always asking for more memory, which is the typical symptom of liberty/universality. IBM might be finitist, like Mechanism, but is not ultrafinist at all. Anyway, mathematically, Mechanism is consistent with ulrafinitsim, even if to prove this, you need to go beyond finitism, (but then that’s the case for all consistent theory: none can prove its own consistency once “rich enough” (= just Turing universal, not “Löbian”).
>>
>> Bruno
>
>
> --
> You received this message because you are subscribed to the Google Groups "Everything List" group.
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On Thursday, June 4, 2020 at 6:07:45 AM UTC-5, Bruno Marchal wrote:
> On 2 Jun 2020, at 19:34, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>
>
>
> On 6/2/2020 2:49 AM, Bruno Marchal wrote:
>>> On 1 Jun 2020, at 22:43, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>>>
>>>
>>>
>>> On 6/1/2020 2:08 AM, Bruno Marchal wrote:
>>>> Brent suggest that we might recover completeness by restricting N to a finite domain. That is correct, because all finite function are computable, but then, we have incompleteness directly with respect to the computable functions, even limited on finite but arbitrary domain. In fact, that moves makes the computer simply vanishing, and it makes Mechanism not even definable or expressible.
>>> That's going to come as a big shock to IBM stockholders.
>>
>> Why? On the contrary. IBM bets on universal machine
>
> No, they bet only on finite machines, and they will be very surprised to hear that they have vanished.
They bet on finite machines … including the universal machine, which I insist is a finite machine. That is even the reason why I called it from times to times universal number.
I recall that once we get the phi_i, which can be defined in elementary arithmetic, we get all the universal numbers, that is all u such that there phi_u(x, y) = phi_x(y), and such u can be used to define all the recursive enumeration of all digital machines.
The implementation of this fine but universal machines are called (physical) computer, and is the domain of expertise of IBM.
Bruno
Of course any computation is going to be finite or involve a finite number of bits. This happens as well with quantum computers, but there is one difference. Two states can be prepared and entangled so they have a continuum of probabilities depending upon measurement angle. This is what separates QM from classical mechanics.
--This separates entanglement of spins from the Bergman's socks, where knowing the left sock is in one box the right must be in the other. So while there is a finitude to the entanglement entropy or the quantity of quantum information, the possible ways an entanglement can register outcomes is infinite. This is what gives a violation of Bell's theorem in QM. With the measurement of a quantum system the pair of a state and measurement forms a type of Godel numbering. This connects QM foundations with the phi_u(x, y) = phi_x(y),you state above.
A classical computer will always be finite, and you can't have an infinite Cantor diagonalization. The computers that are manufactured are done so to solve certain problems, RSA encyrption, user interfaces for service personnel from travel agents to sales, word processors, games, cell phone signal shifters, data processors of medical measurements and on it goes. Even with quantum computers this will take off, and in fact I have thought quantum computing would be a way of managing a dynamics network defined by millions of drones over a city. Even if as I think the Godel-Turing result underlies obstructions between entanglement types quantum computers will in time become the province of engineering and business applications.
LC
>
> Brent
>
>> and know well what is a computer: a finite arithmetical being in touch with the infinite, and indeed, always asking for more memory, which is the typical symptom of liberty/universality. IBM might be finitist, like Mechanism, but is not ultrafinist at all. Anyway, mathematically, Mechanism is consistent with ulrafinitsim, even if to prove this, you need to go beyond finitism, (but then that’s the case for all consistent theory: none can prove its own consistency once “rich enough” (= just Turing universal, not “Löbian”).
>>
>> Bruno
>
>
> --
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On 6/4/2020 3:39 PM, Lawrence Crowell wrote:
Of course any computation is going to be finite or involve a finite number of bits. This happens as well with quantum computers, but there is one difference. Two states can be prepared and entangled so they have a continuum of probabilities depending upon measurement angle. This is what separates QM from classical mechanics.
I've wondered about this. Of course a lot variables in the theory are continua; not just angle but also position. Yet none of those can be measured to arbitrary precision. And the more precisely one is, the less precisely it's conjugate can be...which is what separate QM from classical mechanics. Holevo's theorem limits what we can know about a state.
Brent
On 4 Jun 2020, at 20:35, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 6/4/2020 4:27 AM, Bruno Marchal wrote:
On 3 Jun 2020, at 21:47, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 6/3/2020 3:26 AM, Lawrence Crowell wrote:
On Tuesday, June 2, 2020 at 12:34:37 PM UTC-5, Brent wrote:
On 6/2/2020 2:49 AM, Bruno Marchal wrote:
>> On 1 Jun 2020, at 22:43, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>>
>>
>>
>> On 6/1/2020 2:08 AM, Bruno Marchal wrote:
>>> Brent suggest that we might recover completeness by restricting N to a finite domain. That is correct, because all finite function are computable, but then, we have incompleteness directly with respect to the computable functions, even limited on finite but arbitrary domain. In fact, that moves makes the computer simply vanishing, and it makes Mechanism not even definable or expressible.
>> That's going to come as a big shock to IBM stockholders.
>
> Why? On the contrary. IBM bets on universal machine
No, they bet only on finite machines, and they will be very surprised to
hear that they have vanished.
Brent
For the most part computers are meant to run various algorithms that solve some restricted set of problems, say business applications. We use them largely as tools.
Mathematics is largely a tool. My pure mathematics friends over on math-fun seem to have most of their fun on Mathematica.
Of course, this is close to Aristotelian theology. It assumes that there is something which is not mathematical in some reality. A platonism or a pythegaorean think that he physical universe is but a tool, invented by the numbers to figure out what happens, and what is real.
But once you grasp that all computations exists in arithmetic (or more exactly, that they are enabled by the arithmetical true relations), even without Mechanism, the charge are reversed. It is those who claim (in metaphysics, not in physics) that there is a primitive universe who have the task to provide evidence.
You have implicitly asserted that computation=reality. With not proof, or even evidence.
Brent
I have given the way to test this, and, thanks to QM, we can say that there are not yet any evidence found for a primitive physical universe. On the contrary, nature seems to obey exactly to what is needed for mechanism to be true.
Then, if we assume furthermore Mechanism, there is no more choice in this matter. Physics cannot be the fundamental science, it reduces to arithmetic (or any model of any Turing equivalent machinery) “seen-from inside”.
Bruno
Brent
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@philipthrift--
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On 6/4/2020 3:39 PM, Lawrence Crowell wrote:
On Thursday, June 4, 2020 at 6:07:45 AM UTC-5, Bruno Marchal wrote:
> On 2 Jun 2020, at 19:34, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>
>
>
> On 6/2/2020 2:49 AM, Bruno Marchal wrote:
>>> On 1 Jun 2020, at 22:43, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>>>
>>>
>>>
>>> On 6/1/2020 2:08 AM, Bruno Marchal wrote:
>>>> Brent suggest that we might recover completeness by restricting N to a finite domain. That is correct, because all finite function are computable, but then, we have incompleteness directly with respect to the computable functions, even limited on finite but arbitrary domain. In fact, that moves makes the computer simply vanishing, and it makes Mechanism not even definable or expressible.
>>> That's going to come as a big shock to IBM stockholders.
>>
>> Why? On the contrary. IBM bets on universal machine
>
> No, they bet only on finite machines, and they will be very surprised to hear that they have vanished.
They bet on finite machines … including the universal machine, which I insist is a finite machine. That is even the reason why I called it from times to times universal number.
I recall that once we get the phi_i, which can be defined in elementary arithmetic, we get all the universal numbers, that is all u such that there phi_u(x, y) = phi_x(y), and such u can be used to define all the recursive enumeration of all digital machines.
The implementation of this fine but universal machines are called (physical) computer, and is the domain of expertise of IBM.
Bruno
Of course any computation is going to be finite or involve a finite number of bits. This happens as well with quantum computers, but there is one difference. Two states can be prepared and entangled so they have a continuum of probabilities depending upon measurement angle. This is what separates QM from classical mechanics.
I've wondered about this. Of course a lot variables in the theory are continua; not just angle but also position. Yet none of those can be measured to arbitrary precision. And the more precisely one is, the less precisely it's conjugate can be...which is what separate QM from classical mechanics. Holevo's theorem limits what we can know about a state.
Brent
--This separates entanglement of spins from the Bergman's socks, where knowing the left sock is in one box the right must be in the other. So while there is a finitude to the entanglement entropy or the quantity of quantum information, the possible ways an entanglement can register outcomes is infinite. This is what gives a violation of Bell's theorem in QM. With the measurement of a quantum system the pair of a state and measurement forms a type of Godel numbering. This connects QM foundations with the phi_u(x, y) = phi_x(y),you state above.
A classical computer will always be finite, and you can't have an infinite Cantor diagonalization. The computers that are manufactured are done so to solve certain problems, RSA encyrption, user interfaces for service personnel from travel agents to sales, word processors, games, cell phone signal shifters, data processors of medical measurements and on it goes. Even with quantum computers this will take off, and in fact I have thought quantum computing would be a way of managing a dynamics network defined by millions of drones over a city. Even if as I think the Godel-Turing result underlies obstructions between entanglement types quantum computers will in time become the province of engineering and business applications.
LC
>
> Brent
>
>> and know well what is a computer: a finite arithmetical being in touch with the infinite, and indeed, always asking for more memory, which is the typical symptom of liberty/universality. IBM might be finitist, like Mechanism, but is not ultrafinist at all. Anyway, mathematically, Mechanism is consistent with ulrafinitsim, even if to prove this, you need to go beyond finitism, (but then that’s the case for all consistent theory: none can prove its own consistency once “rich enough” (= just Turing universal, not “Löbian”).
>>
>> Bruno
>
>
> --
> You received this message because you are subscribed to the Google Groups "Everything List" group.
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On 5 Jun 2020, at 00:39, Lawrence Crowell <goldenfield...@gmail.com> wrote:On Thursday, June 4, 2020 at 6:07:45 AM UTC-5, Bruno Marchal wrote:
> On 2 Jun 2020, at 19:34, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>
>
>
> On 6/2/2020 2:49 AM, Bruno Marchal wrote:
>>> On 1 Jun 2020, at 22:43, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>>>
>>>
>>>
>>> On 6/1/2020 2:08 AM, Bruno Marchal wrote:
>>>> Brent suggest that we might recover completeness by restricting N to a finite domain. That is correct, because all finite function are computable, but then, we have incompleteness directly with respect to the computable functions, even limited on finite but arbitrary domain. In fact, that moves makes the computer simply vanishing, and it makes Mechanism not even definable or expressible.
>>> That's going to come as a big shock to IBM stockholders.
>>
>> Why? On the contrary. IBM bets on universal machine
>
> No, they bet only on finite machines, and they will be very surprised to hear that they have vanished.
They bet on finite machines … including the universal machine, which I insist is a finite machine. That is even the reason why I called it from times to times universal number.
I recall that once we get the phi_i, which can be defined in elementary arithmetic, we get all the universal numbers, that is all u such that there phi_u(x, y) = phi_x(y), and such u can be used to define all the recursive enumeration of all digital machines.
The implementation of this fine but universal machines are called (physical) computer, and is the domain of expertise of IBM.
Bruno
Of course any computation is going to be finite or involve a finite number of bits.
This happens as well with quantum computers, but there is one difference. Two states can be prepared and entangled so they have a continuum of probabilities depending upon measurement angle. This is what separates QM from classical mechanics. This separates entanglement of spins from the Bergman's socks, where knowing the left sock is in one box the right must be in the other. So while there is a finitude to the entanglement entropy or the quantity of quantum information, the possible ways an entanglement can register outcomes is infinite. This is what gives a violation of Bell's theorem in QM. With the measurement of a quantum system the pair of a state and measurement forms a type of Godel numbering. This connects QM foundations with the phi_u(x, y) = phi_x(y),you state above.
A classical computer will always be finite, and you can't have an infinite Cantor diagonalization.
The computers that are manufactured are done so to solve certain problems, RSA encyrption, user interfaces for service personnel from travel agents to sales, word processors, games, cell phone signal shifters, data processors of medical measurements and on it goes.
Even with quantum computers this will take off, and in fact I have thought quantum computing would be a way of managing a dynamics network defined by millions of drones over a city. Even if as I think the Godel-Turing result underlies obstructions between entanglement types quantum computers will in time become the province of engineering and business applications.
LC
>
> Brent
>
>> and know well what is a computer: a finite arithmetical being in touch with the infinite, and indeed, always asking for more memory, which is the typical symptom of liberty/universality. IBM might be finitist, like Mechanism, but is not ultrafinist at all. Anyway, mathematically, Mechanism is consistent with ulrafinitsim, even if to prove this, you need to go beyond finitism, (but then that’s the case for all consistent theory: none can prove its own consistency once “rich enough” (= just Turing universal, not “Löbian”).
>>
>> Bruno
>
>
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On 5 Jun 2020, at 08:09, Philip Thrift <cloud...@gmail.com> wrote:
On Thursday, June 4, 2020 at 11:01:20 PM UTC-5, Brent wrote:
On 6/4/2020 3:39 PM, Lawrence Crowell wrote:
Of course any computation is going to be finite or involve a finite number of bits. This happens as well with quantum computers, but there is one difference. Two states can be prepared and entangled so they have a continuum of probabilities depending upon measurement angle. This is what separates QM from classical mechanics.
I've wondered about this. Of course a lot variables in the theory are continua; not just angle but also position. Yet none of those can be measured to arbitrary precision. And the more precisely one is, the less precisely it's conjugate can be...which is what separate QM from classical mechanics. Holevo's theorem limits what we can know about a state.
Brent
I was going to comment here but just to re-quote Max Tegmark's dictum:Our challenge as physicists is to discover the infinity-free equations describing it—the true laws of physics.
It seems to always be needed to restate to physicists *as Vic Stenger did):Just because a mathematical theory someone came up with to model physical stuff has property X doesn't mean that the physical stuff has property X.
@philipthrift
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On 4 Jun 2020, at 22:33, Philip Thrift <cloud...@gmail.com> wrote:Years ago I wrote about the Zetanswho never imagined infinities, nor found any reason to either think of them, or invent them.They have a fine definition of computers and computing, and have found no need for anything more than finite mechanism in any of their theory of computing.That we came to think "infinity" plays a role in computing (or in computing theory, or in mathematics in general) is just an aspect of our own peculiar psychology and history, but it is not needed.That makes some sense. You can compute without axiom of infinity, and indeed you can define what is a computer just by using the two axioms Kxy = x, and Sxyz = xz(yz), as I have explicitly shown on this list. Similarly you can define a computer using only elementary arithmetic, like Gödel did implicitly and Kleene did explicitly. But to prove anything non trivial, you need induction, and to get semantics treated mathematically, you need actual infinity axioms, like with the notion of real numbers, etc.To *understand* Kxy = x …, you need an axiom of infinity at the meta-level, and this is required by all scientist-numbers in arithmetic, so “infinity” is more than welcome to define the notion of observer, and for the notion of physical *laws*.Bruno
On 4 Jun 2020, at 20:35, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 6/4/2020 4:27 AM, Bruno Marchal wrote:
On 3 Jun 2020, at 21:47, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 6/3/2020 3:26 AM, Lawrence Crowell wrote:
On Tuesday, June 2, 2020 at 12:34:37 PM UTC-5, Brent wrote:
On 6/2/2020 2:49 AM, Bruno Marchal wrote:
>> On 1 Jun 2020, at 22:43, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>>
>>
>>
>> On 6/1/2020 2:08 AM, Bruno Marchal wrote:
>>> Brent suggest that we might recover completeness by restricting N to a finite domain. That is correct, because all finite function are computable, but then, we have incompleteness directly with respect to the computable functions, even limited on finite but arbitrary domain. In fact, that moves makes the computer simply vanishing, and it makes Mechanism not even definable or expressible.
>> That's going to come as a big shock to IBM stockholders.
>
> Why? On the contrary. IBM bets on universal machine
No, they bet only on finite machines, and they will be very surprised to
hear that they have vanished.
Brent
For the most part computers are meant to run various algorithms that solve some restricted set of problems, say business applications. We use them largely as tools.
Mathematics is largely a tool. My pure mathematics friends over on math-fun seem to have most of their fun on Mathematica.
Of course, this is close to Aristotelian theology. It assumes that there is something which is not mathematical in some reality. A platonism or a pythegaorean think that he physical universe is but a tool, invented by the numbers to figure out what happens, and what is real.
But once you grasp that all computations exists in arithmetic (or more exactly, that they are enabled by the arithmetical true relations), even without Mechanism, the charge are reversed. It is those who claim (in metaphysics, not in physics) that there is a primitive universe who have the task to provide evidence.
You have implicitly asserted that computation=reality. With not proof, or even evidence.
?
The UDA *proves* that the fundamental reality = arithmetic.
And AUDA (arithmetical Dovetailer Argument) makes the proof constructive, and it makes Mechanism testable, and the evidences for mechanism are striking, at a place where we know since 1500 years that Materialism is already refuted. Oh, yes, that is well hidden since 1500 years, by all gnostic (atheist or non atheists).
You are the one who seems to claim the existence of an ontological physical universe, where there is no proof nor any evidence.
Evidences for a physical reality is not evidences for an ontological or primitive physical reality.
The confusion between both of those is know as Aristotle theology. The belief in primary matter or physicalism (mathematicalist or not).
Bruno
Brent
I have given the way to test this, and, thanks to QM, we can say that there are not yet any evidence found for a primitive physical universe. On the contrary, nature seems to obey exactly to what is needed for mechanism to be true.
Then, if we assume furthermore Mechanism, there is no more choice in this matter. Physics cannot be the fundamental science, it reduces to arithmetic (or any model of any Turing equivalent machinery) “seen-from inside”.
Bruno
Brent
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On 5 Jun 2020, at 13:34, Philip Thrift <cloud...@gmail.com> wrote:
On Friday, June 5, 2020 at 4:47:14 AM UTC-5, Bruno Marchal wrote:On 4 Jun 2020, at 22:33, Philip Thrift <cloud...@gmail.com> wrote:Years ago I wrote about the Zetanswho never imagined infinities, nor found any reason to either think of them, or invent them.They have a fine definition of computers and computing, and have found no need for anything more than finite mechanism in any of their theory of computing.That we came to think "infinity" plays a role in computing (or in computing theory, or in mathematics in general) is just an aspect of our own peculiar psychology and history, but it is not needed.That makes some sense. You can compute without axiom of infinity, and indeed you can define what is a computer just by using the two axioms Kxy = x, and Sxyz = xz(yz), as I have explicitly shown on this list. Similarly you can define a computer using only elementary arithmetic, like Gödel did implicitly and Kleene did explicitly. But to prove anything non trivial, you need induction, and to get semantics treated mathematically, you need actual infinity axioms, like with the notion of real numbers, etc.To *understand* Kxy = x …, you need an axiom of infinity at the meta-level, and this is required by all scientist-numbers in arithmetic, so “infinity” is more than welcome to define the notion of observer, and for the notion of physical *laws*.BrunoAs my old post shows, the Zetans do have their Axiom of Infinity - called the Axiom of Zillions.
They are happy with their finite set of numbers, but sometimes they construct bigger numbers to add to the set. But they do not think there are numbers between the bigger numbers. There are gaps.There is no potential infinity since they don't think their galaxy will last forever.
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On 5 Jun 2020, at 00:39, Lawrence Crowell <goldenfield...@gmail.com> wrote:On Thursday, June 4, 2020 at 6:07:45 AM UTC-5, Bruno Marchal wrote:
> On 2 Jun 2020, at 19:34, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>
>
>
> On 6/2/2020 2:49 AM, Bruno Marchal wrote:
>>> On 1 Jun 2020, at 22:43, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>>>
>>>
>>>
>>> On 6/1/2020 2:08 AM, Bruno Marchal wrote:
>>>> Brent suggest that we might recover completeness by restricting N to a finite domain. That is correct, because all finite function are computable, but then, we have incompleteness directly with respect to the computable functions, even limited on finite but arbitrary domain. In fact, that moves makes the computer simply vanishing, and it makes Mechanism not even definable or expressible.
>>> That's going to come as a big shock to IBM stockholders.
>>
>> Why? On the contrary. IBM bets on universal machine
>
> No, they bet only on finite machines, and they will be very surprised to hear that they have vanished.
They bet on finite machines … including the universal machine, which I insist is a finite machine. That is even the reason why I called it from times to times universal number.
I recall that once we get the phi_i, which can be defined in elementary arithmetic, we get all the universal numbers, that is all u such that there phi_u(x, y) = phi_x(y), and such u can be used to define all the recursive enumeration of all digital machines.
The implementation of this fine but universal machines are called (physical) computer, and is the domain of expertise of IBM.
Bruno
Of course any computation is going to be finite or involve a finite number of bits.Any halting computation.Some non halting computation requires infinite time and space, virtual, arithmetical or physical.
This happens as well with quantum computers, but there is one difference. Two states can be prepared and entangled so they have a continuum of probabilities depending upon measurement angle. This is what separates QM from classical mechanics. This separates entanglement of spins from the Bergman's socks, where knowing the left sock is in one box the right must be in the other. So while there is a finitude to the entanglement entropy or the quantity of quantum information, the possible ways an entanglement can register outcomes is infinite. This is what gives a violation of Bell's theorem in QM. With the measurement of a quantum system the pair of a state and measurement forms a type of Godel numbering. This connects QM foundations with the phi_u(x, y) = phi_x(y),you state above.OK. But you assume some quantum universe, where the UDA explains why you have to derive the quantum from arithmetic or (Turing) equivalent.
A classical computer will always be finite, and you can't have an infinite Cantor diagonalization.The Kleene diagonalisation is constructive. It shows the inexistence of some finite machine having some “arithmetical omniscience”. It requires potential infinities, not the cantorian infinities.
The computers that are manufactured are done so to solve certain problems, RSA encyrption, user interfaces for service personnel from travel agents to sales, word processors, games, cell phone signal shifters, data processors of medical measurements and on it goes.All computers exists in arithmetic, and all computations exist in an internal limit of arithmetic (by step 2, actually!).With mechanism, the physical reality is not the fundamental reality. The physical reality emerges from the computation executed in virtue of the number relations, like the prime number distribution, for example.
Even with quantum computers this will take off, and in fact I have thought quantum computing would be a way of managing a dynamics network defined by millions of drones over a city. Even if as I think the Godel-Turing result underlies obstructions between entanglement types quantum computers will in time become the province of engineering and business applications.No doubt on this. It is just that with mechanism, the physical universe is not ontological, but more like a collective hallucination made by the relative universal number relations which are as true, and independent of the physical laws, than 117 is composite and 317 is prime.Bruno<<
Of this reality, as I explained […], I take a 'realistic" view. At any rate (and this is my main point) this realistic view is much more plausible of mathematical than of physical reality, because mathematical objects are so much more what they seem. A chair or a star is not in the least like what it seems to be ; the more we think of it, the fuzzier its outlines become in the haze of sensations which surrounds it; but '2' and '317' has nothing to do with sensations, and its properties stand out the more clearly the more closely we scrutinize it. It may be that modern physics fits best in the framework of idealistic philosophy---I do not believe it, but there are eminent physicist who say so. Pure Mathematics, on the other hand, seems to me a rock on which all idealism founders: 317 is prime, not because we think so, or because our minds are shaped in one way rather than another, but because it is so, because mathematical is built that way.
>>
G. H. Hardy, "A Mathematician's Apology", Cambridge University Press, 1940 (1998).
LC
>
> Brent
>
>> and know well what is a computer: a finite arithmetical being in touch with the infinite, and indeed, always asking for more memory, which is the typical symptom of liberty/universality. IBM might be finitist, like Mechanism, but is not ultrafinist at all. Anyway, mathematically, Mechanism is consistent with ulrafinitsim, even if to prove this, you need to go beyond finitism, (but then that’s the case for all consistent theory: none can prove its own consistency once “rich enough” (= just Turing universal, not “Löbian”).
>>
>> Bruno
>
>
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On 5 Jun 2020, at 21:13, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 6/5/2020 2:39 AM, Bruno Marchal wrote:
On 4 Jun 2020, at 20:35, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 6/4/2020 4:27 AM, Bruno Marchal wrote:
On 3 Jun 2020, at 21:47, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 6/3/2020 3:26 AM, Lawrence Crowell wrote:
On Tuesday, June 2, 2020 at 12:34:37 PM UTC-5, Brent wrote:
On 6/2/2020 2:49 AM, Bruno Marchal wrote:
>> On 1 Jun 2020, at 22:43, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>>
>>
>>
>> On 6/1/2020 2:08 AM, Bruno Marchal wrote:
>>> Brent suggest that we might recover completeness by restricting N to a finite domain. That is correct, because all finite function are computable, but then, we have incompleteness directly with respect to the computable functions, even limited on finite but arbitrary domain. In fact, that moves makes the computer simply vanishing, and it makes Mechanism not even definable or expressible.
>> That's going to come as a big shock to IBM stockholders.
>
> Why? On the contrary. IBM bets on universal machine
No, they bet only on finite machines, and they will be very surprised to
hear that they have vanished.
Brent
For the most part computers are meant to run various algorithms that solve some restricted set of problems, say business applications. We use them largely as tools.
Mathematics is largely a tool. My pure mathematics friends over on math-fun seem to have most of their fun on Mathematica.
Of course, this is close to Aristotelian theology. It assumes that there is something which is not mathematical in some reality. A platonism or a pythegaorean think that he physical universe is but a tool, invented by the numbers to figure out what happens, and what is real.
But once you grasp that all computations exists in arithmetic (or more exactly, that they are enabled by the arithmetical true relations), even without Mechanism, the charge are reversed. It is those who claim (in metaphysics, not in physics) that there is a primitive universe who have the task to provide evidence.
You have implicitly asserted that computation=reality. With not proof, or even evidence.
?
The UDA *proves* that the fundamental reality = arithmetic.
All proofs are relative to their premises. You just assume arithmetic is real.
To view this discussion on the web visit https://groups.google.com/d/msgid/everything-list/811521da-af37-5f5f-2f7b-90a30109d8b5%40verizon.net.
The axioms that I use are just Kxy = x, and Sxyz = xz(yz).But you allow rules of inference that permit inferences about the enumerated array of all functions.Right. Here is the complete set of ontological assumptions: AXIOMS KAB = A SABC = AC(BC) RULES: If A = B and A = C, then B = C If A = B then AC = BC If A = B then CA = CB
All we have to assume is that a number added to 0 gives that number, that 0 is not a successor, etc. We have just to believe that 817 is prime or not prime, or that (x + 4 = 9) admits a solution, or not. I have never met a physicist who does not believe in those truth.
Now, given that all computations are run in arithmetic, a believer in Matter is invited to provide evidences, but as Plato understood already, there are no evidences at all.
Not one. All the evidences we have today points on the immaterial consequence of Digital mechanism, from molecular biology to QM without collapse.
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On 6 Jun 2020, at 12:44, Lawrence Crowell <goldenfield...@gmail.com> wrote:On Friday, June 5, 2020 at 4:57:06 AM UTC-5, Bruno Marchal wrote:On 5 Jun 2020, at 00:39, Lawrence Crowell <goldenfield...@gmail.com> wrote:On Thursday, June 4, 2020 at 6:07:45 AM UTC-5, Bruno Marchal wrote:
> On 2 Jun 2020, at 19:34, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>
>
>
> On 6/2/2020 2:49 AM, Bruno Marchal wrote:
>>> On 1 Jun 2020, at 22:43, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
>>>
>>>
>>>
>>> On 6/1/2020 2:08 AM, Bruno Marchal wrote:
>>>> Brent suggest that we might recover completeness by restricting N to a finite domain. That is correct, because all finite function are computable, but then, we have incompleteness directly with respect to the computable functions, even limited on finite but arbitrary domain. In fact, that moves makes the computer simply vanishing, and it makes Mechanism not even definable or expressible.
>>> That's going to come as a big shock to IBM stockholders.
>>
>> Why? On the contrary. IBM bets on universal machine
>
> No, they bet only on finite machines, and they will be very surprised to hear that they have vanished.
They bet on finite machines … including the universal machine, which I insist is a finite machine. That is even the reason why I called it from times to times universal number.
I recall that once we get the phi_i, which can be defined in elementary arithmetic, we get all the universal numbers, that is all u such that there phi_u(x, y) = phi_x(y), and such u can be used to define all the recursive enumeration of all digital machines.
The implementation of this fine but universal machines are called (physical) computer, and is the domain of expertise of IBM.
Bruno
Of course any computation is going to be finite or involve a finite number of bits.Any halting computation.Some non halting computation requires infinite time and space, virtual, arithmetical or physical.It is easy to make a nonhalting computation that is finite. A few lines of code with a line4 GOTO 3
will be nonhalting. When your desk or lap computer freezes up it has entered into a state where something like this is happening. With codes that have a bounded length
it is in principle possible for a UTM that can catch all nonhalting codes.
Though for programs with thousands of lines the number of possibilities is ~ n^{1000}, which is a tad large. The finite UTM is very difficult. Just ponder Microsoft the next time your machine freezes up.
This happens as well with quantum computers, but there is one difference. Two states can be prepared and entangled so they have a continuum of probabilities depending upon measurement angle. This is what separates QM from classical mechanics. This separates entanglement of spins from the Bergman's socks, where knowing the left sock is in one box the right must be in the other. So while there is a finitude to the entanglement entropy or the quantity of quantum information, the possible ways an entanglement can register outcomes is infinite. This is what gives a violation of Bell's theorem in QM. With the measurement of a quantum system the pair of a state and measurement forms a type of Godel numbering. This connects QM foundations with the phi_u(x, y) = phi_x(y),you state above.OK. But you assume some quantum universe, where the UDA explains why you have to derive the quantum from arithmetic or (Turing) equivalent.
As John Wheeler asked, "Why the quantum?”
The quantum horizon and a general undecidability of all possible propositions are related and maybe ultimately equivalent. Quantum mechanics may entirely be due to this limitation.
I wrote a paper, under adjudication right now, that entanglement types are topologically distinct removed from any unitary equivalence by topological obstruction due to mathematical undecidability.
A classical computer will always be finite, and you can't have an infinite Cantor diagonalization.The Kleene diagonalisation is constructive. It shows the inexistence of some finite machine having some “arithmetical omniscience”. It requires potential infinities, not the cantorian infinities.Yes, I have heard of this. It is similar to my approach to Hilbert space as finite and unbounded. By making it unbounded it just means that even if the HIlbert space is infinite the most extreme UV states are unoccupied or inaccessible.
With quantum gravitation this is where the Planck scale comes in. Quantum states with a wavelength smaller than the Planck length ℓ_p = √(Għ/c^3) are unentangled with states in the rest of the universe. The accelerated expansion of the universe increases their wavelength and in effect pulls them out of this tiny scale. These then become entangled with the rest of the observable universe. Quantum states that have very low energy are similarly stretched out these eventually exceed the cosmological horizon length √(3/Λ) for the cosmological constant Λ = 8πGρ/c^2 and are then no longer entangled with any local region bounded by the cosmological horizon. This keeps the number of quantum states finite.
The computers that are manufactured are done so to solve certain problems, RSA encyrption, user interfaces for service personnel from travel agents to sales, word processors, games, cell phone signal shifters, data processors of medical measurements and on it goes.All computers exists in arithmetic, and all computations exist in an internal limit of arithmetic (by step 2, actually!).With mechanism, the physical reality is not the fundamental reality. The physical reality emerges from the computation executed in virtue of the number relations, like the prime number distribution, for example.I guess I have not seen any reason to be concerned with the distinction between mechanism and physicalism. This strikes me as sort of philosophical hair splitting that is of no utility to doing physics.
Again, the ultimate relationship between the physical world and that of mathematics is not something that may be knowable.
At some point here we are in an existential nullity, where our understanding of what it means to exist is not longer definite.
With QM we have less certitude over what is meant by an event or objective meaning to an object and with mathematics there is no clear definition of what is meant by mathematical truth.
Hardy tries to raise this point below, but it appears we have today a lack of clarity with respect to what is meant by a proof
and clearly Gödel showed that within an axiomatic system
there are holes of undecidability and these things have a dualism of being objective and almost Platonic, but also on the other hand little more than model systems.
LCEven with quantum computers this will take off, and in fact I have thought quantum computing would be a way of managing a dynamics network defined by millions of drones over a city. Even if as I think the Godel-Turing result underlies obstructions between entanglement types quantum computers will in time become the province of engineering and business applications.No doubt on this. It is just that with mechanism, the physical universe is not ontological, but more like a collective hallucination made by the relative universal number relations which are as true, and independent of the physical laws, than 117 is composite and 317 is prime.Bruno<<
Of this reality, as I explained […], I take a 'realistic" view. At any rate (and this is my main point) this realistic view is much more plausible of mathematical than of physical reality, because mathematical objects are so much more what they seem. A chair or a star is not in the least like what it seems to be ; the more we think of it, the fuzzier its outlines become in the haze of sensations which surrounds it; but '2' and '317' has nothing to do with sensations, and its properties stand out the more clearly the more closely we scrutinize it. It may be that modern physics fits best in the framework of idealistic philosophy---I do not believe it, but there are eminent physicist who say so. Pure Mathematics, on the other hand, seems to me a rock on which all idealism founders: 317 is prime, not because we think so, or because our minds are shaped in one way rather than another, but because it is so, because mathematical is built that way.
>>
G. H. Hardy, "A Mathematician's Apology", Cambridge University Press, 1940 (1998).LC
>
> Brent
>
>> and know well what is a computer: a finite arithmetical being in touch with the infinite, and indeed, always asking for more memory, which is the typical symptom of liberty/universality. IBM might be finitist, like Mechanism, but is not ultrafinist at all. Anyway, mathematically, Mechanism is consistent with ulrafinitsim, even if to prove this, you need to go beyond finitism, (but then that’s the case for all consistent theory: none can prove its own consistency once “rich enough” (= just Turing universal, not “Löbian”).
>>
>> Bruno
>
>
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Brent
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A proposition cannot be ambiguous or nonsensical and also proven: "The UDA *proves* that the fundamental reality = arithmetic.”
All we have to assume is that a number added to 0 gives that number, that 0 is not a successor, etc. We have just to believe that 817 is prime or not prime, or that (x + 4 = 9) admits a solution, or not. I have never met a physicist who does not believe in those truth.
I've never met a physicist who confused true with real. But I've met such mathematicians.
Now, given that all computations are run in arithmetic, a believer in Matter is invited to provide evidences, but as Plato understood already, there are no evidences at all.
No evidence for what?
Not one. All the evidences we have today points on the immaterial consequence of Digital mechanism, from molecular biology to QM without collapse.
A theory that depends on the collapse interpretation of QM
as proof that mathematics is real;
is self contradictory since there are mathematically consistent theories of QM in which the wave function does collapse.
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Though for programs with thousands of lines the number of possibilities is ~ n^{1000}, which is a tad large. The finite UTM is very difficult. Just ponder Microsoft the next time your machine freezes up.All UTM are finite (unless working in a non standard model, but that has to be made precise, and it is something entirely different).Ana dall finite UTM leads to undecidability. For all UTM M and U, there is some x for which no UTM M cannot say if Ux stops or not.
This happens as well with quantum computers, but there is one difference. Two states can be prepared and entangled so they have a continuum of probabilities depending upon measurement angle. This is what separates QM from classical mechanics. This separates entanglement of spins from the Bergman's socks, where knowing the left sock is in one box the right must be in the other. So while there is a finitude to the entanglement entropy or the quantity of quantum information, the possible ways an entanglement can register outcomes is infinite. This is what gives a violation of Bell's theorem in QM. With the measurement of a quantum system the pair of a state and measurement forms a type of Godel numbering. This connects QM foundations with the phi_u(x, y) = phi_x(y),you state above.OK. But you assume some quantum universe, where the UDA explains why you have to derive the quantum from arithmetic or (Turing) equivalent.As John Wheeler asked, "Why the quantum?”And Wheeler gave the correct answer: It for bit. Although a more precise one is: qubits from the theology of bits.
The quantum horizon and a general undecidability of all possible propositions are related and maybe ultimately equivalent. Quantum mechanics may entirely be due to this limitation.It has to. This is what I have proven. (Assuming the digital mechanist theory, to be sure).I wrote a paper, under adjudication right now, that entanglement types are topologically distinct removed from any unitary equivalence by topological obstruction due to mathematical undecidability.If you can give a link toward your text, I would be pleased.
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Though for programs with thousands of lines the number of possibilities is ~ n^{1000}, which is a tad large. The finite UTM is very difficult. Just ponder Microsoft the next time your machine freezes up.All UTM are finite (unless working in a non standard model, but that has to be made precise, and it is something entirely different).Ana dall finite UTM leads to undecidability. For all UTM M and U, there is some x for which no UTM M cannot say if Ux stops or not.I meant a finite list.
This happens as well with quantum computers, but there is one difference. Two states can be prepared and entangled so they have a continuum of probabilities depending upon measurement angle. This is what separates QM from classical mechanics. This separates entanglement of spins from the Bergman's socks, where knowing the left sock is in one box the right must be in the other. So while there is a finitude to the entanglement entropy or the quantity of quantum information, the possible ways an entanglement can register outcomes is infinite. This is what gives a violation of Bell's theorem in QM. With the measurement of a quantum system the pair of a state and measurement forms a type of Godel numbering. This connects QM foundations with the phi_u(x, y) = phi_x(y),you state above.OK. But you assume some quantum universe, where the UDA explains why you have to derive the quantum from arithmetic or (Turing) equivalent.As John Wheeler asked, "Why the quantum?”And Wheeler gave the correct answer: It for bit. Although a more precise one is: qubits from the theology of bits.It from bits that are in self-referential loops.
The quantum horizon and a general undecidability of all possible propositions are related and maybe ultimately equivalent. Quantum mechanics may entirely be due to this limitation.It has to. This is what I have proven. (Assuming the digital mechanist theory, to be sure).I wrote a paper, under adjudication right now, that entanglement types are topologically distinct removed from any unitary equivalence by topological obstruction due to mathematical undecidability.If you can give a link toward your text, I would be pleased.I entered this into the FQXi essay contest. I read the announcement on this topic of undecidability and uncertainty, and was inspired to work like crazy on this. I had been kicking this idea around for a while. I furiously worked this theory and hammered out this paper.
My essay did fair to decent in the voting. If you click on community rating in the page linked below you can see my paper made nearly 90 percentile rating.This essay contest is not the highest ranked place to host a paper. but on the other hand this is such a "way out there" sort of idea that it is hard to get this sort of thing published in more standard peer review. The FQXi poobahs tend to give the prizes to their own members and members of the Perimeter Institute, so my prospects are not entirely great.
I will try to get to the rest later
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On 8 Jun 2020, at 22:51, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:
On 6/8/2020 4:36 AM, Bruno Marchal wrote:On 7 Jun 2020, at 23:03, 'Brent Meeker' via Everything List <everyth...@googlegroups.com> wrote:It is unclear if by “assuming arithmetic” you are are assuming 0 + 0 = 0, 1 + 0 = 1, etc.
On 6/7/2020 5:08 AM, Bruno Marchal wrote:I'm not confused. You made two statements that are implicitly contradictory:But the “UDA proves that …” is not derived from “arithmetic is real”. It is derived from x + 0 = x, etc.A proposition cannot be ambiguous or nonsensical and also proven: "The UDA *proves* that the fundamental reality = arithmetic.”To assume arithmetic is real is ambiguous, if not non sensical.The UDA *proves* that the fundamental reality = arithmetic.All proofs are relative to their premises. You just assume arithmetic is real.
You seem to confuse the theory/machine (and what its says) with the arithmetical reality. Those do not belong to the same level of explanation. The arithmetical reality proves nothing: it is not a theory.
(1) To assume arithmetic is real is ambiguous, if not non sensical.
Ask yourself what you were assuming. It's your statement.
or if you are assuming that the theory exists and is consistent (that is: assuming that a model of arithmetic exists, which when formalised assumes much more, like infinite sets, etc.).(2) The UDA *proves* that the fundamental reality = arithmetic.
UDA shows that we cannot use the assumption that there is a universe to explain why we see a universe. It shows rigorously that this idea does not work.
But you can assume the UDA.
Proofs are relative to their premises.
But that is beside my point: It is contradictory to say that to assume proposition X is nonsense and also that proposition X can be proven.
Any proposition that can be proven (in any logical system) is a proposition that can be consistently added to the axioms.
BrentOf course, the neoplatonician udesrood this since long, but without the Church thesis, their argument (mainly the dream argument) is not constructive, and does not provide the means of verification.I just made the contradiction explicit by pointing out that any proposition that can be proven, cannot be ambiguous or nonsensical and hence can be unambiguously assumed.
The expression “assuming arithmetic” is unclear. With mechanism (which is an heavy assumption) we isolate by meta-reasoning a theory of everything which has very few assumptions: just 0 + 0 = 0, 1 + 0 = 1, etc. That is quite different than assuming that arithmetic is consistent, or make sense, etc.
There is a subtlety here, no doubt. As we assume as much math as we needed at the meta-level, and for the internal phenomenology as well, but all this is done without assuming more than elementary arithmetic at the fundamental ontological level. Mechanism justifies such an approach. All the machine interviews in the context of RA, believes far more proposition than RA. Arithmetic explains why numbers believe (even “richly”) in much more than arithmetic, indeed, they believe in most of the objects that they are dreaming…
BrunoBrent
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