If it's not conserved, as seems implied by the red shift due to expansion, where does it go? TIA, AG
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If you attempt to Sum up all of the components, how close to 0 do you get?Ronald
Just a laymen curiosityAlan Gray by your thought that "When an expanding gas cools, doesn't the energy go into work done to cause the expansion". Let us assume that the energy loss of red shift fuels the expansion of our universe. We know that E=hc/(lamda) and derivative of energy w.r.t wavelength is -hc/(lamda)^2 so as wavelength increase the loss in energy decreases so the rate of expansion should decelerate rather than accelerating.So I think we cannot compare this two observations.
On Fri, May 8, 2020 at 6:35 PM Alan Grayson <agrays...@gmail.com> wrote:
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On Friday, May 8, 2020 at 5:33:53 AM UTC-6, Bruce wrote:On Fri, May 8, 2020 at 9:02 PM Alan Grayson <agrays...@gmail.com> wrote:On Friday, May 8, 2020 at 4:24:36 AM UTC-6, Bruce wrote:On Fri, May 8, 2020 at 7:11 PM Alan Grayson <agrays...@gmail.com> wrote:On Friday, May 8, 2020 at 2:56:50 AM UTC-6, Bruce wrote:On Fri, May 8, 2020 at 6:00 PM Alan Grayson <agrays...@gmail.com> wrote:If it's not conserved, as seems implied by the red shift due to expansion, where does it go? TIA, AGSilly question. If it is not conserved, it does't have to go anywhere -- it just vanishes.BruceWhen an expanding gas cools, doesn't the energy go into work done to cause the expansion? Is it your opinion then, that something cannot come from nothing, but something can become nothing? AGThat's what non-conservation means -- something can come from nothing and go to nothing.BruceIf you believe in what's called "evidence", and extrapolating from it to create a hypothetical physical theory, can you give a single example of something coming from nothing? AGTwo examples. The universe; Dark energy.BruceWe have no clue how the universe began, or even IF it began; and we have zero understanding of dark energy, other than it probably exists and gravitationally interacts with ordinary matter. Where's the rigor? AG
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There is no global meaning to energy conservation. There is the Hamiltonian constraint Nℌ = 0, which just says that for a local region where the lapse function can be parallel translated to the energy is zero. This is for Petrov type O solutionsNℌ = 0 = ½(da/dt)^2 - 4πGρa^2/3c^3 - kWhich leads to the FLRW constraint(a’/a)^2 = 8πGρ/3c^3 – k/a^2 a’ = da/dtWhere the Hubble parameter H = 70km/s-Mpc is (a’/a)^2 = H^2. This means that in a local region we have energy conservation FAPP. The difficulty is this is not a property of the symmetries of the system so we have no way to extend this globally.What this ultimately means is that all physics is local. It does not mean we have mass-energy locally vanishing. The apparent increase in the kinetic energy due to expansion is well enough compensated for by a decease in gravitational potential energy.
There is nothing mysterious going on here. All this means is there is a limitation or horizon to our ability to know if there are global symmetries to the universe. As such there is no meaning to conservation principles.
On Friday, May 8, 2020 at 4:50:55 PM UTC-6, Lawrence Crowell wrote:There is no global meaning to energy conservation. There is the Hamiltonian constraint Nℌ = 0, which just says that for a local region where the lapse function can be parallel translated to the energy is zero. This is for Petrov type O solutionsNℌ = 0 = ½(da/dt)^2 - 4πGρa^2/3c^3 - kWhich leads to the FLRW constraint(a’/a)^2 = 8πGρ/3c^3 – k/a^2 a’ = da/dtWhere the Hubble parameter H = 70km/s-Mpc is (a’/a)^2 = H^2. This means that in a local region we have energy conservation FAPP. The difficulty is this is not a property of the symmetries of the system so we have no way to extend this globally.What this ultimately means is that all physics is local. It does not mean we have mass-energy locally vanishing. The apparent increase in the kinetic energy due to expansion is well enough compensated for by a decease in gravitational potential energy.This is the claim, but I haven't seen any proof of it. Do you have one? Take a planet. Can you show that Mc^2, where M is the planet's mass, is equal to its negative gravitational potential energy? AG
On Friday, May 8, 2020 at 4:50:55 PM UTC-6, Lawrence Crowell wrote:There is no global meaning to energy conservation. There is the Hamiltonian constraint Nℌ = 0, which just says that for a local region where the lapse function can be parallel translated to the energy is zero. This is for Petrov type O solutionsNℌ = 0 = ½(da/dt)^2 - 4πGρa^2/3c^3 - kWhich leads to the FLRW constraint(a’/a)^2 = 8πGρ/3c^3 – k/a^2 a’ = da/dtWhere the Hubble parameter H = 70km/s-Mpc is (a’/a)^2 = H^2. This means that in a local region we have energy conservation FAPP. The difficulty is this is not a property of the symmetries of the system so we have no way to extend this globally.What this ultimately means is that all physics is local. It does not mean we have mass-energy locally vanishing. The apparent increase in the kinetic energy due to expansion is well enough compensated for by a decease in gravitational potential energy.This is the claim, but I haven't seen any proof of it. Do you have one? Take a planet. Can you show that Mc^2, where M is the planet's mass, is equal to its negative gravitational potential energy? AG
There is nothing mysterious going on here. All this means is there is a limitation or horizon to our ability to know if there are global symmetries to the universe. As such there is no meaning to conservation principles.We can estimate the volume of the observable universe and its average mass-energy density. So it seems we can estimate its total energy. Does that energy remain constant or not as the universe expands? This seems like a reasonable question to ask. AG
On Friday, May 8, 2020 at 9:28:02 PM UTC-5, Alan Grayson wrote:
On Friday, May 8, 2020 at 4:50:55 PM UTC-6, Lawrence Crowell wrote:There is no global meaning to energy conservation. There is the Hamiltonian constraint Nℌ = 0, which just says that for a local region where the lapse function can be parallel translated to the energy is zero. This is for Petrov type O solutionsNℌ = 0 = ½(da/dt)^2 - 4πGρa^2/3c^3 - kWhich leads to the FLRW constraint(a’/a)^2 = 8πGρ/3c^3 – k/a^2 a’ = da/dtWhere the Hubble parameter H = 70km/s-Mpc is (a’/a)^2 = H^2. This means that in a local region we have energy conservation FAPP. The difficulty is this is not a property of the symmetries of the system so we have no way to extend this globally.What this ultimately means is that all physics is local. It does not mean we have mass-energy locally vanishing. The apparent increase in the kinetic energy due to expansion is well enough compensated for by a decease in gravitational potential energy.This is the claim, but I haven't seen any proof of it. Do you have one? Take a planet. Can you show that Mc^2, where M is the planet's mass, is equal to its negative gravitational potential energy? AGThe Hamiltonian constraint above and the FLRW equation are all you need. It is right there.
There is nothing mysterious going on here. All this means is there is a limitation or horizon to our ability to know if there are global symmetries to the universe.
On Saturday, May 9, 2020 at 4:58:20 AM UTC-6, Lawrence Crowell wrote:On Friday, May 8, 2020 at 9:28:02 PM UTC-5, Alan Grayson wrote:
On Friday, May 8, 2020 at 4:50:55 PM UTC-6, Lawrence Crowell wrote:There is no global meaning to energy conservation. There is the Hamiltonian constraint Nℌ = 0, which just says that for a local region where the lapse function can be parallel translated to the energy is zero. This is for Petrov type O solutionsNℌ = 0 = ½(da/dt)^2 - 4πGρa^2/3c^3 - kWhich leads to the FLRW constraint(a’/a)^2 = 8πGρ/3c^3 – k/a^2 a’ = da/dtWhere the Hubble parameter H = 70km/s-Mpc is (a’/a)^2 = H^2. This means that in a local region we have energy conservation FAPP. The difficulty is this is not a property of the symmetries of the system so we have no way to extend this globally.What this ultimately means is that all physics is local. It does not mean we have mass-energy locally vanishing. The apparent increase in the kinetic energy due to expansion is well enough compensated for by a decease in gravitational potential energy.This is the claim, but I haven't seen any proof of it. Do you have one? Take a planet. Can you show that Mc^2, where M is the planet's mass, is equal to its negative gravitational potential energy? AGThe Hamiltonian constraint above and the FLRW equation are all you need. It is right there.If it's so obvious, there'd be no dispute about this. But there definitely is! Bruce, e.g. Can you cite a paper where it's explicitly proven? TIA, AG
There is nothing mysterious going on here. All this means is there is a limitation or horizon to our ability to know if there are global symmetries to the universe.There are surely limitations on our observational abilities, but why is a symmetry necessary? Nature seems pretty asymmetric; e.g., imbalance of matter and anti-matter. AG
On Saturday, May 9, 2020 at 6:22:44 AM UTC-5, Alan Grayson wrote:
On Saturday, May 9, 2020 at 4:58:20 AM UTC-6, Lawrence Crowell wrote:On Friday, May 8, 2020 at 9:28:02 PM UTC-5, Alan Grayson wrote:
On Friday, May 8, 2020 at 4:50:55 PM UTC-6, Lawrence Crowell wrote:There is no global meaning to energy conservation. There is the Hamiltonian constraint Nℌ = 0, which just says that for a local region where the lapse function can be parallel translated to the energy is zero. This is for Petrov type O solutionsNℌ = 0 = ½(da/dt)^2 - 4πGρa^2/3c^3 - kWhich leads to the FLRW constraint(a’/a)^2 = 8πGρ/3c^3 – k/a^2 a’ = da/dtWhere the Hubble parameter H = 70km/s-Mpc is (a’/a)^2 = H^2. This means that in a local region we have energy conservation FAPP. The difficulty is this is not a property of the symmetries of the system so we have no way to extend this globally.What this ultimately means is that all physics is local. It does not mean we have mass-energy locally vanishing. The apparent increase in the kinetic energy due to expansion is well enough compensated for by a decease in gravitational potential energy.This is the claim, but I haven't seen any proof of it. Do you have one? Take a planet. Can you show that Mc^2, where M is the planet's mass, is equal to its negative gravitational potential energy? AG
The Hamiltonian constraint above and the FLRW equation are all you need. It is right there.If it's so obvious, there'd be no dispute about this. But there definitely is! Bruce, e.g. Can you cite a paper where it's explicitly proven? TIA, AGTolman computed some of this early on, His old book Relativity, Thermodynamics, and Cosmology. Oxford: Clarendon Press. 1934 is a source. There is nothing about physical cosmology that says we will witness some horrendous violation of energy conservation locally. It does tell us that since GR is a local principle, based on local translations of vectors etc, there is then no general symmetry rule for energy conservation.There is nothing mysterious going on here. All this means is there is a limitation or horizon to our ability to know if there are global symmetries to the universe.There are surely limitations on our observational abilities, but why is a symmetry necessary? Nature seems pretty asymmetric; e.g., imbalance of matter and anti-matter. AGThat has nothing in particular to do with this.
On Saturday, May 9, 2020 at 5:49:07 AM UTC-6, Lawrence Crowell wrote:On Saturday, May 9, 2020 at 6:22:44 AM UTC-5, Alan Grayson wrote:
On Saturday, May 9, 2020 at 4:58:20 AM UTC-6, Lawrence Crowell wrote:On Friday, May 8, 2020 at 9:28:02 PM UTC-5, Alan Grayson wrote:
On Friday, May 8, 2020 at 4:50:55 PM UTC-6, Lawrence Crowell wrote:There is no global meaning to energy conservation. There is the Hamiltonian constraint Nℌ = 0, which just says that for a local region where the lapse function can be parallel translated to the energy is zero. This is for Petrov type O solutionsNℌ = 0 = ½(da/dt)^2 - 4πGρa^2/3c^3 - kWhich leads to the FLRW constraint(a’/a)^2 = 8πGρ/3c^3 – k/a^2 a’ = da/dtWhere the Hubble parameter H = 70km/s-Mpc is (a’/a)^2 = H^2. This means that in a local region we have energy conservation FAPP. The difficulty is this is not a property of the symmetries of the system so we have no way to extend this globally.What this ultimately means is that all physics is local. It does not mean we have mass-energy locally vanishing. The apparent increase in the kinetic energy due to expansion is well enough compensated for by a decease in gravitational potential energy.This is the claim, but I haven't seen any proof of it. Do you have one? Take a planet. Can you show that Mc^2, where M is the planet's mass, is equal to its negative gravitational potential energy? AGSorry; I may have been confused about what you were claiming. I thought you claimed the total energy of the cosmos is zero, in which case the role of rest energy cannot be ignored. But apparently you just meant that kinetic energy and gravitational potential energy sum to zero, which is apriori plausible. AG
>> If you believe in what's called "evidence", and extrapolating from it to create a hypothetical physical theory, can you give a single example of something coming from nothing? AG> Two examples. The universe; Dark energy.