Help, question about upload image

[Weikang Meng]

Hello, I'm working on a Django project that need to upload images and there's limit on the image file size(like 5M). I need to compress the image if it is larger than the upper limit.

 And my problem is how can i return the compressed image data just like the format of file.read()?

Here's how I did: 

(1) get the image as a file object from the Django request.FILE

(2) get file_data, which is to return, from file.read(). and compare the length of data.

(3) Compress the image, using library Image, thumbnail function.

(4) Here comes my problem, How can return the compressed data with the format like file.read

import Image
def upload(request):
    """
         return: file_data  <-  file.read()
    """
    file = request.FILE['file'] #get the image as file object
    file_data = file.read()      #read the file
    file_size = len(file_data) #get the file size of the image
    if cmp(file_size, MAX_SIZE):
        im = Image.open(file)
        im.thumbnail((128, 128), Image.ANTIALIAS)
        file_data = ???? #Help how can i return the same format like file.read() which didn't come into the 'if' part.
    return file_data

        

[Collin Anderson]

That's more a of a pillow question than a django question, but something like this might work:

import tempfile

imagefile = tempfile.TemporaryFile()
im.save(imagefile)
return imagefile

[孟维康]

Thanks a lot for your help.
I got another way to do that with StringIO the same way as the tempfile. Could you tell me which is better? I'm not good at programing and working on it.
http://stackoverflow.com/questions/3723220/how-do-you-convert-a-pil-image-to-a-django-file

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