Using jquery ajax POST method with django

[Hossein Rashnoo]

I use this code to send a request:

function checkuser() {
    $.ajax({
        url: 'http://10.252.84.159/ajaxrecivelogin',
        //type: 'POST',
        data: "{'username': 'aa', 'password' : 'bb'}",
        context: this,
        dataType: 'json',
        success: function (data) {
            $("#resp").html("success");
        },
        error: function ()
        {
            $("#resp").html("error");
        }
    });
};

And its worked But when i add type:POST part it cause error.

I use this django code to response that request:

def ajaxrecivelogin(request):
        import json
        response_data = {}
        response_data['status'] = '1'
        return HttpResponse(json.dumps(response_data), content_type="application/json")

Is it about my django code?

[Erwin Sprengers]

Hello,

POST works fine for me,  I use the following django code :

at the end of the view :

return HttpResponse(simplejson.dumps(response_dict), mimetype='application/javascript')

and following ajax code :

       $.ajax({
          url: '/ajax/is_key_mm/',
          type: 'POST',
          async:   false,
          data: {node : node.id, slug : "{{article_slug}}"},
          success: function(Result) {
                 if (Result.substring(1,4)=="NOK") {
                        console.log("not key");
                        key_label = "----";
                 }
                }
          });

[Vijay Khemlani]

Maybe it's triggering the CSRF validation? What error message are you getting exactly from the server?

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[Hossein Rashnoo]

I correct my code and it's worked. Thank you guys for your help.

Ajax Code:

function checkuser() {
    var myObject = new Object();
    myObject.username = $('#username').val();
    myObject.password = $('#password').val();
    $.ajax({
        url: 'http://10.252.84.159/ajaxrecivelogin/',
        type: 'POST',
        data: JSON.stringify(myObject),

        context: this,
        dataType: 'json',
        success: function (data) {

            alert( data.status );
        },
        error: function ()
        {
            alert( "Error" );
        }
    });
};

Django Code:

def ajaxrecivelogin(request):
        import json
        import ast
        x = ast.literal_eval(request.body)
        response_data = {}
        response_data['status'] = username
        

return HttpResponse(json.dumps(response_data), content_type="application/json")

And i comment out django.middleware.csrf.CsrfViewMiddleware in setting

[carlos]

if you comment middleware csrf this is a risk security problem in your app

maybe you need read this part of documentation

https://docs.djangoproject.com/en/1.7/ref/contrib/csrf/#ajax

Cheers

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