Custom Primary Key

[Soumen Khatua]

Hi Folks,

In Django is there any way to create custom Primark Key like: M01234GH, M056YUOIP, etc.

Please help me guys.

Thank you in advance

Regards,

Soumen Khatua

[David Chorpash]

Hi Soumen,

Are you looking for this?

https://docs.djangoproject.com/en/3.0/ref/models/fields/#primary-key

You should be able to create a field in your model and set the primary_key to True

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[Soumen Khatua]

In the documentation they are specified, How to set Primary Key in Django model but In my case, I want to generate custom Primary Key?!

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[Oleg Kishenkov]

Hello Soumen, you should use a CharField with the primary_key=True attribute for your model. This way no no automatic primary key field is generated, your field will be implicitly unique and non-null though. Only one primary key is allowed in a model.

class Foo(models.Model)

    id = models.CharField(max_length=15, primary_key=True)

Regards,

Oleg

[Clive Bruton]

Just to clarify this, are you indicating that when you create the
record you generate a unique custom key yourself and insert this?


-- Clive

[Soumen Khatua]

Yes, at the time of add a new record in model, automatically I want to create a custom ID and insert it into model

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[Clive Bruton]

On 24 Jun 2020, at 06:24, Soumen Khatua wrote:

> Yes, at the time of add a new record in model, automatically I want
> to create a custom ID and insert it into model

There is a post about this at Stack Overflow:

https://stackoverflow.com/questions/52070462/django-generate-custom-id


-- Clive

[Oleg Kishenkov]

Yes, first you generate your custom key, second you specify it as the id of an object.

id = 'A1B2C3D4E5'

foo = Foo(id=id)

foo.save()

This code would create a record in the database. I also have to note that if you read this record to an object, changed it and saved it, the record wouldn't change, another record would be created with the new id

foo = Foo.objects.filter(id=id)[0]

foo.id = 'X1Y2Z3'

foo.save()

Foo.objects.all()

<QuerySet [<Foo: Foo object (A1B2C3D4E5)>, <Foo: Foo object (X1Y2Z3)>]>

Oleg

среда, 24 июня 2020 г. в 04:49:45 UTC+3, Clive Bruton: