Hi everone,
I started to code a two-apps django project. ModelA belongs to appone and ModelB belongs to apptwo. My purpose is to create a ModelA instance everytime that the user creates a ModelB instance. And the value of a ModelA CharField (that is ckeditor widgeted) must be the source code of a ModelB admin view. I used a post_data signal to link a function of creation for that. The problem is that i use the id of each instance of ModelB in order to create the good content for each instance of ModelA. When I try to use a string of the url sending the id parameter, the content field has for value the source code of the debug page
(error 500, DoesNotExist at /admin/apptwo/modelb/my_view/ref=76, [76 is an example] ModelB matching query does not exist. Exception location : /home/me/Desktop/env/lib/python3.5/site-packages/django/db/models/query.py in get, line 385)
But when I try to visit the url "http://localhost:8000//admin/apptwo/modelb/my_view/ref=76", or when I hardcode the url, without a str(instance.id), the page exists and everything works perfectly.
I don't understand why.
Could anybody give me some help to solve this problem ?
Thanks in advance,
PS :
The first app has a model.py that contains the following code :
from django.db import models
from django.contrib.auth.models import User
from registre.models import *
class ModelA(models.Model):
content = models.CharField(max_length=255, null=True)
def __str__(self):
return "ModelA : " + str(self.id)
the admin.py of this first app also contains :
from django.contrib import admin
from appone.models import *
from apptwo.models import ModelB
from django.http import HttpResponse
from django.template.response import TemplateResponse
from django.conf.urls import url
from registre import views
from django.db.models.signals import post_save
from django.dispatch import receiver
import datetime
from django.contrib.auth.models import User
from django import forms
from ckeditor.widgets import CKEditorWidget
from django.template.loader import render_to_string
import requests
class ModelAAdminForm(forms.ModelForm):
content = forms.CharField(widget=CKEditorWidget())
class Meta:
model = ModelA
fields = '__all__'
class ModelAAdmin(admin.ModelAdmin):
form = ModelAAdminForm
def create_A(sender, instance, **kwargs):
string = "http://localhost:8000/admin/apptwo/modelb/my_view/ref=" + str(instance.id)
r = requests.get(string)
ModelA.objects.create(contenu=r.text.encode('utf-8'))
post_save.connect(create_A, sender=ModelB)
admin.site.register(ModelA, ModelAAdmin)
the second app (apptwo) has a models.py like this :
from django.db import models
from django.contrib.auth.models import User
class ModelB(models.Model):
owner = models.ForeignKey(User, null=True)
name = models.CharField(max_length=255, null=True)
def __str__(self):
return self.name
and an admin.py that contains :
from django.contrib import admin
from appone.models import *
from apptwo.models import *
import datetime
from django.conf.urls import url, include
from django.template.response import TemplateResponse
class ModelBAdmin(admin.ModelAdmin):
def get_queryset(self, request):
qs = super(ModelB, self).get_queryset(request)
if request.user.is_superuser:
return qs
return qs.filter(owner=request.user)
def save_model(self, request, obj, form, change):
obj.owner = request.user
obj.save()
def get_urls(self):
urls = super(ModelBAdmin, self).get_urls()
my_urls = [
url(r'^my_view/ref=(?P<id>\d+)$', self.my_view),
]
return my_urls + urls
def my_view(self, request, id):
context = dict(
self.admin_site.each_context(request),
selector = ModelB.objects.get(id=id),
)
return TemplateResponse(request, "myview.html", context)
admin.site.register(ModelB, ModelBAdmin)
and finally a template myview.html with :
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