Django - Pass a model instance specified by template tags to the view

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Jack

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Nov 8, 2017, 9:37:36 PM11/8/17
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On my HTML page, I have a list of Agent's (Agent is my custom User model).  Beside each agent is a 'Send Invite' button.  To create a `TeamInvitation`, I need to specify which Agent is attached to its `receiver_agent` field (a OneToOneField with Agent)

There are multiple Agents displayed on the HTML page, and they are listed in order with template tags.  I need to input something after `pk` at `receiver_agent = Agent.objects.get(pk = ???)`, but I don't know what to input.

views.py

    class InviteAgentSearchResults(ListView):
        model = Agent
        form_class = AgentSearchForm
        template_name = 'invite_agent_search_results.html'
        
        def get_queryset(self):
            # ... Code to find correct list of agents
        
        def post(self, request, *args, **kwargs):
            invite = TeamInvitation.objects.create(receiver_agent = Agent.objects.get(pk = ???))
            return HttpResponse('Invite successfully sent.')

HTML:

    {% for agent in agent_list %}
    <div class="agent">
    # ... Some code here

            <form method="post">  # The "Send Invite" button
                {% csrf_token %}
                <button class="button1"><span>Send Invite</span></button>
            </form>
    </div>
    {% endfor %}

Adam Simon

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Nov 8, 2017, 11:24:29 PM11/8/17
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It seems to me that the quickest thing would be to make each agent a separate form. 

Alternatively, you could set up some JavaScript:

Add the agent.id to a hidden input,  separated by commas, and have that hidden field submitted via the form

Then on the backend separate out each ID and have the invites sent one by one. I would be happy to write some code if you wish.


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Adam F. Simon, PhD
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Jack

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Nov 9, 2017, 2:45:33 PM11/9/17
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There will be a lot of agents in the database, so would it violate the DRY principle if I were to write a form for each agent?  Plus it'll be super time consuming.

I'm going to try the hidden agent.id thing, I never thought about that.  I'll report back to see if I managed to get it working. 

Adam Simon

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Nov 9, 2017, 3:41:07 PM11/9/17
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Each form would be generated by a loop; still I would go with the hidden field. 

Look forward to seeing how it goes. 



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Jack

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Nov 9, 2017, 11:12:58 PM11/9/17
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Ok I'm very stuck.  Thought very hard about it but can't see how I can add a hidden field into the HTML, and relay the specified instance of the hidden field back to the views... or am I completely off about something?

Also in regards to the looped form's.  If you look at my original code, I actually do have a <form> representing a button for each agent.  The resulting page looks like this (excuse the bad CSS).  I'm not sure if that is what you meant by having a form for each agent.

So if I understood you correctly, I do have a separate <form> input for each displayed agent; looped with {% for agent in agent_list %}.  The question is, how do I relay the correct agent linked to its 'Send Invite' button back to the views?

Adam Simon

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Nov 9, 2017, 11:20:53 PM11/9/17
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Hi Jack. I will write some more details when I get home. Have you ever used Ajax?

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Jack Zhang

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Nov 9, 2017, 11:42:53 PM11/9/17
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No I am not familiar with Ajax.  I only know a bit of JavaScript.
ᐧ

On Thu, Nov 9, 2017 at 6:19 PM, Adam Simon <add.si...@gmail.com> wrote:

Hi Jack. I will write some more details when I get home. Have you ever used Ajax?
On Thu, Nov 9, 2017 at 3:14 PM Jack <valac...@gmail.com> wrote:
Ok I'm very stuck.  Thought very hard about it but can't see how I can add a hidden field into the HTML, and relay the specified instance of the hidden field back to the views... or am I completely off about something?

Also in regards to the looped form's.  If you look at my original code, I actually do have a <form> representing a button for each agent.  The resulting page looks like this (excuse the bad CSS).  I'm not sure if that is what you meant by having a form for each agent.

So if I understood you correctly, I do have a separate <form> input for each displayed agent; looped with {% for agent in agent_list %}.  The question is, how do I relay the correct agent linked to its 'Send Invite' button back to the views?

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Adam F. Simon, PhD
Calabasas, CA.

cell:      818-425-3719
home:   818-880-8405

Feel free to link w/ me: LinkedIn


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Jack Zhang

Adam Simon

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Nov 9, 2017, 11:50:36 PM11/9/17
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I would recommend taking a look at how Jquey does Ajax. It’s a lot simpler than Django forms. I will post some example code when I get home


On Thu, Nov 9, 2017 at 3:42 PM Jack Zhang <valac...@gmail.com> wrote:
No I am not familiar with Ajax.  I only know a bit of JavaScript.
ᐧ

On Thu, Nov 9, 2017 at 6:19 PM, Adam Simon <add.si...@gmail.com> wrote:

Hi Jack. I will write some more details when I get home. Have you ever used Ajax?
On Thu, Nov 9, 2017 at 3:14 PM Jack <valac...@gmail.com> wrote:
Ok I'm very stuck.  Thought very hard about it but can't see how I can add a hidden field into the HTML, and relay the specified instance of the hidden field back to the views... or am I completely off about something?

Also in regards to the looped form's.  If you look at my original code, I actually do have a <form> representing a button for each agent.  The resulting page looks like this (excuse the bad CSS).  I'm not sure if that is what you meant by having a form for each agent.

So if I understood you correctly, I do have a separate <form> input for each displayed agent; looped with {% for agent in agent_list %}.  The question is, how do I relay the correct agent linked to its 'Send Invite' button back to the views?

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Adam F. Simon, PhD
Calabasas, CA.

cell:      818-425-3719
home:   818-880-8405

Feel free to link w/ me: LinkedIn


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