Get the Parameter Value From URL

[Pravin Yadav]

Hello,

I want to get the parameter value from url in djago template. i'm using the django 2.0.6 and python 3.6.1.

base.html:-  

{{ request.GET.get('videorandom_id') }}

 

My url: http://127.0.0.1:8000/watch/videos/4626634807531689

Error Message:

TemplateSyntaxError at /watch/videos/4626634807531689

Could not parse the remainder: '('videorandom_id')' from 'request.GET.get('videorandom_id')'

Request Method: GET

Request URL: http://127.0.0.1:8000/watch/videos/4626634807531689

Django Version: 2.0.6

Exception Type: TemplateSyntaxError

Exception Value:

Could not parse the remainder: '('videorandom_id')' from 'request.GET.get('videorandom_id')'

Exception Location: /usr/local/lib/python3.6/site-packages/django/template/base.py in __init__, line 668

Python Executable: /usr/local/bin/python3

Python Version: 3.6.1

Python Path:

['/var/www/html/videowithfriends',

 '/usr/local/lib/python36.zip',

 '/usr/local/lib/python3.6',

 '/usr/local/lib/python3.6/lib-dynload',

 '/usr/local/lib/python3.6/site-packages']

Server time: Tue, 12 Jun 2018 12:46:13 +0000

[赖信桃]

Hi, Pravin

You don't need `get` method in template, just use dot, and if it doesn't exist, Django template engine will set it to None automatically.

Both below works:

```

{{ request.GET.foo }}

{% if request.GET.my_var %}

  {{ request.GET.my_var }}

{% endif %}

```

Check Django template language: https://docs.djangoproject.com/zh-hans/2.0/ref/templates/language/

Pravin Yadav <pk.j...@gmail.com>于2018年6月12日周二 下午8:49写道：

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