Django http request to api error

[chern...@gmail.com]

As this is the first time I'm trying this out, I do not know what is wrong with the problem. So it would be great if someone can help me solve this problem

The code I'm using is at the bottom page of this website: https://www.twilio.com/blog/2014/11/build-your-own-pokedex-with-django-mms-and-pokeapi.html

Where it give example on how you can make HTTP request function and retrieve database on your query.

The code on the website is this.

query.py

import requests
import json

BASE_URL = 'http://pokeapi.co'


def query_pokeapi(resource_url):
    url = '{0}{1}'.format(BASE_URL, resource_url)
    response = requests.get(url)

    if response.status_code == 200:
        return json.loads(response.text)
    return None


charizard = query_pokeapi('/api/v1/pokemon/charizard/')

sprite_uri = charizard['sprites'][0]['resource_uri']
description_uri = charizard['descriptions'][0]['resource_uri']

sprite = query_pokeapi(sprite_uri)
description = query_pokeapi(description_uri)

print
charizard['name']
print
description['description']
print
BASE_URL + sprite['image']

In my edit, I only change these print line at the bottom of this

query.py

print(charizard['name'])
print(description['description'])
print(BASE_URL + sprite['image'])

But i got this error instead

Traceback (most recent call last): File "query2.py", line 46, in sprite_uri = charizard['sprites'][0]['resource_uri'] TypeError: 'NoneType' object is not subscriptable

[Matemática A3K]

On Wed, Jan 17, 2018 at 1:42 AM, <chern...@gmail.com> wrote:

As this is the first time I'm trying this out, I do not know what is wrong with the problem. So it would be great if someone can help me solve this problem

The code I'm using is at the bottom page of this website: https://www.twilio.com/blog/2014/11/build-your-own-pokedex-with-django-mms-and-pokeapi.html

Where it give example on how you can make HTTP request function and retrieve database on your query.

The code on the website is this.

query.py

import requests
import json

BASE_URL = 'http://pokeapi.co'


def query_pokeapi(resource_url):
    url = '{0}{1}'.format(BASE_URL, resource_url)
    response = requests.get(url)

    if response.status_code == 200:
        return json.loads(response.text)
    return None

If there is not a 200 response it returns None

charizard = query_pokeapi('/api/v1/pokemon/charizard/')

It's because charizard is None

sprite_uri = charizard['sprites'][0]['resource_uri']

that can't do None['sprites']...

description_uri = charizard['descriptions'][0]['resource_uri']

sprite = query_pokeapi(sprite_uri)
description = query_pokeapi(description_uri)

print
charizard['name']
print
description['description']
print
BASE_URL + sprite['image']

In my edit, I only change these print line at the bottom of this

query.py

print(charizard['name'])
print(description['description'])
print(BASE_URL + sprite['image'])

But i got this error instead

Traceback (most recent call last): File "query2.py", line 46, in sprite_uri = charizard['sprites'][0]['resource_uri'] TypeError: 'NoneType' object is not subscriptable

And that's why the error

 

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[chern...@gmail.com]

May i know what does this means:

def query_pokeapi(resource_url):
    url = '{0}{1}'.format(BASE_URL, resource_url)
    response = requests.get(url)

the '{0}{1}' and resource_url

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[Andréas Kühne]

Hi,

That's called string interpolation. Check here:

https://stackoverflow.com/questions/11788472/does-python-has-a-similar-variable-interpolation-like-string-var-in-ruby

Not the best explanation, but should get you going.

Regards,

Andréas

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