Custom Admin Form for listing all url

[Vanni Brutto]

hi,

i want to make a custom form in admin.py for modify the form of a model that should show a combobox with all urlpattern name defined in urls.py.

I tryed with this code (i'm a python/django newbie, sorry ;)):

def fasullo():

    pass

class NameURLForm(forms.ModelForm):

    class Meta:

        model = NameURL

        fields = ['nameStart', 'nameEnd']

    def clean_date(self):

        pass

    def __init__(self, *args, **kwargs):

        super(NameURLForm, self).__init__(*args, **kwargs)

        listURL = []

        for name, L in get_resolver(None).reverse_dict.items():

            if type(name) != type(fasullo):

                if name != None and name != "":

                    listURL.append(name)

        self.fields['nameStart'] = forms.ChoiceField(choices=listURL)

        self.fields['nameEnd'] = forms.CharField(label="nameEnd", max_length=80,required=True,

                                                 widget=forms.Select(choices=[(i,listURL[i]) for i in range(len(listURL))]))

any hint?

[Vanni Brutto]

solved! Here the code:

class NameURLForm(forms.ModelForm):

    class Meta:

        model = NameURL

    def __init__(self, *args, **kwargs):

        super(NameURLForm, self).__init__(*args, **kwargs)

        listURL = []

        for name, L in get_resolver(None).reverse_dict.items():

            if type(name) is not FunctionType:

                listURL.append((name, name))

        listURL.sort()

        self.fields['nameStart'] = forms.ChoiceField(choices=listURL,label=_("URL di partenza"))

        self.fields['nameEnd'] = forms.ChoiceField(choices=listURL,label=_("URL di arrivo"))