Greetings,
trying to create new app with simple Form to create and update Company info. My view looks like:
def company_new(request):
if request.method == "POST":
form = CompanyForm(request.POST)
if form.is_valid():
company = form.save(commit=False)
company.save()
return redirect('views.company_detail', pk=company.pk)
else:
form = CompanyForm()
return render(request, 'crm/company_edit.html', {'form': form})
with urls.py:
app_name = 'crm'
urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^index_previous', views.index_previous, name='index_previous'),
url(r'^report_money', views.report_money, name='report_money'),
url(r'^report_works', views.report_works, name='report_works'),
url(r'^company/(?P<pk>[0-9]+)/$', views.company_detail, name='company_detail'),
url(r'^work/(?P<pk>[0-9]+)/$', views.work_detail, name='work_detail'),
url(r'^company/new/$', views.company_new, name='company_new'),
url(r'^company/edit/(?P<pk>[0-9]+)/$', views.company_edit, name='company_edit'),
] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
But when i save my new company, i get info:
So Django takes whole URL + my redirect. Is it possible to force to use my urls.py? I found something like "return HttpResponseRedirect('/')", but it's strange solution. Another way is to point to exact path, but i don't like too, i'd like to use urls.py to redirect.
Thanks for tips, i hope it's some simple trick or import i'm missing.