save cropped image with PIL to database

[shahab emami]

hello

i have a question and i cant find answer with search.

i want to save cropped image in database then :

this is my model:

class Photo(models.Model):
    file        = models.ImageField(upload_to='%Y/%m/%d', blank=True,null=True)

i have a form then user can select image and send to view like this:

<form method="post" enctype="multipart/form-data" " >
    {% csrf_token %}

  <input type="file"  id="photo_id" name="file">

    <input type="submit" value=" send image" />

  </form>

and in the view i have this :

from PIL import Image


def save_photo(request):

    _photo, created = models.Photo.objects.get_or_create(pk=1)

    if request.method == 'POST':
        photo = request.FILES.get('file')

        image = Image.open(photo)

        cropped_image = image.crop((100, 100, 200, 200))
        resized_image = cropped_image.resize((200, 200), Image.ANTIALIAS)
        _photo.file = resized_image
        _photo.save()


        return HttpResponse("your image has been saved")

but i get this error:

'Image' object has no attribute '_committed'

i'm sure my mistake is in views.py but i dont now how to fix it. how can put resized_image that is an object of Image class to 

a model.

can you help me please?

[Andréas Kühne]

I would have a look at the easy-thumbnails plugin (http://easy-thumbnails.readthedocs.io/en/2.1/). It uses pillow behind the scenes and it is very easy to do the cropping and everything that you need and you don't need to write it yourself :-)

Regards,

Andréas

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[shahab emami]

but i want to do it myself.

when i write code i can improve it as much as i can. 

can anybody please tell me about my mistake please

Regards,

Andréas

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[Andréas Kühne]

Sorry - can't help you there. I prefer using pip packages than writing my own code - where possible. :-)

Regards,

Andréas

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[Melvyn Sopacua]

On Monday 03 July 2017 03:09:56 shahab emami wrote:

> hello

>

> i have a question and i cant find answer with search.

 

Really?

https://duckduckgo.com/?q=django+resize+image&t=ffsb&ia=software

 

--

Melvyn Sopacua

[Tom Evans]

On Mon, Jul 3, 2017 at 11:09 AM, shahab emami <royar...@gmail.com> wrote:
> hello
>
> i have a question and i cant find answer with search.
>
> i want to save cropped image in database then :
> this is my model:
>
> class Photo(models.Model):
> file = models.ImageField(upload_to='%Y/%m/%d',
> blank=True,null=True)
>
>
> i have a form then user can select image and send to view like this:
>
> <form method="post" enctype="multipart/form-data" " >
> {% csrf_token %}
>
> <input type="file" id="photo_id" name="file">
>
> <input type="submit" value=" send image" />
>
> </form>
>
>
> and in the view i have this :
>
> from PIL import Image
>
>
> def save_photo(request):
>
> _photo, created = models.Photo.objects.get_or_create(pk=1)
>
> if request.method == 'POST':
> photo = request.FILES.get('file')

This is a django.core.files.File (or subclass) object. It is file-like
and can be treated as a file.

>
> image = Image.open(photo)
>
> cropped_image = image.crop((100, 100, 200, 200))
> resized_image = cropped_image.resize((200, 200), Image.ANTIALIAS)

resized_image is a pil.Image. Again, it is file-like, but it is not a
django.core.files.File...

> _photo.file = resized_image
> _photo.save()

so this doesn't work. You will need to wrap the PIL.Image file-like
object with the django File class (remember appropriate imports):

_photo.file = File(resized_image)
_photo.save()


Cheers

Tom