Mydb.objects.all()[:1]
Mydb.objects.all()[1:]
You can try Mydb.objects.last()
You can also try reversing the order and using first: Mydb.objects.order_by(‘-pk’).first()
And for some terminology clarification, a database consists of tables. In Django, a model maps to a table, not a database. A table has fields; a database has tables but not fields.
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You can try Mydb.objects.last()
You can also try reversing the order and using first: Mydb.objects.order_by(‘-pk’).first()
And for some terminology clarification, a database consists of tables. In Django, a model maps to a table, not a database. A table has fields; a database has tables but not fields.
From: django...@googlegroups.com [mailto:django...@googlegroups.com] On Behalf Of Stéphane Manguette
Sent: Wednesday, January 30, 2019 4:02 PM
To: Django users
Subject: Get very last object of database
Hello guys,
My issue is pretty simple. I want to get the very last record of my database (which is populated with thousands of entries)
So far ->very easy. But I want to make sure that the access to the database is as light as possible. Don't want django to parse everything in my database.
Kindly note that my DB has Primary key field.
I tried
Mydb.objects.all()[:1]
Mydb.objects.all()[1:]
but both return the first filed instead of the last one.
Thanks for your help
Stephane
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Hello
I have a field in my model which has unique = True.
If I specify an error message with a reference to the value of the field, Django crashes with Key error.
Yet this works for other error_messages. How wan I solve this?
Here is the code and the trace back
Is this a bug in admin?
I thank you in advance for your help.
Piscvau