Error arises again and again\

[niranjan shukla]

I am using the Django 1.11 but I always encounter the same error. if you know anything to this then tell me, brother,

from common.decorators import ajax_required

      ModuleNotFoundError: No module named 'common

[胡超]

Maybe you need pip the pack;

在 2019年8月1日，下午3:39，niranjan shukla <niranjan...@gmail.com> 写道：

ModuleNotFoundError

[niranjan shukla]

pip install django-common

or 

pip install common

[胡超]

Y

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[niranjan shukla]

AFTER INSTALLING THE DJANGO-COMMON AND I AM USING PYTHON 3.6

 

from common.decorators import ajax_required

  File "C:\Users\user\AppData\Local\Programs\Python\Python36\lib\site-packages\common\decorators.py", line 61

    except Exception, ex:

                    ^

SyntaxError: invalid syntax

[胡超]

You can uninstall Django-common and install common. Try it.

在 2019年8月1日，下午3:49，niranjan shukla <niranjan...@gmail.com> 写道：

Python

[niranjan shukla]

views.py

from django.http import JsonResponse

from django.views.decorators.http import require_POST

from common.decorators import ajax_required

from .models import Contact

@ajax_required

@require_POST

@login_required

def user_follow(request):

    user_id = request.POST.get('id')

    action = request.POST.get('action')

    if user_id and action:

        try:

            user = User.objects.get(id=user_id)

            if action == 'follow':

                Contact.objects.get_or_create(

                    user_from=request.user,

                    user_to=user)

            else:

                Contact.objects.filter(user_from=request.user,

                                       user_to=user).delete()

            return JsonResponse({'status':'ok'})

        except User.DoesNotExist:

            return JsonResponse({'status':'ko'})

    return JsonResponse({'status':'ko'})

when I install the common then 

ERROR: 

File "C:\Users\user\Desktop\allauth1 - Copy\users\views.py", line 133, in <module>

    from common.decorators import ajax_required

ModuleNotFoundError: No module named 'common.decorators'

 

[胡超]

When you install Django-common , exam the function ajax_required  . Try to  fond error.

Im sorry for my bad English.

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[niranjan shukla]

# -*- coding: utf-8 -*-

"""

Contains view's decorators which automates common tasks.

"""

import traceback

from django.shortcuts import render_to_response

from django.template import RequestContext

from common.http import HttpResponseJson

def render_to(template):

    """

    Render view's output with ``template`` using ``RequestContext``.

    If decorated view returns dict object then wrap it in RequestContext and

    render the template.

    If decorated view returns non dict object then just return this object.

    Args:

        :template: path to template

    

    Example::

        @render_to('blog/index.html')

        def post_list(request):

            posts = Post.objects.all()

            return {'posts': posts,

                    }

    """

    def decorator(func):

        def wrapper(request, *args, **kwargs):

            output = func(request, *args, **kwargs)

            if not isinstance(output, dict):

                return output

            else:

                ctx = RequestContext(request)

                return render_to_response(template, output, context_instance=ctx)

        return wrapper

    return decorator

def ajax(func):

    """

    Convert views's output into JSON.

    Decorated view should return dict object.

    If ``request.method`` is not ``POST`` then deny the request.

    If view raises Exception then return JSON message with error description.

    """

    def wrapper(request, *args, **kwargs):

        if request.method == 'POST':

            try:

                response = func(request, *args, **kwargs)

            except Exception, ex:

                response = {'error': traceback.format_exc()}

        else:

            response = {'error': {'type': 403, 'message': 'Accepts only POST request'}}

        if isinstance(response, dict):

            return HttpResponseJson(response)

        else:

            return response

    return wrapper

def ajax_get(func):

    """

    Convert views's output into JSON.

    Decorated view should return dict object.

    If view raises Exception then return JSON message with error description.

    """

    def wrapper(request, *args, **kwargs):

        try:

            response = func(request, *args, **kwargs)

        except Exception, ex:

            response = {'error': traceback.format_exc()}

        if isinstance(response, dict):

            return HttpResponseJson(response)

        else:

            return response

    return wrapper

def disable_cache(func):

    def decorated(*args, **kwargs):

        resp = func(*args, **kwargs)

        resp['Pragma'] = 'no-cache'

        resp['Expires'] = '0'

        resp['Cache-Control'] = 'no-cache, no-store, must-revalidate'

        return resp

    return decorated

 

Error is 

[胡超]

The answer is change for  python2.7 & python3.6 .

This pack is worked  in python2.7 

Could you try fond the pack worked in python3.6

[Lim Kai Wey]

如果有需要, 我能帮忙翻译，看你俩聊好像有点痛苦。

Translation:

I can help translate if you guys want... I don’t mind translating 

Regards,

Kai Wey

[胡超]

好人啊

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[胡超]

多谢了。兄弟 ，请翻译 ：

问题是由于python2.7 和python3.6 之间的版本差异导致的。

这位小兄弟在使用python3.6 的版本。加载一个python2.7 版本的包。django-common。 需要寻找这个包的python3.6 版本， 如果没有这个版本的话 就需要寻找其他的解决方案。

在 2019年8月1日，下午4:56，Lim Kai Wey <limk...@gmail.com> 写道：

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[Lim Kai Wey]

哈哈哈 我真不介意，大家都来这学习嘛。互相帮忙是应该的。

Translation:

I really don’t mind translating, this is where we all learn. It’s a must to help each other out.

Ps. The three letters he said translate that I’m a nice person 

Regards,

Kai Wey

[niranjan shukla]

Yes translate and share with us please and how I can talk with you if I got another error

[Lim Kai Wey]

请翻译 ：

问题是由于python2.7 和python3.6 之间的版本差异导致的。

这位小兄弟在使用python3.6 的版本。加载一个python2.7 版本的包。django-common。 需要寻找这个包的python3.6 版本， 如果没有这个版本的话 就需要寻找其他的解决方案。

Translates:

The problem is due to the difference between the Python version 2.7 and 3.6. Because you’re using Python 3.6, you’ll have to have another Python 2.7’s package.  The Django-Common package will search for its package that is in Python 3.6, if there aren’t any package in this version then you’ll have to look for another solution.

Regards,

Kai Wey

[niranjan shukla]

I want to build the follow system in my website how i can do that

    beacuse i am using that ajax so that i can building follow system

and i am learning from https://learning.oreilly.com/library/view/django-2-by/9781788472487/d61f6f4a-a9f1-4f9f-b0eb-18ae1518a2dd.xhtml

 

[Lim Kai Wey]

翻译：

他说，他需要用那系统来设计他网站。他都是靠Ajax 设计那网站的。他都在这学的 

https://learning.oreilly.com/library/view/django-2-by/9781788472487/d61f6f4a-a9f1-4f9f-b0eb-18ae1518a2dd.xhtml

Ps. I just wanna say please use propose grammar so I can translate more accurately. Thanks

Regards,

Kai Wey

[Lim Kai Wey]

他还有问要怎么弄才行。

[胡超]

多谢了 兄弟：

我找了一篇帖子 主要讲如何在django 中使用ajax 来实现前端和后端的通信。

可以参考一下这篇帖子

https://blog.csdn.net/IqqIqqIqqIqq/article/details/52160662

当然这篇帖子中有一部分内容是中文。但是代码逻辑是相同的。

帮我翻译。幸苦了兄弟。

在 2019年8月1日，下午5:31，Lim Kai Wey <limk...@gmail.com> 写道：

他还有问要怎么弄才行。

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[Lim Kai Wey]

我找了一篇帖子 主要讲如何在django 中使用ajax 来实现前端和后端的通信。

可以参考一下这篇帖子

https://blog.csdn.net/IqqIqqIqqIqq/article/details/52160662

当然这篇帖子中有一部分内容是中文。但是代码逻辑是相同的。

Translate:

I found an article, that mainly teaches the backend and frontend between Django and Ajax. Although the article is in mandarin, but the logic of the code is there and same. You can view it as a reference.

[niranjan shukla]

I want to build user following system in Django for my social site

I want to build user following system in Django for my social site 

[Lim Kai Wey]

他说，他要在他社交网站弄个 用户关注