static templatetag: adding default argument blank

[Mohammad Etemaddar]

in the conversion of HTML template to Django template, sometimes it is hard to find&remplce static paths.
In current Django template we should change for example this:

<link rel="stylesheet" href="css/w3.css">

to

<link rel="stylesheet" href="{% static 'css/w3.css' %}">

as you see we add two parts to the href:

<link rel="stylesheet" href="{% static 'css/w3.css' %}">

We can also do in this order:

(2) <link rel="stylesheet" href="{% static '' %}css/w3.css">

In this way, we need to do only one find/replace. But in the previous way, we should first do find/replace on beginning and then add "%}" to the end. Maybe with some find/replace on every suffix (jpg,jpeg,css,js,png...)
But in way (2) We need only one find/replace if we have one asset directory in template.
In this way, We can give the static function default value blank in order to put just {% static %}.

[Adam Johnson]

I would be against adding this. Most text editors support a find-and-replace with regex option that would let you capture the asset path and place it within the {% static '' %} tag; additionally, you could always change your templates to include STATIC_URL globally and just do {{ STATIC_URL }} if you wanted to avoid using the static tag with the path to the asset.

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Adam

[Mohammad Etemaddar]

You are right. This is a better option, {{ STATIC_URL }}.

Mohammad Etemaddar
 
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