It needs to be an open interval. That's because to define the definition of a
function f(x) at some point x, you need that
f'(x0) = lim_{x->x0} (f(x)-f(x0))/(x-x0)
is well defined. That requires that f(x) is defined both to the left and to
the right of x0, and that can only be the case if x0 is an interior point of
an interval. So the derivative is *always* only well defined for interior
points, and it should have been the open interval (0,T) in the same way as we
always define Omega to be an open set.
Best
W.
--
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Wolfgang Bangerth email:
bang...@colostate.edu
www:
http://www.math.colostate.edu/~bangerth/