Dear Johanna,
What you describe here makes sense. Such a transformation is
described at
this link (see section 2.7 "Converting tensors between
Cartesian and Spherical-Polar bases". I think that the
circumferential stress would then be S_{\theta \theta}, according
to their notation). Its just that (in general) your rotation
matrix would have to change for each evaluation point, as the
radius and angle with respect to the axis would change.
We have a couple of functions already implemented that might help you to achieve this:
I hope that this helps you.
Best,
Jean-Paul
--
The deal.II project is located at http://www.dealii.org/
For mailing list/forum options, see https://groups.google.com/d/forum/dealii?hl=en
---
You received this message because you are subscribed to the Google Groups "deal.II User Group" group.
To unsubscribe from this group and stop receiving emails from it, send an email to dealii+un...@googlegroups.com.
To view this discussion on the web visit https://groups.google.com/d/msgid/dealii/57d95553-e531-4030-b9b8-266fc394da96n%40googlegroups.com.