Wrapping a `const void *` with the buffer interface without copying

[Craig de Stigter]

Hi folks

I'm trying to wrap a git blob class with a simple readonly buffer. The buffer should wrap the blob contents, which is exposed as a `const void*`, preferably without copying it. The latter is hard because it seems like the `buf` member of the PyBuffer struct is declared as a `void*`, so it can't accept values which are declared const.

My attempt looks like this so far:

>

> cdef class Blob:

> cdef unique_ptr[cppgit2_blob] thisptr

>

> def __getbuffer__(self, Py_buffer *buffer, int flags):

>

> # const void *blob::raw_contents()

> contents = <char*>deref(self.thisptr).raw_contents()

> size = deref(self.thisptr).raw_size()

>

> buffer.buf = contents

> buffer.format = 'c'

> buffer.internal = NULL

> buffer.itemsize = 1

> buffer.len = size;

> buffer.ndim = 1

> buffer.obj = self

> buffer.readonly = 1

> buffer.shape = [size]

> buffer.strides = [1]

> buffer.suboffsets = NULL

>

> def __releasebuffer__(self, Py_buffer *buffer):

> pass

And results in this compile error:

libkart.cpp:6252:47: error: assigning to 'void *' from 'const void *' discards qualifiers
  __pyx_v_contents = (*__pyx_v_self->thisptr).raw_contents();
                     ~~~~~~~~~~~~~~~~~~~~~~~~~^~~~~~~~~~~~~~

Is there any way to avoid this? Or perhaps is there a better way to achieve this, e.g. is it possible to achieve this using the Typed Memoryviews somehow?

Thanks

Craig

[da-woods]

I'm a bit puzzled because the cast to <char*> should do it (and does when I check myself with a simplified example) but for some reason it doesn't appear in the generated code  "__pyx_v_contents = (*__pyx_v_self->thisptr).raw_contents();". I'd expect to see
"__pyx_v_contents = (char*)(*__pyx_v_self->thisptr).raw_contents();"

I'd make sure that you're definitely compiling the code that you think you are (because I think it's right)

--

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